Work done from kinetic energy - solved example | Work & Energy | Physics | Khan Academy

Let's calculate work done when velocities are given.
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Created by Mahesh Shenoy

[@priyanshukumarsingh6240]

1/2m(v^2-u^2) you can use this for faster calculation (just simplified)
v= final velocity
u=initial velocity

[@ever_e_thing]

Thank you for the knowledge, sir.

[@RishabhSingh-xz3yp]

Nice.......... i understand everything.. thankyou sir..

[@godwinmakinyiwulimaja]

You're always on point
This is such a great work done 👍
Thanks so much sir 😊

[@trenetae]

Thank you for your efforts. Great video!

[@syedrizvi2687]

Thank you for such a good explanation!

[@sakuuux]

THANKYOU

[@grahamflowers]

There is no kinetic energy in a moving mass there is force Mv squared kinetic energy is the energy of consistent work from a consistent force regards Graham Flowers

[@naveedahsan7315]

shouldn't the last answer be 7500J?

[@KhanAcademyIndiaEnglish]

Not really, I am guessing you did 250 times 30; but it's 30 squared!

[@moviecircus3063]

Yes sir

[@naveedahsan7315]

@@KhanAcademyIndiaEnglish ah yes!! I was careless😅
Thank you sir!

[@gassanali8667]

I'm the first to comment!

[@innyikoli6868]

Shouldn't the answer for the last one be -225000 J, why is it positive?