Sir this is the first video which i saw of your and i literally had become your fan please make video a lecture on gravitation and oscillation and waves, if you are free
I have a doubt. For conservation of momentum net external forces should be zero But here mg(mass*gravity) is also acting. So external force is not zero. Plz help me. I am presently in 12 standard(india)
Thank you for your time and effort. I have this big question bothering me, I would think that on the explosion there would be forces involved (those of the explosion) how can moment be conserved in this case?
Miguel, Newton's 3rd law says that for every force there is an equal and opposite force. So those explosive forces pushing particle 1 to the right are also pushing particle 2 to the left. Newton's 3rd leads directly to conservation of momentum. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@@yoprofmatt can we also say that since the explosion occurs due to internal forces so net force externally is essentially equal to initial net force and hence momentum is conserved?
In the calculation of the Pfx, why would you not be using absolute values ? Is the final P in the x direction not the absolute sum of the parts ? To have m1v1 as negative seems to suggest a loss in overall P thus making the statement Pix = Pfx untrue. Thank you Prof. Matt.
Ciscoho, Typically we don't use absolute value bars in physics. Too time consuming. Generally all variable are thought of as positive. If something needs to be negative, we put that out in front. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Wait I’m confused is explosion in terms of conservation of momentum always conserved. We are doing a lab in physics and when I add the before momentum and final momentum I always don’t get 0 for explosions thanks
Ghost Reaper724, Yes, momentum is always conserved IF the system is isolated. On Earth, we always have gravity, so your experiment is not really an isolated system. And then don't forget about friction! That also complicates things. And air resistance, and ... Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Marko, Yes, if you can measure the velocity of all the particles (and also the heat generated). Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Where would you substract energy loss? Would you calculate it as a whole at the moment of the explosion and substract it from Pi? Then calculate it for each of P1, P2 and P3 and decrease respective V depending on time?
x_0euf, Be careful. You can't subtract energy from momentum, they are not the same units. Conservation of energy is a separate entity. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Is this collage or high school physics? I’m a freshman taking physics and this is similar to what I’m learning but different as well, so it’s a bit confusing for me
I am not sure about something regarding this problem. In an explosion doesn't one gain Kinetic energy. If all the parts combined have more kinetic energy than the initial Kinetic energy before the explosion, does conservation of momentum still hold?
Yan, Good question. Conservation of momentum always holds, so even though the particles shoot our at high velocity, the total momentum (a vector quantity) has to be conserved. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Excellent question. The explosion certainly increases the SPEED of the individual particles, meaning the energy of the explosion is transferred to the kinetic energy of the particles. But momentum is concerned with VELOCITY, which means the direction matters. The explosion cannot change the momentum of the system. Perhaps one way to think of it is this: if a stationary object explodes into two equal parts and one part is going to the right at v, what happens to the other particle? Reply back and let me know what you think. Cheers, Dr. A
I have a question .... Shouldn't the third angle be between 270 and 360 because we take angle with the positive x-axis in the anticlockwise sense ..... Please can you answer , Sir?
can anyone recommend any good books with lots of conceptual physics questions? or just questions that help build intuition? I know you just need to sit there and think and try understanding why it is all the formulas work, and trust me, I've done that SOOO much, but I would still love a good book with cool practice problems.
One of the most smartest & coolest explaination for collision in system of particles..Kudos Sir🙏🏽
Oh my gosh, thank you so much for this! You teach really well. I've been having trouble with this, but it's much clearer now.
Mind blown that this guy is writing backward
Kaitlyn,
I wish. Not that talented. Secret given away here: www.learning.glass
Cheers,
Dr. A
@Luke Smith's Guide to Cringing my math teacher does it too haha
@@yoprofmatt you invented the glass???
I think the video is inverted
I learned more in 8 minutes from this video than a 2 weeks in class
It’s probably Cz u r dumb
@@parshgoel950 Could be true. But can't argue that Anderson's teaching style is amazing.
Thanks it cleared by basics ❤️ love from India 🇮🇳
Youre a true genius sir!! Dr.A is the best
thank you sosososososo much i was struggling on this one exploding rock problem for so long
lifesaver) May God bless you with even more knowledge
this dude writes inverted to him, genius
Wow….THANK YOU SO MUCHHHHHH!
THIS MADE EVERYTHING SO MUCH CLEARER!
I'm sorry you have to correct everyone who comments 'omg he's writing backwards'
No problem, glad they're paying attention.
Cheers,
Dr. A
Sir this is the first video which i saw of your and i literally had become your fan please make video a lecture on gravitation and oscillation and waves, if you are free
This video helped a lot since I'm more of a visual learner. Thank you for making these videos
Excellent professor
Superb! Thank you Sir.
This actually makes sense.
Foof, that's a relief.
Cheers,
Dr. A
I have a doubt.
For conservation of momentum net external forces should be zero
But here mg(mass*gravity) is also acting. So external force is not zero.
Plz help me. I am presently in 12 standard(india)
I completely understood. thank you
Excellent explanation, thank you!
I just realized. Hes writing backwards to help his students. What a guy
Not that talented. Secret here: www.learning.glass
Cheers,
Dr. A
amazing! exiting! physics is awsome!!!!
Great Explanation ,Thank you .
Prabin Pandit,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
Magnificent!!!
Thank you prof
Amazing
Isn’t it possible that conservation of momentum wouldn’t be true due to the explosion applying an external force?
Nice video!!!
Thanks we'll explained
fantastic!
Thanks a lot.
+Hassan Hashemi You are very welcome. Keep up with the physics!
Cheers, Dr. A
Thank you! you made it very easy = ]
Excellent! Physics is not that scary.
Cheers,
Dr. A
Excellent sir
Many many thanks.
Cheers,
Dr. A
Thank you and excellent explain
How can I calculate the magnitude of one piece after the explosion?
Thank you!
You are very welcome.
Cheers,
Dr. a
thank you, sir
Thank you for your time and effort. I have this big question bothering me, I would think that on the explosion there would be forces involved (those of the explosion) how can moment be conserved in this case?
Miguel,
Newton's 3rd law says that for every force there is an equal and opposite force. So those explosive forces pushing particle 1 to the right are also pushing particle 2 to the left. Newton's 3rd leads directly to conservation of momentum.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
@@yoprofmatt yes this is what i was looking for thanks
@@yoprofmatt can we also say that since the explosion occurs due to internal forces so net force externally is essentially equal to initial net force and hence momentum is conserved?
When we have an supernova that explodes is the moemntum conserved?
Yep.
Cheers,
Dr. A
In the calculation of the Pfx, why would you not be using absolute values ? Is the final P in the x direction not the absolute sum of the parts ? To have m1v1 as negative seems to suggest a loss in overall P thus making the statement Pix = Pfx untrue. Thank you Prof. Matt.
Ciscoho,
Typically we don't use absolute value bars in physics. Too time consuming. Generally all variable are thought of as positive. If something needs to be negative, we put that out in front.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
BEST !
After the explosion, will the pieces move with same velocity?
Wait I’m confused is explosion in terms of conservation of momentum always conserved. We are doing a lab in physics and when I add the before momentum and final momentum I always don’t get 0 for explosions thanks
Ghost Reaper724,
Yes, momentum is always conserved IF the system is isolated.
On Earth, we always have gravity, so your experiment is not really an isolated system. And then don't forget about friction! That also complicates things. And air resistance, and ...
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
this video is amazing ı think you are a great teacher and you always explain why this is. thank you
What about a traveling object that explodes, is the initial momentum not zero?
What if there is no movement in the mass but movements in pressure waves FROM A BLAST?
awesome question. I also had that doubt
Is there a way to calculate the energy of an explosion
Marko,
Yes, if you can measure the velocity of all the particles (and also the heat generated).
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
He's a lefty
Where would you substract energy loss? Would you calculate it as a whole at the moment of the explosion and substract it from Pi? Then calculate it for each of P1, P2 and P3 and decrease respective V depending on time?
x_0euf,
Be careful. You can't subtract energy from momentum, they are not the same units. Conservation of energy is a separate entity.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
@@yoprofmatt I'm definitely going to check it out, currently developing a physics engine with my own set of laws :)
Thanks for the answer, stay safe!
He writes mirrored?!!!!!
I want to better understand your teaching technique; are your writing everything backwards to your perspective? :o
Is this collage or high school physics? I’m a freshman taking physics and this is similar to what I’m learning but different as well, so it’s a bit confusing for me
It is college (Dr A teaches at San Diego State). Intro mechanics courses may differ between universities
I am not sure about something regarding this problem. In an explosion doesn't one gain Kinetic energy. If all the parts combined have more kinetic energy than the initial Kinetic energy before the explosion, does conservation of momentum still hold?
Yan,
Good question. Conservation of momentum always holds, so even though the particles shoot our at high velocity, the total momentum (a vector quantity) has to be conserved.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
@@yoprofmatt Thank you for clarifying!
Didnt get the idea at all
Cuz i was staring at the glass thingy
It all makes sense except for one thing. Doesn't the explotion add more energy to the system, thus altering V1, V2 and V3?
Excellent question. The explosion certainly increases the SPEED of the individual particles, meaning the energy of the explosion is transferred to the kinetic energy of the particles. But momentum is concerned with VELOCITY, which means the direction matters. The explosion cannot change the momentum of the system.
Perhaps one way to think of it is this: if a stationary object explodes into two equal parts and one part is going to the right at v, what happens to the other particle?
Reply back and let me know what you think.
Cheers,
Dr. A
we are dealing in momentum, not Kinetic energy
It will go to the left with equal velocity -v so that the final momentum is 0 as it was at the beginning
I have a question .... Shouldn't the third angle be between 270 and 360 because we take angle with the positive x-axis in the anticlockwise sense ..... Please can you answer , Sir?
That is fine, but then you should not put a minus sign in front of it, since, for example, sin (330) = - sin(30).
Cheers,
Dr. A
Matt Anderson Ohh ! Thanks a lot.
can anyone recommend any good books with lots of conceptual physics questions?
or just questions that help build intuition?
I know you just need to sit there and think and try understanding why it is all the formulas work, and trust me, I've done that SOOO much, but I would still love a good book with cool practice problems.
"Conceptual Physics" by Paul Hewitt: www.conceptualphysics.com
Cheers
Dr. A
Wait, does he write backwards????
Nope. Mirror image.
Cheers,
Dr. A
Genius writes in mirror
Then padwan must write on glass.
Cheers,
Dr. A
beast
+alonso alzua Thank you, I think. Beast is good, right?
Cheers, Dr. A
Keeps picking on joseph
Cuz he's the one who asked
how to make screen writing anyone plssssssssssss
www.learning.glass
thank you
Writing backward👏👏👏
Nope. See www.learning.glass
Cheers,
Dr. A