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Class11 Physics Chapter3 One shot | Motion in straight line full chapter one shot | CBSE NEET JEE
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- čas přidán 31. 07. 2024
- #MotionInStraightLine #CBSE #JEE #NEET
Telegram group- Abhishek sahu Sir Physics
link- t.me/AbhisheksahusirPhysics
playlist All chapter - • Class11 Physics 2022-23
TimeStamp-
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
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@@khanieltsok
Sir questions answers ki bhi video create kijiye na sir👀
Sir questions answers ki bhi video create kijiye na sir👀
Thanks you so much brother
❤
Sir i am first attending your class i like so much sir sir one ques is there I mpreparing for neet i can follow u for physicspls tell sir i will surely see your lecturrs i like you lectures it is very helhpul pls tell me sir
*~1 like and subscribe = Infinity ♾️ year your mother's life please bhaiyo bheno kar do yarr🥺~*
Ye koi tareeka h bheek mangne ka 🤡
Sharam kr sanatani ho kr like ki bheekh mang rha h
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Bruh kuch bhi 💀
Done
this is a true life saver for half yearly exams , thank you so much sir for providing such amazing content .
Mera exam kal hai sach me bro sir accha padhate hain kya sare lectures download karlunga
what skl same here
@@The_Rdx bro can u give me ur paper?? Toh thodi practice ho jayegi
Really bro that's true 💯❤️🔥
Yeah 👍
57:32 Sn = 10 + ½ × 3 (2×12-1)
= 10 + 1.5 × 23
= 10 + 34.5 = *44.5 m*
Thank you sir for class 🔥
Thanks for correction bro
74m🤕
320m💀☠️
m per s
bhai mera 6.022*10 ki power 24 particles arha
What my teacher did not explain in 10 days, he explains in 1 hr 👏👏
are you able to solve hcv ?
Bhai
@@enchantedsoul8796 🤣🤣
Cauz he teaches in English and your English is like💩
Is this vdo helpful for neet 2023 agr hum 11th bhul ge h ab ye dekh k questions lga le pyq bs??
Sir please make on every chapter of 11th
Edit --- A ncert question series also
Yes sir
Yes sir
Yes sir🙂🙂🙂🙂
Yes sir
Yes bro
Arjuna jee 2.o attendance here jiski 11 barbad ho chuki hai😢
Present🎉
@@Killerharsh895 us bhai us
Puri tarah se barbad ho gyi hai
Puri khatam
Barbad😢
Anyone 2024😢😊
Yes
Present buddy
Yah
Yeah I am
Yes
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
Answer of last question is 44.5
And thank you sir for this amazing video
plzzz send the full solved answer of last question plz
mine is 46.2
@@riasingh3502 but mera answer toh 44.5 aaya
Same answer brother
@@murmuanju19 mara bhi 44.5 answer aaya ha
Thank YOU so much sir for this wonderful session loved it !! ♥
Sir answer of last question is 44.5 . THANKYOU SIR FOR THIS AMAZING LECTURE 😇
57:47 Sn =u + 1/2 a (2n-1)
= 10+ 1/2 ×3×(24-1)
= 10 + 69/2
= 20+69/2
= 89/2
= 44.5 m
How do you add 20 ? In the eq. In 4th line and why? I don't understand can you please explain me ?
LCM@@DMXHindiGaming
I appreciate that sir is working very hard for us😀
Sir thanku so much for finishing Full chapter in only 1 hr ❤️❤️
Thank you so much sir for saving time and increasing our knowledge...👍🏻👍🏻
Outstanding sir i never seen a lecture like this you teachs very well in less time love you i understand the whole chapter jn 60 minutes thanks
You are such an underrated teacher, I truly adore this channel .... huge respect to you sir ☺ thank you so much
Yeah he is such a nice teacher
@@pacificprop4 bro doesn't even know the definition of underrated 😭💀
@@gracie9717 ok, try to appreciate sir in simple way
Yeah sir is doing alot for us .. 🙂is it sufficient for school exams??? Pls tell
@@NavjotKaur-yc6uz practice more questions
Hats off to our sir who makes video till 12.30 at night to teach us 🙂👏👏
alakh panday sir makes video in 3Am 🙏
@@Premansh_tak ya alakh sir is very talented teacher & they all do so much of hard work . I also watch his videos 🙂🙂
@@Premansh_tak yes but abhishek sir is also very humble i love both of them
At 10pm
@@sumanshukla456 But I dont like alakh sir
Thank you sir ☺️ this video is very helpful for us 💖
What a beautiful explanation in less time.. Hats off you sir... Really you are very great...❤🔥
Very beautiful explanation sir you are making our confident strong
Sir you are really the Best ❤️ . Huge respect to you .
TimeStamp-
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
Credit goes to Abhishek Sir...
COPY PASTE ACHA KR LETE HO 🤣12:40 PE SAME MISTAKE SEED😂 LOL BRO
BUT THANKS
Kiskah exam kal hai ??😁🤗🍀
🙋♀️
😢
Unit test hai kal
Mera nhi h
Thank you so much sir 💓 you are very helpful to us.
Wow what a short explanation of whole chapter ... Such an amazing skill of teaching 🔥
jai allah hu akber
Sir your work is really appreciable, you are helping me a lot with your amazing short content rich videos
Who are watching this video 1 day before final exams
Like thoko
Ur explaination is really so good ❤️❤️
Thank you sir, this session was increadible💙
Literally one of the awesome lecture 🎉
Salute to you sir you are teaching students at 12 am
Thank you sir this lecture was really amazing and helpful. Thank you for this amazing lecture.
😊😊Thank you so much sir my most of doubts and topics were not cleared by any other vdos or by books but your style of teaching is best ! You start from basic so that we learn and remember easily .....again thank you sir😊
❤❤❤❤
Kon kon final exam ki preparation ke liye yaha aaya hai ??😂😅
Mein didi ji 😁
😂or Lage bhi pade he
Koi ni
Your way of teaching is easy to get....😀 thanks alot, sir
Sir you are the best teacher of physics thank you sir , huge respect you sir
Thank you sir for making one shot nd it's very helpful for us really
Very useful lecture.. thank you sir😊
best explanation.......concept get crystal clear..
Thanks for such a great support ❤️
Thanku so much sir... tomorrow is my exam and I'm very scared.. but after watching this video I'm confident.. u just clear my all doubts and now I'm ready for my test...🙂🙂once again thanku so much abhiskek sir😌😌
U are brilliant sir .I am just shocked how this whole content in 60 minutes. Superb explanation. I just had fear of physics because of u it seems interesting thank u sir 🙏🙏
Distance = 44.5 m..... Thank you sir for your wonderful explanation ❤❤...... really you are a great teacher 😀 😊 👍
or vo monkey wale ka
Sir it's great really really great sir ur teaching in a way by which it really helpfull for all of us to revise any chapter ☺️😊😊😊😊😊 thankyou so much sirr
You are a brilliant teacher 👍👍
Very well explained
Thank you sir
Thank you sir,
For the great explaination
Thankyou soo much sir . Never knew a chapter can be taught within an hour. You are far better than those Public School Teachers.
Sir really thank you i hope you will cover all the chapters of ncert in all science subjects 😀
Thank you so much sir for providing this much information in such a less time
( At 7:29 ) sir displacement is always equal or smaller than distance. It can never be bigger than the distance...❤
shut up
Right
You are such a great teacher when you teach physics i am very interested to hearing your magical lectures🥰🥰🥰❤️❤️❤️❤️🔥🔥🔥🔥
You are such a great teacher brother.....
Thank you ,Sir for such a good explanation
Thank you sir fir such a great explanation ❤
Sir you are the best physics teacher i understand all the topics ❣❣
Thank you so much sir tomorrow is my half yearly exam this video is very helpful for revision thank you again......
Thank you so much sir you are very helpful to us...
Thank you so much sir Your video is very useful for me ❤
Thanks a lot🌹❤ for working hard for us....
Sir you are the best teacher who explain very well by connecting a great connection between us due to which you now our felling🤣🤣😍😍
Sir aap ka lecture bahut ache se samajh aata hai
Thank you so much sir for this amazing lecture ❤❤❤
Love u sir ♥️
Ur explanation is too good than teachers and u made by life easy ❤🔥
Thank you so much sir for this video it really helps me to understand the topics well Once again thank you sir 😊
This vid really helped me thank u so much for such a great content🙌🏽
Thanks sir apki Vajah se mere exam se pehle Ye chapter clear Ho gya 😊😊😊
This man really deserves 50 million+ subscribers. ❤️❤️❤️👍👍👍👍💪💪💪
exactly💯💯
Kuch bhi
bro yeh kuch jyada ho gaya, 5-6 million bhi theek hai
@ѕυяуαиѕн ʝαιи внαι кαниє мє куα ʝααтα нαι?
@@suryanshjain2106 ℓ
sir your video is best for revision 👍👍
Good Evening Sir !! Finally came here to thanks you to as you are the teacher who made me realise that I can also do it!!! Because of you only in my final exams I scored more than what I deserve and I am really thankful to you for always telling and posting videos in such a less duration and will continue my 12 studies for boards from you only because the only teacher that I can trust on CZcams is you because you are a purity of NCERT
Bhaiya aapki notes making bato ko follow krke bohot help mili hland ab ye baki cheeze bhi follow krenge!!!❤❤❤
Vectors ke numerical bnao
Like this comment for next video 🙂😜
Lovely teaching sir ❤️❤️
Hats off to u sir u r real gem one day shine like diamond
sirji kisi din bahut aage jayenge
Thank you sir your explanation is very good and in short time it is very good that like all students 😅thak you very much sir for this type of explaining the chapter ❤
Best physics teacher ever seen
Thank you sir
Sir i think that part c speed of monkey with respect to ground should be 36km/hr as it is moving against the motion of train A
Thank u sir keep growing 🎉
thanks sir.. aaj equation lagani pehli baar samjh mein aayi hai
44.5 🙏🏻 very helpful video sir
My Physics final exam is on 1/03/2023 🙂 May God save me
Edit : I passed guys😂😭God saved me
same.. :(
;(
Bhaii darr lg rha
MÉRÏ V SÍSØ😩🖖😂
Mine too
Very good explanation ..... You are great teacher ❤
Sir aap bahut achha padhate ho Orr aapke jo v one shot hote hai vo actually one shot hote hai kam samay me aap bahut sari information de dete ho thank u so much sir♥️🙂
Sir dont know how to thank yuh :) and my exam is on 20 feb ..this year was so short just 6 months!!..i hope my exam will come of easy level as completing 11th syllabus was difficult for us : ( after 10 cls ,11 cls level was at good height *(i feel so) i wish everyone good luck
Are you davian
Which School
I am a DAVian and tomorrow is my physics exam and also I am PCMB student
@@karma5394 yeah:)
@@mokshjain2049 yeah i m too :)
You are the best teacher of physics in CZcams
No word to define your teaching
Thank you so much sir .🥰👍
Ha
Jee main ?
Your explanation is awesome 😎 no one in CZcams explain like you sir thank u so much sir for this wonderful explanation 😊
Just saw the differential video it's damn good ❤🎉
58:05 answer is 44.5
Solution
V = u + at
After 5s
25 = u + 5a --(1)
After 8s
34 = u + 8a --(2)
Subtract equation (1) from equation (2)
34 - 25 = u + 8a - u - 5a
9 = 3a
a = 3 m/s^2
Substitute a = 3m/s^2 in equation (1)
25 = u + 5*3
u = 10 m/s
Distance travelled in 12th second
S = u + a[n - (1/2)]
S = 10 + 3*[12- (1/2)]=44.5 m
Hope it will help you🙂🙂
Tripathi sir
Aap kon
In 1st eq time 3 sec kyu liya
@@kabirkoli7512 bhai 3 kha h 5 h vo to
last wala formula sir ka alag h?
Answer of last question is 44.5 meter of distance travelled by object in 12th second.
Thanks for this great session sir, i am highly grateful to you for this video as I was struggling with questions and basics were not much clear but after this video I have full confidence that i can solve question of this chapter too
Best video that i have came across for this topic so far thanks a lot 🙏
How?
44.5m
Answer of last question
57:43 Sn= 10+½×3(2×12-1)
= 10+½×69
=10+69/2
=89/2
=44.5m
sir u are the best physics teacher in the world . i m following u since last year . sir plz upload letures of chemistry soon plzz
This teacher is very amazing fir those students who are preparing one night before the exam😂😂
Thanks for motivating me that this video is helpful 😂
No one night bro ... In 1-2 hours 😂😂😂 ... After 2 hour my exam was start 😂
@@Yadav_Gamer001how your exam Went then ? Me also watching this video one day before exam 😂
@@msparigaming7817 mera to bro pass hona muskil lag rha
@@Yadav_Gamer001 sister bole sakta ho mera chemistry ka boahut bekar Gaya physics ka patanhi kya hoga 🥲pray karo mera kal ka paper tou acha Jaye
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Sir you are good teacher and good short explanation 🎉🎉🎉🎉
Answer is 44.5 m
Thnk u so much sir for this amazing video ... It helped me a lot✌️
Ans is 45.5
@@rashneetkaur8452 please 🥺 provide solutions
Sir at 50:20 it is 36km/hr because monkey was running in same direction and running against the velo. Of train
Dude its 72km/hr
👍
@@dhruvsingh7621 bro please check the calculation and then try to understand the concept and then read my statement please..
Yes its 36km/hr or 10m/s
thankyou sm, I was really confused:)
Yea sahu log bohot ache teacher hote he😊😊😊
thank you sir for making so amazing video ..
bcz of my late decision to join academy for neet i have a lot to manage bcz of backlog but bcz of sir it is getting really easy for me thankyou for your hard
work sir
Same thing happened with me
Can I do my neet preparation with his lecture?
@@devansharma8458 yes you can but keep practicing mcq type questions ❤️