Algebra 2 Regents Review (January 2024) #13-24 | @LearningwithHaneen
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- čas přidán 20. 06. 2024
- #algebra #algebra2 #math #regents #tutorial
Let's do some regents review for the Algebra 2 regents using the January 2024 regents. In this video we examine the first 12 questions. Stay tuned for the upcoming parts.
Follow along using www.nysedregents.org/algebratwo/
If you have any questions or suggestions, please write them in the comments below! Have fun learning and make sure to like, comment, share, and subscribe!
If you are interested in one to one tutoring, use the following link: forms.gle/RXZR26EgQVCzyRMH9
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#algebra
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Can't believe how quickly this conversation is evolving! It's like a whirlwind of ideas and insights.😘
Can you make videos for other algebra 2 regents practice too please. This actually helps a lot.
Thank you so much for your comment! I could try to post small shorts tomorrow throughout the day solving some questions. If you have any specific topics let me know l and I will try. (The lateness in time for posting these is on my end) Thank you
I'd like to know how you knew that 18 was the maximum for question 14 because it doesent look like that. And I dont understand how the guessing thing works on the calculator like do you guess till you find it?
So when you graph your equation you will see when it hits it peak so to find the exact value you would do 2nd trace, scroll down to maximum and then choose your left bound enter , your right bound enter, and then put your cursor on where you think the maximum is and then once you click enter it will give you your x and y value at the maximum. Does that clarify it?
Can you review the differences between those three equations of compounded monthly vs continuously vs annually
compounded monthly is multiply the time by 12, compounded continuously is multiply the principle by e, and annually is multiply the time by 1
Compounded annually and monthly fall under the same category but when you multiply annually your n will be 1 whereas when you multiply monthly your n is 12 in the equation A= p (1+ r/n)^nt (will be identified in the question). Compounded continuously is an account continuously earning interest and you would use the equation A=Pe^rt.
@@klaus5872 thank you!
u skipped 19
Really sorry! I had it recorded but didn't attach it but 19 is an inverse question so for your equation it is originally y= x^3-3 but as an inverse it is written as x=y^3-3. Add 3 on both sides to get x+3=y^3 then cube root. After that you have cube root of x+3 and then examine what times -3 will get you 3 and that is -1 so answer choice 2.
Questa comunità non smette mai di ispirarmi. C'è così tanta passione e intelletto in ogni scambio.💚