Let's Compare Two Numbers

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  • čas pƙidĂĄn 14. 06. 2024
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Komentáƙe • 19

  • @abdesselambassou3618
    @abdesselambassou3618 Pƙed měsĂ­cem

    Hi. I suggest to compare 10xlog(2) and 3.
    You do a great work, continue👏

    • @MniDaIlM
      @MniDaIlM Pƙed měsĂ­cem

      How would you do that?

  • @stvp68
    @stvp68 Pƙed měsĂ­cem

    Yay, radicals!!!!!!

  • @forcelifeforce
    @forcelifeforce Pƙed měsĂ­cem +3

    *@ SyberMath Shorts* -- You are leaving out the most standard, direct method, and it does not use any approximating:
    Sqrt[5 + 5sqrt(5)] vs. 4
    {Sqrt[5 + 5sqrt(5)]}^2 vs. (4)^2
    5 + 5sqrt(5) vs. 16
    5sqrt(5) vs. 11
    [5sqrt(5)]^2 vs. (11)^2
    25(5) vs. 121
    125 > 121
    Therefore, sqrt[5 + 5sqrt(5)] *>* 4.

    • @mystychief
      @mystychief Pƙed měsĂ­cem

      That's what I had. Squaring is possible without changing which side is bigger because both are positive.

    • @maxhagenauer24
      @maxhagenauer24 Pƙed měsĂ­cem

      Are you sure you can just apply it like an algebraic equation and do whatever you want as long as you do it to both? Its not an equation of any sort.

    • @robertveith6383
      @robertveith6383 Pƙed měsĂ­cem

      ​@@maxhagenauer24 -- The same operations are done to each side, and note the comment from the first reply about squaring.

    • @maxhagenauer24
      @maxhagenauer24 Pƙed měsĂ­cem +1

      @@robertveith6383 I know but if you square something less than 1 like 1/2 then you get something smaller but if you squares something bigger than 1 then it becomes bigger. Are you sure you can square both sides like that ehen comparing any 2 numbers and the bigger vs smaller of the numbers still hold true?

    • @robertveith6383
      @robertveith6383 Pƙed měsĂ­cem

      ​@@maxhagenauer24 -- Every quantity on each side in every step happens to be greater than 1. It is not the situation here, but had an expression been positive between 0 and 1, and it got squared, that would have been okay. What would not have been okay is if in adding or subtracting quantities from each side, that at least one side had become negative, then squaring afterward would not be legitimate.

  • @BorisRaifler
    @BorisRaifler Pƙed měsĂ­cem

    If we square both sides we'll get 5 + 5*sqrt(5) vs. 16. Substract 5 from both sides we'll get 5*sqrt(5) vs. 11. Square once more both sides we'll get 125 vs. 121 -> 125 > 121, therefore LHS > RHS

  • @Skank_and_Gutterboy
    @Skank_and_Gutterboy Pƙed měsĂ­cem

    This is what I did:
    Suppose that √(5+5√5) > 4. Then:
    5+5√5 > 16
    5√5 > 11 ( Note that 5(2.2) = 11, so 11/5 = 2.2 )
    √5 > 2.2
    5 > 2.2^2 (This is very easy to hand-multiply, 2.2 x 2.2 = 4.84)
    5 > 4.84
    Because 5 > 4.84 is true, all steps above are true and √(5+5√5) > 4 QED.

  • @DonEnsley-mathdrum
    @DonEnsley-mathdrum Pƙed měsĂ­cem

    Assume
    √(5+5√5)

  • @Qermaq
    @Qermaq Pƙed měsĂ­cem +1

    My approach was to square both sides, so 5 + 5sqrt(5) relates to 16. Then I can subtract 5 from both sides, so 5sqrt(5) relates to 11. Then I square both sides again, so 125 relates to 121. As I have done nothing to upset the inequality, since 125>121, sqrt(5 + 5sqrt(5)) > 4. And maybe others posted that they did it the same way. It doesn't matter. I'm sharing with the community. That's what this is all about.

    • @robertveith6383
      @robertveith6383 Pƙed měsĂ­cem +1

      Your *duplicate* solution is redundant, so therefore it is *spam,* and it is reported as such. Come up with a *unique* method for a solution when you bother to post in the forums instead of trying to get noticed for what another forum user already achieved and beat you to it. (Edit.) And, it got reported again today as persistent spam that it is.