An Important Olympiad Mathematics!

Hello friends,
In this video we are going to solve a nice Olympiad mathematics (algebra) using laws of indices.All are requested to learn this mathematics and if you like this video how to solve this problem please like share comment and subscribe to my channel.
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Thanks 🙏👍 for watching!

[@JoydeepBhattacharjee-to7jr]

Nice technique to solve step by step

[@annabanerjee5164]

Nice solution, please verify.

[@DebdasBandyopadhyay-yq5jg]

Verified, please see in comment box.

[@DebdasBandyopadhyay-yq5jg]

Verify:
4^x+4^y+4^z=336
4²+4³+4⁴
=16+64+256
=336
Therefore,
X=2,y=3,z=4 is correct answer.

[@walterwen2975]

An Important Olympiad Mathematics: 4^x + 4^y + 4^z = 336; x < y < z = ?
4^x + 4^y + 4^z = 336 = (16)(21) = 4²(1 + 4 + 16) = 4² + 4³ + 4⁴
x = 2, y = 3, z = 4
Answer check:
4^x + 4^y + 4^z = 336; Confirmed as shown
Final answer:
x = 2, y = 3, z = 4

[@marcgriselhubert3915]

336 = 16.21 = 16.(16 + 4 + 1) = (4^2).(4^2 + 4^1 + 4^0)
= 4^4 + 4^3 + 4^2, then a = 4, b = 3, c = 2 (or other order)

[@DebdasBandyopadhyay-yq5jg]

Thanks 🙏👍 for your comments

[@taniacsibi6879]

Ec. Are 6 soluții prin permutarea soluției (2 ,3,4 ) PTR.. in enunț nu se specifica nimic despre x, y,z

[@DebdasBandyopadhyay-yq5jg]

Thanks for your valuable information.

[@user-ff9fx9tb8i]

4 to the power 1 = 4 or 1 he used 1

[@tinsokunsamphea5065]

x=2;y=3;z=4
x=2;y=4;z=3
x=3;y=2;z=4
x=3;y=4;z=2
x=4;y=2;z=3
x=4;y=3;z=2