Hi @SantiagoAguirre, I have a doubt. I am not able to get how to see in second case that theta is pi/2 and phi is -pi/2, as phi was not in 1st case, and in 1st case it was easy to visualize them both with spc but not in second case, as in 2nd case i am not getting what is my position vector wrt z axis and then to see its projection in xy plane.
Your position is on top of the y axis, but in second case is facing -y. There is no projection since you already are in the xy plane. Φ is -π/2 because you are on the y axis, 90 degrees from the x axis, and negative because you "rotate" the other way. You might as well keep rotating the vector in the positive direction until you get to Φ= 3π/2 which works just as well. θ is π/2 because again z axis is 90 degrees from y axis and we consider θ to be positive from 0 to π. Hope this helps
@@santiagoaguirre5927 Hi...Thanks for the reply. Thank you I understood it now. Just a request can I contact yo by any means as this problem 4.5 is related to problem 4.29 where we are asked to find forces too. And by your notation I am not getting the correct result and in the solution manual I have no idea how they do it. Can you help me out in this?
@@AnshulSharma1997 hey. I checked out the question and the solution in the manual. The first force is very easy to understand and do. For the second one applying the same method I got 0. I dont really understand why, but doing the change of coordinates and applying in the E field coordinate free form (eq 3.104) does give the correct answer. Give it some thought!
@@santiagoaguirre5927 So is there a mistake in finding the fields by you in this video as the solution to 4.29 doesn't seem to match, and also I did not get the solution manual of 2nd case of how they change by their own the dipoles position and orientation as your solution made sense too but unable to get forces....aNd yeah can i contact you by some means to discuss further upon it
@@AnshulSharma1997 this video and the solutions are correct. As I mentioned I am not sure how to solve and explain problem 4.29, I may do a video about it in the future. In the mean time try to understand the solution manual on your own or ask your professor. Good luck
Excellent explanation! thank you!
Thank you, it is excellent solution
Thanks a lot
Hi @SantiagoAguirre, I have a doubt. I am not able to get how to see in second case that theta is pi/2 and phi is -pi/2, as phi was not in 1st case, and in 1st case it was easy to visualize them both with spc but not in second case, as in 2nd case i am not getting what is my position vector wrt z axis and then to see its projection in xy plane.
Your position is on top of the y axis, but in second case is facing -y. There is no projection since you already are in the xy plane. Φ is -π/2 because you are on the y axis, 90 degrees from the x axis, and negative because you "rotate" the other way. You might as well keep rotating the vector in the positive direction until you get to Φ= 3π/2 which works just as well. θ is π/2 because again z axis is 90 degrees from y axis and we consider θ to be positive from 0 to π. Hope this helps
@@santiagoaguirre5927 Hi...Thanks for the reply. Thank you I understood it now. Just a request can I contact yo by any means as this problem 4.5 is related to problem 4.29 where we are asked to find forces too. And by your notation I am not getting the correct result and in the solution manual I have no idea how they do it. Can you help me out in this?
@@AnshulSharma1997 hey. I checked out the question and the solution in the manual. The first force is very easy to understand and do. For the second one applying the same method I got 0. I dont really understand why, but doing the change of coordinates and applying in the E field coordinate free form (eq 3.104) does give the correct answer. Give it some thought!
@@santiagoaguirre5927 So is there a mistake in finding the fields by you in this video as the solution to 4.29 doesn't seem to match, and also I did not get the solution manual of 2nd case of how they change by their own the dipoles position and orientation as your solution made sense too but unable to get forces....aNd yeah can i contact you by some means to discuss further upon it
@@AnshulSharma1997 this video and the solutions are correct. As I mentioned I am not sure how to solve and explain problem 4.29, I may do a video about it in the future. In the mean time try to understand the solution manual on your own or ask your professor. Good luck