Eigen values or Characterstic roots of a matrix

Eigen values or Characterstic roots of a matrix with examples

[@manushaparisapogu4667]

I was really suffering to reduce the quadriceps equation . Your explanation made me to understand . With my whole heart I want to say thank you

[@TechlearnersbyNeerajSaxena]

Welcome

[@yuma2528]

FINALLY.
All the videos I've seen till now seem to skip the part where they actually have to find the EIGEN values!

[@TechlearnersbyNeerajSaxena]

Thank you

[@secure-7]

Thank you Sir it saved my time...

[@TechlearnersbyNeerajSaxena]

Welcome

[@himmup4821]

Hm yr

[@akibaziez8624]

ohh man. Thank you very much. you deserve more appreciation

[@TechlearnersbyNeerajSaxena]

Thanq

[@sasankkota9228]

Thank you very much sir tomorrow my exam got easier

[@TechlearnersbyNeerajSaxena]

Welcome

[@dr.strangelove467]

You mean yesterday

[@abbasit8278]

Amazing Sir.... Amazing... Your way of teaching is amazing and to the point. thumbs up

[@user-fy2tm8nw9z]

You are legend 🙌
You know how students should understand the concept

[@bgmiexpress2670]

Sir ।। Finally I understand nobody explained like you thankyou so much।। Sir

[@kennethkngoma1262]

The best video on Matrices so far. thank you so much. You saved me. I have an assignment to submit in 2 days time, but was hell for a month

[@TechlearnersbyNeerajSaxena]

Glad it helped!

[@shwetakumari2055]

Boht Acha samjhaya sir AK hi baar m samajh aa gaya

[@TechlearnersbyNeerajSaxena]

Thanq

[@physicsbaba7134]

What's a teaching technique love you sir from Pakistan
You are one of the best physics teacher in the world 🌎

[@TechlearnersbyNeerajSaxena]

Thanq

[@shiningsabee_]

Thank you so much for making this easier for us.

[@kabatbabu7148]

Thank you very much sir , myself Biuti, ,,

[@ankeshmahaur]

Thank you so much very nice explanation ☺️☺️

[@Pavitar-mc6fj]

Sirr can we use row opretions or column operations before find characteristic roots

[@chinthaguntlavijayaraju9110]

sir excellent explanation about eigen values and find out root or values from an equation in easy way, thanks for your valuble information to the students. thank you sir

[@TechlearnersbyNeerajSaxena]

Most welcome

[@hinazareen5729]

Very informative excellent work 👌 thanks alot

[@TechlearnersbyNeerajSaxena]

Welcome

[@Yaara2004]

Sir u r the most coolest person in maths I've ever seen..mthank u so much..jitna thnks kre utna kum hai

[@TechlearnersbyNeerajSaxena]

So nice of you

[@NeerajSingh_20]

Absolute Life saver❤

[@jakiyaimam3975]

Itni video me samajh nahi aaya aur is ek video me samajh aa gaya

[@manushaparisapogu4667]

Thank you so much sir. You really helped me a lot.

[@TechlearnersbyNeerajSaxena]

Welcome

[@Aldahr708]

Thank you so much sir...i was searching this since 1 hour..

[@TechlearnersbyNeerajSaxena]

You are most welcome

[@aryapatel6504]

Thanku sir, it was very helpful method

[@Zigbee1014]

3:50 min ka dekho sir

[@beyalgaming302]

Nice sir where were you till now . You are a life saver

[@TechlearnersbyNeerajSaxena]

Thanq for appreciation

[@anushas3611]

Thank you so much sir this method is easier for me

[@shreerama5176]

Wow easy explanation❤

[@lifeiseasy173]

Thank you so much sir I can't explain .....how much your video is helpful for me ..... after few days my internal exams are start nd I can't solve this polynomial type questions thank you so much nd I you read this cmt I request you that you make more videos in this concept

[@TechlearnersbyNeerajSaxena]

Most welcome

[@user-md8xb4qm5v]

Tq sir sach m samajh ni ara tha ki Bina calculator ke kese solve kare eigen vector tq sir apne bhot help Kari 🥺🙏

[@hhhorrorgmng4033]

Wow sir, amazing method of teaching..

[@TechlearnersbyNeerajSaxena]

Thanq so much

[@Zigbee1014]

Sir ek bar polynomial nikal ligey

[@rahulkarapadagroup]

Thanks you sir for explanation for trick I am real great full so thank you

[@TechlearnersbyNeerajSaxena]

Most welcome

[@vikashsinghrajawat8048]

Your are great teacher😊 thanku sir

[@suryanshsinha5032]

Sir aapne y mehtod bata die sbse ache se 🛐

[@archan_pandya]

Great Explanation thank you very much sir 😄

[@TechlearnersbyNeerajSaxena]

Thanq for appreciation

[@meetkorat7061]

What A Explanation Thank You Sir :)

[@TechlearnersbyNeerajSaxena]

Most welcome!

[@khahamdebbarma2583]

Such a detailed elaboration
Thankyou!

[@TechlearnersbyNeerajSaxena]

You're very welcome!

[@shahinurrahman5087]

Thanks a lot sir,, your process is very easy & good,so, thank you so much

[@TechlearnersbyNeerajSaxena]

Welcome

[@abhishekrawat4564]

Sir, your product of eigen values is 32 but determinant is 36 ? can you explain again please......

[@TharunReso2023]

TQ so much sir ❤❤ Ur the best

[@Chysrh]

Oh man what a class.

[@chennakesava1745]

you are the better then telugu lecturers

[@TechlearnersbyNeerajSaxena]

Thanq so much

[@neharamgarhia1529]

Thank you sir your video helps me alot 🙏🙏

[@TechlearnersbyNeerajSaxena]

Most welcome

[@Zigbee1014]

Sir ek bar hamko v polynomial solve kar k bhaj degey sir please

[@funwithshorts3897]

S sir you are Wong

[@riyarai2892]

Sahi bhai ham n confusion m hai

[@engineering789]

sir please explain the calculation of getting polynomial from determinant of A because i have attempted many times but i am getting little bit difference. waiting for your kind response sir

[@vikram.armwrestler]

36 is coming?

[@narendrapratapsingh4826]

Sir please how to get characteristic vector of this matrix for (lemda=2) of this matrix. Because when I solve it in last I get an equation which has three unknown how I solve it

[@surjeetkumar3620]

Thnaku very much sir, for sharing this

[@twinkleb1396]

Sir I attempted solving the matrix equation but I obtained a slightly different result as compared to yours. Could you pls show how you got this characterstic matrix?

[@huzaifaali1316]

same

[@sssgaming3019]

Awesome 😎.... thank you sir ❤️❤️❤️❤️

[@TechlearnersbyNeerajSaxena]

Welcome

[@PravinKumar-pg8zv]

You are great sir your explanation is very nice.

[@TechlearnersbyNeerajSaxena]

Thank you

[@gyanaranjannayak100]

Tq so much sir .😊

[@deepakkumarnayak722]

This is very helpful video thank you so much

[@TechlearnersbyNeerajSaxena]

Welcome

[@kabatbabu7148]

Thank you sir

[@nCoder4377]

Thanks a lots sirr

[@engineering789]

instead of 36lambda -32 i am getting 38 lambda -36

[@funwithshorts3897]

Sir please reply

[@HunnyBunny-dl7jj]

Thank you so much sir

[@Inspiredones833]

Thank you sir🙏

[@markguan7194]

Very helpful. Thank you

[@TechlearnersbyNeerajSaxena]

Most welcome

[@abhinavkumarlovanshi2912]

Thank you sir😊

[@techinalboy279]

Sir agar waha pe zero ni aya to pherse usko kaise kare

[@SherazMirrani]

Excellent

[@CHILL_BRO11]

Sir but for this sum eigen vector is not possible for ¥=2 I'm i correct sir👍🏻👍🏻

[@neetikadubey8534]

Thnku so much sir 🙏

[@kanishkaverma3905]

Thnku so much sir this vdo helps me a lot to find the characteristics roots thnku once again sir ❤️☺️🤌

[@TechlearnersbyNeerajSaxena]

Welcome.. You can more concepts from the channel.. All the best

[@RameshRamesh-zo1vl]

Lots of love sir ❤️❤️❤️❤️❤️

[@TechlearnersbyNeerajSaxena]

Thank you so much for your love

[@vardhanmordharia4143]

the magic that happened after 3:40 is the thing we students want to learn sir don't skip that

[@offlinear]

😂

[@jaatjaatt2643]

Mene to video hi es ke leye dekhe thi and sir skip that

[@muskantirole4]

😂

[@gurukiran6265]

Thank u man

[@anitakashyap2328]

This I am finding for
Thanx of lot sir

[@TechlearnersbyNeerajSaxena]

Most welcome

[@suryanshsinha5032]

Sir u r god 🛐🛐

[@TechlearnersbyNeerajSaxena]

I am not god just a teacher.. Thank you for appreciation

[@eneshkaneshk380]

Sir if frst characteristic value is 1,then how we will find nxt two characteristic roots?

[@TechlearnersbyNeerajSaxena]

In the same way i habe explained in video...

[@funwithshorts3897]

To Abhishek Yadav

[@Zigbee1014]

Please sir

[@Yaara2004]

Sir do we need to multiply the first coefficient with 0 always

[@TechlearnersbyNeerajSaxena]

Not always

[@garimakumari6121]

Thnq so much 👏👏

[@TechlearnersbyNeerajSaxena]

Welcome

[@patelshivam1606]

thank you, sir

[@Code_Breakers_]

GOOD EXPLANATION SIR
LOVE IT

[@TechlearnersbyNeerajSaxena]

Thanks for liking

[@parthshuklashayar7967]

Sir ye method lemda ki value find ke liye exam me kar skte h

[@TechlearnersbyNeerajSaxena]

Yes definitely

[@sanaiko3461]

Excellent work sir

[@TechlearnersbyNeerajSaxena]

Thanq

[@ZeeshaFatima-mq8sd]

Thankyou Soo much 🙂🤌

[@mrx_3268]

Char. equation is __--
(-X^3 + 12X^2 -38X + 36 = 0)
(let,X is lemda)
Mera 1 hour gaya or kisika na jaya is liya lik deya😉

[@TechlearnersbyNeerajSaxena]

Thanq so much for this

[@shivamya9579]

Right yrr.... I think video me wrong characteristic equation he

[@sainani3926]

Awsome sir tqq

[@TechlearnersbyNeerajSaxena]

Thanq

[@anandofficial1235]

Very very thank you sir ji ❤️❤️

[@TechlearnersbyNeerajSaxena]

Welcome

[@raousmankhan6812]

Love you sir 💖

[@eepShubhamKumarbhojpur]

Sir lamda value of root 8,2,1 aa rha hai

[@meseretwubetu7826]

can we take eigen values that are repeated?

[@TechlearnersbyNeerajSaxena]

Yes

[@creativity2521]

I am getting characteristics eqn as
Lemda to the power 3 -12 lemda 2 +38lemda -36 =0 .. is it wrong

[@PavanBSNTEE]

I'm alsoo getting Same

[@mr_ig_king_2002]

Sir thanks you mera exam tha muje find karna nhi aa rha apne btaa diya sir 🙏🙏🙏🙏🙏

[@TechlearnersbyNeerajSaxena]

Most welcome

[@vinayaksonawanexyz6555]

Thank you sir for char.equation

[@TechlearnersbyNeerajSaxena]

Welcome

[@dilipkompelli9994]

In short, we get more

[@manpreetbhatti8561]

Thank u sir.....

[@TechlearnersbyNeerajSaxena]

Welcome

[@mrx_3268]

In real value of lemda = (2) ; (7.65) ; (2.35). The sum is = 12 ✌✌

[@satyam_yadav541]

Thank you sir ☺️🙏

[@TechlearnersbyNeerajSaxena]

Most welcome

[@chandanbarnwalofficial]

Great Sir

[@TechlearnersbyNeerajSaxena]

Thanx a lot

[@wacky7697]

THANK YOU SIR❤

[@TechlearnersbyNeerajSaxena]

Most welcome

[@Nishu_50503]

Thank u sir 😊

[@TechlearnersbyNeerajSaxena]

So nice of you

[@f.r.physics3273]

Tq so much

[@harshvardhanchougule9531]

Thank u sir❤️🙏🏻

[@TechlearnersbyNeerajSaxena]

Most welcome

[@leave197]

Thank u sir

[@umeshpandit4108]

Thak you sir