Differentiation of Trigonometric functions 1
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- čas přidán 21. 08. 2024
- This video teaches the Differentiation of trigonometric functions of sine, cosine, tangent, secant, cosecant, cotangent and their combination etc.
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I have my finals in less than 2wks and was lagging in calculus
I just watched the whole differentiation playlist
Thank you so much
God bless you
Always welcomed 👍
@@jonahemmanuelofficialpls do a video on trig identities🥺
Thankyou so much..i have a calculus exam in a months time and i now feel ready for the differentiation questions .you have dissected this so well.blesssings
Awesome. Thank you and Goodluck
My name is precious 💕, What this man is working is Very Leaning and important to Understand.GOD bless you sir❤.
Thank you, happy to hear 👍
You are welcome.🙏👌
For the last differentiation, we can also proceed this way:
We have Cos³(2x+5). The differentiation goes:
(Cos³(2x+5))'. We know that (Cos(ax))'= -Sin(ax), and the derivative or differentiation of a powered equation is (x^n)'=nx'x^n-1(for example (x²)=2×(x)'×(x^2-1)=2×1×x=2x). So:
(Cos³(2x+5))'=3×(Cos(2x+5))'×Cos³‐¹(2x+5)=3×(-2Sin(2x+5))×Cos²(2x+5)= -6Sin(2x+5)Cos²(2x+5). You are great and you explain very well, keep up👏. I don't know much about probabilities, I would really appreciate some lessons about it.
Great..!!! Thank you,
We'll do.
Great teacher
Thank you
bro your God sent, thanks for the good work❤❤❤❤
I appreciate that
This man is too much.... It's quite understandable, I appreciate you so much sire.
Awesome, where are you watching from?
@@jonahemmanuelofficial From Freetown City Sierra Leone
Literally life saving class
Great to hear
who else is reading for exams
👍
Thank you sir you really make life easier ❤ from Nigeria
Thank you so much.
Greetings for Port Harcourt
Please do a video on tangents and normals, minima and maxima and parametric equations
It's available on this channel... check application of differentiation
Thank you very much sir for the amazing class..
Awesome.
Where are you watching from?
God bless you sir
Always welcomed 👍👍
The method is good but there's a shortcut that I would recommend. We know by formulas that:
(Sinu)'=(u)'×Cosu therefore, if, for example we want to differentiate y=Sin(2+e^5x), we'll have:
y'=(Sin(2+e^5x)'
Say u=2+e^5x, then Sin(2+e^5x)=Sinu, therefore the differentiation goes:
(Sinu)'=(u)'×Cosu, and (u)'=(2+e^5x)'=5e^5x, therefore (u)'×Cosu=(5e^5x)×Cos(2+e^5x) => y'=(5e^5x)Cos(2+e^5x). But I think your method is faster😅
Hahahaha.. great....
Thank you for sharing.
Love it.
Your explanation is very easy to understand. Good work
Thank you.
Much appreciation, Am following from East Africa.
Awesome!
Which country exactly?
@@jonahemmanuelofficial Am from Sudan but studying in Kenya
@@bigbong9453 great! Happy learning 🙂
@@jonahemmanuelofficial appreciated sir
I really do appreciate your work Sir
Great...!!!!
💎 Thank u boss ❤
Always welcomed
You're doing well bro
🙏🏻🙏🏻🙏🏻
It's really amazing
Awesome. Glad to hear 👍
thanks a lot btw... can u do a video about differentiation of hyperbolic functions and inverse hyperbolic functions?
Ok then
thank you sir✌🏻
Always welcomed
Pls in the e^5x when U differentiated it in example 3 why didn't the power reduce to 4x why did it still remain as 5x
Go check my video on exponential differentiation
Nice job done sir
Please ga you teah on how the dervatives of those trigonometrical ratios were obtained
Amazing
Great!
Where are you watching from?
❤
🙏🏻
Well done sir
Thank you sir
Always welcomed.
Thanks very much for this
@@sanimohammed8951 welcomed.
Uncle jo❤
Yes ma 💓
Thanks sir
Always welcomed 👍
Nice boss
Always welcomed
Sr i have problem in this function y= x³sin2xcos4x how to solve this
Send us a WhatsApp message 🙂
Cosecant is abbreviated cscx.
Abbreviations are relative.
Can you please help me with differentiation of Determinant
Ok
Unable to download why please
Sorry for the inconveniences.
Please try again.
A little audio echoe .but you re terrific Clear board Thank you
But how can one derive all these without craming it
Practice frequently
👍
Imagine not getting Eg.4
😂😂
😂😂