Can IITians Solve The TOUGHEST JEE Questions Ever? 😱 Ft. Kanishk Priyadarshi
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- čas přidán 21. 10. 2023
- Join us as we put the exceptional students of IIT-Bombay to the test Ft. Kanishk.
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In this video, Kanishk Priyadarshi visits the campus of IIT-Bombay to challenge the brightest minds of the country to solve the MOST Difficult past JEE Questions! 😱💡
Can the brilliant minds of IIT-Bombay conquer these formidable JEE questions?
The stakes are higher than ever with a cash prize of Rs.10,000 for EVERY student who successfully solves a question! 🤑
Can the IIT-Bombay students rise to the occasion or will this challenge prove insurmountable? 🤔
Watch the video to find out! 🔥 And subscribe to Unacademy Spotlight, the ultimate destination for all things IIT JEE and NEET UG!
P.S. Preparing for IIT-JEE or NEET? Don’t forget to join Unacademy’s All Star Batch: unacademy.com/store/batch/fas... - Zábava
Everything was good but the line he said in the last that "If you are smartest in the room then leave the room but in IIT Bombay, The person sitting right next to you is smarter than you." Is the best line.
Ye mere dimag ki gehrai ki line hai
From watching these type of videos during JEE days, to being featured in one, it's been a long journey 😌
3:48 his rank was 865 jee adv mohit tyagi student
if the decomposition reaction is 2Agbr--> 2Ag+br2 then the answer would be 2.303
By using the formula 2kt=lnx/x-y where x = intial pressure =1atm y =pressure after t sec=0.9 then obtained answer is 2.303
If the decomposition reaction is 2Agbr--> 2Ag+br2 then the answer would be 2.303
By using the formula 2kt=lnx/x-y where x = intial pressure =1atm y =pressure after t sec=0.9 then obtained answer is 2.303
Reaction should be given
Hii Unacademy, Good to see that you are back with a entertainment video. And the value of Y is 2.303
I know the answer too. So, if I answer, the answer, then can I give myself the 10K cash prize?
Ofcourse you should, and you can.
Don’t you think it’ll be unfair to others?
Ofcourse it will be. Ok, don’t do it. Find someone random.
Noted.
U are epic sir😂😂
Unit of rate constant (k) represent it is a first order reaction
2N2O5→2N2O4+O2
t=0 1atm 0 0
t=t 1−p p p/2
Total pressure
1−P+P+P/2=1.45
P/2=0.45,
P=0.9
Now,
t={(2.303)/2×5×10−4 }log(1/1−P)
y×10^3={(2.303)/2×5×10−4}log(1/1−0.9)=({2.303)/2×5×10−4}log10
therefore y=2.30
now where's my money😂btw the anchor is really good!(done kanishk👍)
13:00 value of y - 2.303 commentary was lit🔥🔥🔥🔥🔥
12:58 (Ans. y=2.303) bhai ye copy paste kiya hu😢
aaaaaaa paise mil jaenge kya?
Bhai abhi pdha kuch aur logon ke comments yeh log likh rhe hai ki reaction nhi diya hua hai toh kya karein abhi..lgta hai isko bhi copy paste krna pdega yeh lo (bro reaction hi nhi diya hua hai ans kidhrr se nikale)
Yeah it's so easy peasy y=2.303 kuch aacha leke aay yaar😅
Copy karke answer dena aasan hai vro
Ashish Agarwal sir ke student ho kya?
Bina reaction ke answer kaise nikala bhai?⁰
Kanishk!!!! 🔥
Kanishk bhaiya on topp❤.
Answer will be 2.303
Nitin, ko jitao yaar Unacademy.
Tbh that was very entertaining yet full of knowledge.
Awesome brother ❤
It's answer is 2.303
Kanishk 🔥
Ranu Ji Dhanvayad
2:40 is the last product - 2,4,6 tribromoaniline?
Sach me Bhai gajab ke chhokre hai. Manna padega
Answer is A+B the hole square
12:58 Ans. 2.303
The kclo3 question is too easy man. How did it even go unsolved in the exam
So, the question here is incomplete.
If reaction is this 2N2O5(g)Δ−→2N2O4(g)+O2(g)
Then value of Y will be 2.303
2N_{2}*O_{5} * Delta 2N 2 O 4 +O 2 ;K=5*10^ -4 sec^ -1
Initial pressure (in atm)
1
Pressure after time t sec 1-2x
1 - 2x + 2x + x = 1.45atm
x = 0.45 atm
For 1st order reaction (takingaccount of reaction stoichiometry)
2Kt = ln(a_{0}/(a_{0} - x))
a_{0} propto1
and a_{0} -x propto0.1
t = 1/(2 * 5 * 10 ^ - 4) * ln(1/0.1)
into
Useapp
= 2.3 * 10 ^ 3 sec
6:08 pretty 😍
12:59 Ans is -> y = 2.303
Hey! kanky swanky 2.303 is the right answer
2.30 answer
The answer is 2.303
value of Y is 2.303
Answer is 2.303
KANKYYYY you're a masterpiece!!
Sell me.
Jaldi se comment kardeta hu
Phir 10k bhi lena hai😂😂.
Y=2.303
Keep entertaining us❤
Hahahahhaha
Answer is 2.42
12:58 Ans = 2.303 @Kanishk Priyadarshi
decomposition of what??????? reaction hi nhi di koi
Y=2.303
kankyyyy is pro
14:59 ans - 2.303
Ans 2.303
The value of y is 2.303
The answer is y = - 743.2
Kanishk ❤❤❤mast haircut ❤
Sarcasm hit huyela, screen ke through bhi
2.303 is the ans
Y= 2.303 I was surprised seeing him in unacspotlight
2.303 ❤
Answer 2.303
❤
Ans is 2.303
2.303
answer is 2.303
Y is 2.303
y=2.303
reaction to di hi nahi answer kaise nikalenge🙃🙃
Value of Y is 2.303
answer is 2.30
👏👏👏👏
2.303 broo eazzziiee
And=2.303 👍
Ladkiya bhi kya baat hai
OMG Kanishk.❤❤❤❤❤
Ji Haan?
@@smackchie Best entertaining Anchor ✨
answer is 2.303 pleaseeeeee give the moneyyyy😭
Ans =2.303
2.3
value of y=2.303
Finally answer is 😢 2.303
Answer Is 2.30
value of Y is 2.303! & KANISHK IS AS ALWAYS gr8 with @unacademy
Y= 2.303😀
Answer is Y=2.303
The answer will be 2.303
The answer is y=2.303
uttar 2.303hai 10K jaldi............. tabhi na 75 din wala batch le paunga
Good video. Good Anchor.
Y=2.303
Ans - 2.303
Saala sb tapore baithe h ...
Decomposition rxn th dii hi nhi rkkhi h ... Aur sbka ans tk aa gya ...
Waah waah bhai waah !!! 😂😂
i guess the question was incomplete as metioned i cant see any decomposition reaction in the question
Anchor op🎉🎉
The answer is y = 2.303😊
❤❤❤
Value of y is 2.303
😅Apke😂😂😂😂
Y=2.303 is ans 🎉
One like for those people who are watching it on 360p and just increased the quality 😅😅
Kanky 😅😅bhaiya
Ans : 2.303
Y is ln2 = 2.303
5:56 reaction to btao konsi h? Mujhe depression m dal diya ki kinetics ka simple sa swal solve nhi ho rha
It's 2.303
ans- 2.30
i watched the video ans is 2.303
2.303 is the answer
Ans . 2.303 need a little tough 😂
Ans=6
Awesome Content.🎉
Awesome host. 🎉
Awesome Unacademy. 🥳
And Y=2.303
The correct answer is 2.303
Too funny yrrrrrr 😂😂😂😂😅😅😂
Its easy 2.303
2.303 hai answer... nikal mere 10 hazar 😤
3:59 question from sequence and series and answers are
A) 1056
D) 1332
How did you solve it?