Can We Solve An Exponential Equation? 😁

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  • čas pƙidĂĄn 2. 08. 2024
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Komentáƙe • 9

  • @ronbannon
    @ronbannon Pƙed 23 dny +4

    Let f(x) be the left-hand side of this equation. It is easy to show that f(x) is concave up everywhere and has a minimal point at x=0 and f(0)=3.

  • @dakcom-mk6mp
    @dakcom-mk6mp Pƙed 17 dny

    Nice

  • @tunneloflight
    @tunneloflight Pƙed 21 dnem

    easier. by observation the LHS is uniformly increasing with x. Since any positive value to the 0 power equals 1, by observation x must = 0, and no other real solution is possible.

  • @mr.d8747
    @mr.d8747 Pƙed 23 dny +2

    *What about complex solutions?*

  • @phill3986
    @phill3986 Pƙed 23 dny

    😊🎉👍👍👍🎉😊

  • @michaelpurtell4741
    @michaelpurtell4741 Pƙed 20 dny

    I have watched your video several times and still do not understand why ABC need be equal.

  • @DonEnsley-mathdrum
    @DonEnsley-mathdrum Pƙed 18 dny

    In the real world, all the quantities of the left may only be positive. If we say
    f(x) = 2ËŁ+ (⅔)ËŁ+ (Ÿ)ËŁ
    then f(x) > 0 for all real x.
    f'(x) = 2ËŁln 2 + (⅔)ËŁln ⅔+ (Ÿ)ËŁln Ÿ
    = 2ËŁln 2 + (⅔)ËŁ(ln 2- ln 3)+ (Ÿ)ËŁ(ln 3-2 ln 2)
    At x = 0, we find
    f'(0) = ln 2 + (ln 2- ln 3)+ (ln 3-2 ln 2)
    = ln 2 + ln 2- ln 3+ ln 3-2 ln 2
    = 0
    f(0) = 3
    The second derivative at 0 is
    (ln 2)ÂČ + (ln ⅔)ÂČ + (ln Ÿ)ÂČ
    Since this is positive, the function only increases with positive or negative change in x.
    solution
    x = 0