Finding Quartiles Quick and Easy
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- čas přidán 5. 08. 2024
- This method can be used for all types of data sets but is most valuable when you have a large amount of data such as in stem-and-leaf plots.
Also, exam-type questions will generally provide you with the number of data values in the given set, which further contributes to the speed at which you can find the quartiles using this method.
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Thank you so much you made this so much easier !
Can this method use to median , Q1 and Q2 for group data(like in table form)?
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Thank you so much for this video, the formula is very helpful and come in handy.
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What if your median was 2 numbers and you had to add and divide them leaving you with a decimal ?
8:00
Does this work for third quartile
This algorithm assumes that the values are already sorted. Picking quantiles in a sorted stream of arrays is rather easy. Tricky quantiles algorithms are those that don't require sorting (they are actually faster than sorting).
all stem and leaf diagrams must be sorted... what are you on about
@@shivtyagi8572 from the video description "This method can be used for all types of data sets but is most valuable when you have a large amount of data such as in stem-and-leaf plots. ", if you have any dataset you first have to generate the stem and leave diagram which costs much more time than the quantiles algorithm (O(n log n) vs O(n)).
k thx
what if you don't get a whole number?
Thank you, I was using this blindly with the thought that if it's even I shouldn't add a 1 when using either the 1/4*n or 3/4*n. I was getting the wrong answer and got me confused. Makes me wonder when should I not add the 1
is calling q2 the inter-quartile correct?
What if its a decimal?
Then you round to the nearest whole number.
What if the number of data values is an odd???
I mean an even data of values
@@jasperley3256 If the number is even then after N+1 you will end up with an odd number. Half an odd number = X.5 th value, This just means that you need to average the number on either side of the the .5
So if 1/2(10+1) = 5.5th number. You need to average the 5th and 6th value.
He explains this at minute 5:35 in his video.
Here is an even easier way:
If the number of data points is even add 1 and multiply by 1/2 for mean, but if you are trying to find Q1 or Q3, add 2 to the even number of total data and multiply by 1/4(for Q1) or 3/4(for Q3). But if the number of total data are odd, then add 1 for median and quartiles
what is the difference between 1/4(n+1) and 1/2(n+1)?
+Mr Pantsu some books say to use 1/4(n+1) to find Q1 but that won't give you an accurate answer. It's best to find Q2 first which will split the data in half and then use 1/2(n+1) on each half of the data to find Q1 and Q3.
Ahhhh ok! Thanks a lot!!
you explained it well but I have a question , if zero is there do you count that
Yes😊
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