The XL series are actually quite successful when used for their own purposes. For example, in my tests on the buck converter, the efficiency is around % 75-80 for the LM2596, while it is around 90-95% for the XL4005. XL6009 is for boost converter only. I see that this circuit design including the Buck converter is actually a failed topology. You did a very nice and professional job. It was useful for me, thanks a lot!
These DC-DC converters with the XL6019E1 semiconductor in the TO263-5L package performs rather poorly, given the datasheet specifications. However, the KeeYees DC-DC Boost Mini step-up converter with a micro USB input on the PCB which has the SDB628 6-pin SOT23 semiconductor package really outperforms the larger aforementioned units surprisingly well. The entire KeeYees circuit board is less than 1/3 the size of the XL6019E1 type modules. The SDB628 6-pin SOT23 component is a fraction of the size and it really outperforms the XL6019E1 by a landslide. This seems very counterintuitive to say the least. Thank you for this video and all of your research. Keep up the excellent work.
The reviewer has misread the spec sheet. The 4 amp rating is for the switching MOSFET and essentially defines the Maximum INPUT current NOT the Maximum OUTPUT current. Consider that in the video's first load test he is trying to draw 4 amps at 30 volts from a 12 volt source. This is a 120 watt load. If we assume 92% efficiency that means we must draw 130 watts from the 12 volt source. This translates into aprox. 11 Amps. This is well beyond the 4 Amp specification for the device. Because this is a buck-boost up converter the output current limit is derived from the input and output voltage. In the reviewer's example 12 Vin 30 Vout we can calculate the maximum current from this formula. Iout = (4 Amps * Vin * 0.85%) / Vout Note: I used 85% efficiency because the datasheet only gives a rating for one case and depending of the voltages it can range between 85% and 96%. Hence 85% is a safe maximum. In your specific use case, you may be able to exceed this slightly. Simplifying our equation and inserting the values used in the video we get Amps out = 3.4amps * Vin / Vout 3.4 *12/30 = 1.35 amps Maximum output at 30 Volts with and input source of 12 volts. Note this formula is for any case where Vin < Vout.
I have been victim of stores. So I am trying to test with whatever label they have on eBay, AliExpress or Amazon. so people are not fooled by the fake labels. Thanks for the comment.
If you read the data sheet for this buck boost converter it is rated at about 1 amp output continuous with about 10v differential so example 10volts in at 2 amps = 20volts out 1 amp = 22.5w input with losses about 2.5 watts 5a is its Max rating for milliseconds which includes input or output amperage
Thankyou 11:11 this is what i needed. I have 12v 2A wall charger and want to convert it to 8v 2A. Going from 12 to 8. The aplication is for replacing 2 18650 Batteries with wall adapter.
The stability test at 4.14 to 4.19 shows a nasty problem. If the input voltage drops below the minimum threshold - the output voltage jumps from the desired 8v up to 13.6v. My testing of an input supply drop-out - with a small LED load - has produced an over-voltage up to 25v when set for a 4v output. I would have expected the output to degrade safely when the input drops below the minimum.
This board works better with a heat sink on the diode. There is a well known heat problem with this board which can be solved by using a heat sink or adding another diode in parallel. (there is a video on youtube from a British guy that covers it).
Great review, very detailed and methodical. However I wish you also tested the efficiency of these things. They claim 94% efficiency in the datasheet. But with my actual test they had about 50% efficiency!! I was trying to run a 9v@1A load from a 5v supply and I realized it draws about 3.5A of current from the input.
this was one of early videos. I've added so many features to the tests. here is a converter video on my other channel which focuses only on Power, charger, solar and battery czcams.com/video/1VNqRqV0kek/video.html
I appreciate your work and demonstration. What a pity that you didn't measure the currents at 10V and 14V input and 12V output. I what to use this module to stabilize a battery. If you have that data, please let me know. Anyway thanks for the video.
Some shops do not provide information about output power. But I researched and found out it's only ~20W (and 25W with heatsink) in theory. Yeah, pretty low but don't ask too much at 2$. (Sorry if my English makes you uncomfortable)
Hi there, I ahve two questions. 1. Will adding heat sink to the IC help? 2. What buck/boost converter have you tested so far that you recommend. Thank you in advance.
it doesn't work and failed shown at 07:19 . But generally if it works, the total power P = V x I, I is current so if output is 30V at 3A, P = 30X3= 90W and the input should be 90W + losses (if 10%) = 100W. and you see at 12V, you can get I = P÷V, I= 100÷12= 8.33A
if you take off the trim pot 103=10kΩ then fb=0v; it turns out Vout=48v. if you piggy back xl6009 ic and diode ss34(max 3A instants) on the top with thermal pad then you doable double amperes from 2A to 4A. the module has no voltage protect feature but you can use for lab or cheap project not for expensive device. avg load =12w max then you need to change cap of out put=100u200v and inductor filter=8uh.
All these xl 6009/6019 converters are a great way to blow up your electronic circuits. These boosts wildly swing output voltages at low input voltage . Most test review do not even mention this or warn you. Good luck using this crap. For more see the comment from richardnanis
Nice and simple video, thank you for sharing. BY THE WAY, did you measure the A you can get @ 12V output? I'm running a project where the load (an aquarium pump) needs 2A @12VDC, and the small step up can't cope with such need. Any advice? Thx
I purchased four of these and the slow boat from China just arrived. If I wanted to drive a white LED from a 1.2v cell how would I do it since this is not a CC driver?
Question: Should you not adjust output voltage WHILE on the load instead ? Any 12v car battery will register 14.4-15v by itself and drop to 11-12v on load.
it is if you can carry on your back 50kg and walk easily up to 1000m. if they put 100kg, then your back will perhaps bent and after 200m you will stop and say "can't do it". exactly the same will happen. first the output voltage will drop and it will and then will stop working.See this datasheet www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf on page one you see very important features .
Source Input 12V > ?A if Source Power lower amp .... A. Boots Step < A. Source Power . 12V 1A = 12W if you boot to 24V Max A= 0.5A = 12W I want to know how many amps of the 12V power source. Because if you put 12V 1 A it will not boost you. The output is directly proportional to the source power supply, so if you supply lower current than what the destination load uses. It dropped. The test source is invalid, the result of this test is invalid. --------------------- อยากทราบว่า แหล่งไฟฟาต้นทาง 12V กี่แอม เพราะถ้าคุณใส่ 12V 1 A ยังไงมันก็ บูสเพิ่มให้คุณไม่ได้หรอก เอาท์พุท จะแปรผันตรงกับแหล่งจ่ายไฟต้นทาง ดังนั้น ถ้าคุณจ่ายกระแสไฟ ต่ำกว่า ที่โหลดปลายทางใช้ มันก็ดรอปนะสิ ต้นทางที่ทดสอบ ไม่ถูกต้อง ผลลัพท์ การทดสอบนี้ จึงไม่ถูกต้อง
i don't know if i sound stupid, i have no background info about this but...does the output current of XL6009 depend on the load? or it depends on something else?
No question via stupid. The current depends on the load but if load draws mor than the board can supply, then either the voltage will be reduced or the board dies.
Thanks so much for your video! In the university, when I learned about boost converter I remember that Boost only is used for low current operation, boost isn't good for hight current. Anyone can recommend a good boost/buck converter?
P=IV, I=3, V=5, so P=3(5)=15W and for output you wan to make P=2(9)=18W. so you wan to get 3W more than input. The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. you can't do it.
@@robojax Nonsense - the 4A current limit is the limit of the current flowing through the internal MOSFET. If it's in boost mode, the 4A will be the limit for the INPUT current. That's why you get the so-called "FAILED" when you try to take 4A out at 30V - with only 12V input, you're trying to draw over 10A input current. Of course it shuts down.
What is the make and model of your test equipment? I need to test converters at 12v/12A input boosted to 15v/8A output. I’ve been hunting for a way to do it. That unit would help me.
the chip is already soldered on the PCB so you can't put it on heat sink. Even if you left it, up, there is no enough room to put heat sink as the inductor is on the way. So this module is how it is used.
Hi, I am working on a project that uses a hand crank generator that I built to charge an 18650 Li-ion cell. I have a charge protection circuit for the 18650 cell which requires a 5V input. The issue that I have is that due to the nature of hand cranks the voltages they produce are quite variable. I have added a 4700uF capacitor to the output of the generator to try to help with this but I need a buck/boost converter which will take the voltage from the hand crank, about 8V (which varies by about +/- 1V) and provide a 5V output which is stable to supply the Charging circuit. The other issue is that the current draw from the battery decreases as it gets more charged so I’m worried this will further affect the stability of the buck/boosted 5V. Can you suggest a buck/boost module for this? Thanks
Yes you can use just a boost converter so it always output like 12V. then you need buck converter that brings it down to your need level. of course if you get buck boost will do that for you.
I had to watch the video to see if I have answer to your question and indeed I have. You have skipped the video. I have spend almost full day testing, recording and editing. Please watch without skipping and you will get the answer to your question.
@@robojax yes sorry, that was my fault I can conclude if the input voltage is below 3volt, the output voltage seems to rise above the desired voltage. Is it true? Is that the character? if yes, I think this module is very dangerous for a beginner thank you
Hi, I am not sure if you paid attention. I have tested different input and output voltages and tested it with load. Load is like your WiFi router. I don't remember the numbers so watch and see which value is closer to what you need and see if it work. but 12V to 9V conversion at 60mA is like nothing to this module.
Hello, with this module is it possible to supply a 3.7V 18650 2600 mAh battery with a 9V output? and how much ampere will be obtained with the output, the question is how much this module consumes, I will connect it with arduino due with 3 peripheral modules, thanks for your help
Sir, recently I bought xl6009e1 dc-dc module when I connect from battery of 5v I get desired output, however when I connect to any device immediately vtage drops and my router or modem or setup box do not turn on which consist of 12v. Your inputs is highly appreciated
I've demonstrated the maximum current (ampere). if the output power exceeds, the voltage is reduced. so check your load or router's current before connecting making sure this module is capable of powering it up. calculate input and output power and input must be 15% higher than output. your 5V must be able to have AT LEAST 15% higher power than output. Power is IV where I=current in ampere and V is voltage for both input and output calculate this. good luck.
@@robojax Sir Thanks for your valuable inputs, I have power bank with 5v 2.1a as on output. which is connected to step up module and getting output as 12v. I cannot increase input 15% as higher than output, coz i am drawing voltage and load from a mobile powerbank and boosting up to 12v. i am hobbyist and beginner not expert, so thought to do own circuit and see if works.
15% is the losses, if you can't increase the input by 15%, then subtract 15% at output. I have to make a video so anyone had question, just send them the link. when input is 12W the output can never be 12W it will always be less than the input by the amount of losses. good luck.
@@robojax sure sir I will, just all want is 5v with 2amp and step up to 12v with load of 2amp in this regard I have used mc34063 IC however it has only capacity of 1.5amp current drawn for the components have used in my circuit. Just wanted 2amp at the max, please do one video it's a request
I watched your video without skipping :) but I am still unsure of how I could use xl6009 to step down my power source from 24V 10A to 12V 2A. over here I am not worrying about the output voltage but the input current from my supply is 10A. Any ideas of stepping the current down? I was thing of using resistors in parallel configuration .
if you connect 24V 1A or 24V 1000A it doesn't make any difference when you connecting it. Only when you consume or use higher current, if the convert can't handle it, either it disconnects the output or the module burns. in your case the module will simply reduce the voltage and and allow up to 5V to pass. the 5V depends on the load. if the load needs 2A, then 2A will pass.
I need 5v to 9v 2a converter. Im confused which one to get this one or step up converter ? I need this for a guitar amp it needs dc 9v 2a. So i was thinking to use my powerbank it outputs 5v and upto 2.4a so possible to draw 9v 2a using any of this booster or converter ? What would you suggest ?
Hello, if it is broken, then you gotta replace it. The value is on the pot as 204 or 105 or any other 3 digit. if not broken, turn it about 10 to 20 turns to bring it back.
watch MT3608 review here czcams.com/video/LMKiPE_2Uu4/video.html and decide which one is better. The word "better" is relative. So you watch and decide if it is better 'for you' or not.
two different things XL6009 is 5A www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf and LM2596 is 4A converter www.ti.com/lit/ds/symlink/lm2596.pdf?ts=1607320532696&ref_url=https%253A%252F%252Fwww.google.com%252F we can't compare them. it is like a sedan and SUV.
Check for your output voltage, see how much current (ampere) is needed and if your modem power bank has that much power or current, yes you can use it. It must be DC.
@@englishrupe01 yes . I checked the polarity and limited my current to .5 amps at input. And no load is connected except multi meter... . And I agree with the circuits that I buy from chaina. I ordered many boards and never happened like that. Maybe the batch I ordered might be flawed ( may be used different valued caps or inductors). I will check in detail and update soon. Tq sm for the response ,🤗
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
yes. you supply 5V x 1A= 5W that is total power. You need 24V x 0.003 =0.0072 or 7.2mA. this is about 60 time of this device can supply and it should work fine.
@@AbhishekKumar1902 You don't know that, it depends how much current can be drawn from the power bank which will be more than 0.5A as it's boosting the voltage which lowers the current.
I believe I made this video to answer questions like this. please watch it to get the answer. I have spent over 10 hours to make this video. You can will watch it for 20 minuets and get all experience and usage of equipment and knowledge.
The maximum current is fixed in this module Your load determines if you want to draw high current or low current. connecting smaller resister at output will draw higher current . (i) is current in Amper I = V/R
the chip manufacturer rating is misleading. When you buy this module, you don't expect to attach anything. just input power and the load. That's why I am doing the test so user knows what to expect from the item they purchase.
this is Buck converter or step down converter. You need boost converter. So my videos on boost converters czcams.com/channels/kcBSig_Iu4ZnAIeCeG1TVg.htmlsearch?query=boost
@@robojax yes but are you using battery? if battery C-rate might be a factor it's failing. I've used this successfully with 18650 in 2s2p w/ 15W LED COB LED.
I did not provide it but I have noticed that these converters have about 90% efficiency which is 10% loss. So they need 10% extra power at input. for 9V and 3A output 9V x3A=27W, add 10% to it would be 1.1x27 =29.7W. Now if you need to get this power from 12V input, then 29.7W÷12V =2.48A at input.
Input current depends of the output, but in video you can’t see variations in the input it means that power is enough for the tests, the regulator is what fails
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
The XL series are actually quite successful when used for their own purposes. For example, in my tests on the buck converter, the efficiency is around % 75-80 for the LM2596, while it is around 90-95% for the XL4005. XL6009 is for boost converter only. I see that this circuit design including the Buck converter is actually a failed topology. You did a very nice and professional job. It was useful for me, thanks a lot!
That FAILED message scared the shit out of me, man
LOL 😊😊😊😊😊
same here
Same here on earphones!
These DC-DC converters with the XL6019E1 semiconductor in the TO263-5L package performs rather poorly, given the datasheet specifications.
However, the KeeYees DC-DC Boost Mini step-up converter with a micro USB input on the PCB which has the SDB628 6-pin SOT23 semiconductor package really outperforms the larger aforementioned units surprisingly well.
The entire KeeYees circuit board is less than 1/3 the size of the XL6019E1 type modules.
The SDB628 6-pin SOT23 component is a fraction of the size and it really outperforms the XL6019E1 by a landslide.
This seems very counterintuitive to say the least.
Thank you for this video and all of your research. Keep up the excellent work.
The reviewer has misread the spec sheet. The 4 amp rating is for the switching MOSFET and essentially defines the Maximum INPUT current NOT the Maximum OUTPUT current. Consider that in the video's first load test he is trying to draw 4 amps at 30 volts from a 12 volt source. This is a 120 watt load. If we assume 92% efficiency that means we must draw 130 watts from the 12 volt source. This translates into aprox. 11 Amps.
This is well beyond the 4 Amp specification for the device. Because this is a buck-boost up converter the output current limit is derived from the input and output voltage. In the reviewer's example 12 Vin 30 Vout we can calculate the maximum current from this formula.
Iout = (4 Amps * Vin * 0.85%) / Vout
Note: I used 85% efficiency because the datasheet only gives a rating for one case and depending of the voltages it can range between 85% and 96%. Hence 85% is a safe maximum. In your specific use case, you may be able to exceed this slightly.
Simplifying our equation and inserting the values used in the video we get
Amps out = 3.4amps * Vin / Vout
3.4 *12/30 = 1.35 amps Maximum output at 30 Volts with and input source of 12 volts.
Note this formula is for any case where Vin < Vout.
I have been victim of stores. So I am trying to test with whatever label they have on eBay, AliExpress or Amazon. so people are not fooled by the fake labels. Thanks for the comment.
If you read the data sheet for this buck boost converter it is rated at about 1 amp output continuous with about 10v differential so example 10volts in at 2 amps = 20volts out 1 amp = 22.5w input with losses about 2.5 watts 5a is its Max rating for milliseconds which includes input or output amperage
Thankyou 11:11 this is what i needed. I have 12v 2A wall charger and want to convert it to 8v 2A. Going from 12 to 8. The aplication is for replacing 2 18650 Batteries with wall adapter.
The stability test at 4.14 to 4.19 shows a nasty problem. If the input voltage drops below the minimum threshold - the output voltage jumps from the desired 8v up to 13.6v. My testing of an input supply drop-out - with a small LED load - has produced an over-voltage up to 25v when set for a 4v output. I would have expected the output to degrade safely when the input drops below the minimum.
This board works better with a heat sink on the diode. There is a well known heat problem with this board which can be solved by using a heat sink or adding another diode in parallel. (there is a video on youtube from a British guy that covers it).
this product is very cheap. buying diode would cost the same as the board. People should simply avoid this a select something else.
Help me to find him please.
@@muflatu He probably means Antony Cartwright.
Great review, very detailed and methodical. However I wish you also tested the efficiency of these things. They claim 94% efficiency in the datasheet. But with my actual test they had about 50% efficiency!!
I was trying to run a 9v@1A load from a 5v supply and I realized it draws about 3.5A of current from the input.
this was one of early videos. I've added so many features to the tests. here is a converter video on my other channel which focuses only on Power, charger, solar and battery czcams.com/video/1VNqRqV0kek/video.html
thanks for the thorough testing
Our pleasure!
Great !! ⭐⭐⭐⭐⭐
Subscribed.
thank you sir you are so good Im Ali from Iraq 💖😊
I appreciate your work and demonstration. What a pity that you didn't measure the currents at 10V and 14V input and 12V output. I what to use this module to stabilize a battery. If you have that data, please let me know. Anyway thanks for the video.
Thank you very much good job
Good review sir very specific
Hope for further videos
I will try my best
Thanks. Good test.
Thank you too!
Thank you for this video
Some shops do not provide information about output power. But I researched and found out it's only ~20W (and 25W with heatsink) in theory. Yeah, pretty low but don't ask too much at 2$.
(Sorry if my English makes you uncomfortable)
Hi there, I ahve two questions.
1. Will adding heat sink to the IC help?
2. What buck/boost converter have you tested so far that you recommend.
Thank you in advance.
1-yes it can reach up to 5A 2-Can't recommend but you can see them here czcams.com/users/robojaxTVsearch?query=review
Thanks I need this
Problem is with the charging capacitors, inductors and line path ampherage. Not with the topology...
I noticed that adding a slice of tin foil over the heat sink helps improve these numbers
thank you for tip.
19v 2a 34v 👍👍
Nice
12V input and 30V - 4A output... How many Amps are you pulling from the INPUT ? 10 A ? ratings are given for the input, no ?
it doesn't work and failed shown at 07:19 . But generally if it works, the total power P = V x I, I is current so if output is 30V at 3A, P = 30X3= 90W and the input should be 90W + losses (if 10%) = 100W. and you see at 12V, you can get I = P÷V, I= 100÷12= 8.33A
if you take off the trim pot 103=10kΩ then fb=0v; it turns out Vout=48v. if you piggy back xl6009 ic and diode ss34(max 3A instants) on the top with thermal pad then you doable double amperes from 2A to 4A. the module has no voltage protect feature but you can use for lab or cheap project not for expensive device. avg load =12w max then you need to change cap of out put=100u200v and inductor filter=8uh.
Your suggestion might work. then why use the module at all? Make your own PCB and circuit.
All these xl 6009/6019 converters are a great way to blow up your electronic circuits. These boosts wildly swing output voltages at low input voltage . Most test review do not even mention this or warn you. Good luck using this crap. For more see the comment from richardnanis
you are right.
V.good video, you definitely need to get a FLIR cam.
thanks. see my latest review of converter czcams.com/video/hkLC6EcSklI/video.html
Nice and simple video, thank you for sharing. BY THE WAY, did you measure the A you can get @ 12V output? I'm running a project where the load (an aquarium pump) needs 2A @12VDC, and the small step up can't cope with such need. Any advice? Thx
Thank you. You are right. At the time, I did not have power supply with 30V and 5A. now I have got it and make sure to do another test with 30 or 35V
Nice and clear. Have you tested booster XL6009?
Here is how to find a video in a channel czcams.com/video/OhkUceBWcHs/video.html
I purchased four of these and the slow boat from China just arrived. If I wanted to drive a white LED from a 1.2v cell how would I do it since this is not a CC driver?
Question: Should you not adjust output voltage WHILE on the load instead ? Any 12v car battery will register 14.4-15v by itself and drop to 11-12v on load.
You can adjust but if the output is connected to sensitive device you might burn that device if voltage increases
Seems to have two inductors. Is it an isolated buck / boost converter ?
What will happen if I connect 10A to the Input ???? Plz Reply to me!
it is if you can carry on your back 50kg and walk easily up to 1000m. if they put 100kg, then your back will perhaps bent and after 200m you will stop and say "can't do it". exactly the same will happen. first the output voltage will drop and it will and then will stop working.See this datasheet www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf on page one you see very important features .
These are not safe to use they will blow your load because most of the safety features don't even work.
If battery drop (input), your device output will be burn 🔥🔥🔥
Source Input 12V > ?A if Source Power lower amp .... A. Boots Step < A. Source Power .
12V 1A = 12W if you boot to 24V Max A= 0.5A = 12W
I want to know how many amps of the 12V power source.
Because if you put 12V 1 A it will not boost you.
The output is directly proportional to the source power supply, so if you supply lower current than what the destination load uses. It dropped.
The test source is invalid, the result of this test is invalid.
---------------------
อยากทราบว่า แหล่งไฟฟาต้นทาง 12V กี่แอม
เพราะถ้าคุณใส่ 12V 1 A ยังไงมันก็ บูสเพิ่มให้คุณไม่ได้หรอก
เอาท์พุท จะแปรผันตรงกับแหล่งจ่ายไฟต้นทาง ดังนั้น ถ้าคุณจ่ายกระแสไฟ ต่ำกว่า ที่โหลดปลายทางใช้ มันก็ดรอปนะสิ
ต้นทางที่ทดสอบ ไม่ถูกต้อง ผลลัพท์ การทดสอบนี้ จึงไม่ถูกต้อง
Thanksss.
You're welcome
i don't know if i sound stupid, i have no background info about this but...does the output current of XL6009 depend on the load? or it depends on something else?
No question via stupid. The current depends on the load but if load draws mor than the board can supply, then either the voltage will be reduced or the board dies.
What is the equipment you use to create the test load? I could do with one!
I should have mentioned in the video as "Electronic load" and I have a video on that: czcams.com/video/-kI7OtTHd18/video.html
what was your input current?
Thanks so much for your video! In the university, when I learned about boost converter I remember that Boost only is used for low current operation, boost isn't good for hight current.
Anyone can recommend a good boost/buck converter?
You're very welcome! I can't suggest. But have tones of videos. czcams.com/users/robojaxTVvideos search here
Good video, with a power bank 5V 3A, can you opt for the 9v and 2A output? Thank you
P=IV, I=3, V=5, so P=3(5)=15W and for output you wan to make P=2(9)=18W. so you wan to get 3W more than input. The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. you can't do it.
Hi Robojax! The "4A" current limit specified on this module is IN or OUT current? Whichever is bigger?
Hi, it is OUT. See my test.
@@robojax Nonsense - the 4A current limit is the limit of the current flowing through the internal MOSFET. If it's in boost mode, the 4A will be the limit for the INPUT current. That's why you get the so-called "FAILED" when you try to take 4A out at 30V - with only 12V input, you're trying to draw over 10A input current. Of course it shuts down.
@@RexxSchneider yes. You're right. Power is limited
What is the make and model of your test equipment? I need to test converters at 12v/12A input boosted to 15v/8A output. I’ve been hunting for a way to do it. That unit would help me.
it is called 150W electronic load. sold on eBay. I have a video on it here : czcams.com/video/-kI7OtTHd18/video.html
I will bet you the problem is heat not being dissipated, and the device protecting itself. Wonder if a heatsink will help
the chip is already soldered on the PCB so you can't put it on heat sink. Even if you left it, up, there is no enough room to put heat sink as the inductor is on the way. So this module is how it is used.
I want to get 12V 2.1 or 2.2 amp from this module as output voltage. Will it drop when the load is putted?
this test was exactly for that purpose so you can get to see it. Please watch and come to conclusions
@@robojax do you have any videos with XL 6019 board?
Does heatsink on the IC help on the temperature?
of course it does help.
Hi, I am working on a project that uses a hand crank generator that I built to charge an 18650 Li-ion cell. I have a charge protection circuit for the 18650 cell which requires a 5V input.
The issue that I have is that due to the nature of hand cranks the voltages they produce are quite variable. I have added a 4700uF capacitor to the output of the generator to try to help with this but I need a buck/boost converter which will take the voltage from the hand crank, about 8V (which varies by about +/- 1V) and provide a 5V output which is stable to supply the Charging circuit.
The other issue is that the current draw from the battery decreases as it gets more charged so I’m worried this will further affect the stability of the buck/boosted 5V.
Can you suggest a buck/boost module for this? Thanks
Yes you can use just a boost converter so it always output like 12V. then you need buck converter that brings it down to your need level. of course if you get buck boost will do that for you.
what happens if you use an input voltage less than the recommended voltage?
maybe a voltage less than 5 volts
I had to watch the video to see if I have answer to your question and indeed I have. You have skipped the video. I have spend almost full day testing, recording and editing. Please watch without skipping and you will get the answer to your question.
@@robojax yes sorry, that was my fault
I can conclude if the input voltage is below 3volt, the output voltage seems to rise above the desired voltage.
Is it true?
Is that the character?
if yes, I think this module is very dangerous for a beginner
thank you
@@ayaaca8500 It seem so, but the testing below 3.6v was so brief it's not conclusive.
Sir can i run a 9volt 0.06amp wifi router with this module.use as a buck module from 12to 9volt?
Hi, I am not sure if you paid attention. I have tested different input and output voltages and tested it with load. Load is like your WiFi router. I don't remember the numbers so watch and see which value is closer to what you need and see if it work. but 12V to 9V conversion at 60mA is like nothing to this module.
Please Sir will it work with input of 4.2v from lithium ion battery?
And why if yes?
I have mentioned they minimum and maximum input voltage and shown datasheet. Please watch the video.
please also use a thermal camera to monitor the chip temperature
I did use it when I had the camera. But some videos are done before I got a thermal camera.
@@robojax ok, keep up the good work 👍
Thanks. Will do .
Hello, with this module is it possible to supply a 3.7V 18650 2600 mAh battery with a 9V output? and how much ampere will be obtained with the output, the question is how much this module consumes, I will connect it with arduino due with 3 peripheral modules, thanks for your help
Hi, I did this test to answer all question you might have. Please watch it without skipping the video. watch it fully and you will find the answer.
Greetings friend!! Considering the use of XL6009, what is the minimum voltage that I need to input to obtain an output of 19V 2A?
Hi, CZcams made new tools so I can check which comments I have not replied and here I found you. Sorry I missed your comment.
why you removed the diode from the input sir?
I have not modified anything. Where ? please mention the time like 3:45 so I look at it
Sir, recently I bought xl6009e1 dc-dc module when I connect from battery of 5v I get desired output, however when I connect to any device immediately vtage drops and my router or modem or setup box do not turn on which consist of 12v.
Your inputs is highly appreciated
I've demonstrated the maximum current (ampere). if the output power exceeds, the voltage is reduced. so check your load or router's current before connecting making sure this module is capable of powering it up. calculate input and output power and input must be 15% higher than output. your 5V must be able to have AT LEAST 15% higher power than output. Power is IV where I=current in ampere and V is voltage for both input and output calculate this. good luck.
@@robojax Sir Thanks for your valuable inputs, I have power bank with 5v 2.1a as on output. which is connected to step up module and getting output as 12v. I cannot increase input 15% as higher than output, coz i am drawing voltage and load from a mobile powerbank and boosting up to 12v.
i am hobbyist and beginner not expert, so thought to do own circuit and see if works.
15% is the losses, if you can't increase the input by 15%, then subtract 15% at output. I have to make a video so anyone had question, just send them the link. when input is 12W the output can never be 12W it will always be less than the input by the amount of losses. good luck.
@@robojax sure sir I will, just all want is 5v with 2amp and step up to 12v with load of 2amp in this regard I have used mc34063 IC however it has only capacity of 1.5amp current drawn for the components have used in my circuit. Just wanted 2amp at the max, please do one video it's a request
I watched your video without skipping :) but I am still unsure of how I could use xl6009 to step down my power source from 24V 10A to 12V 2A. over here I am not worrying about the output voltage but the input current from my supply is 10A. Any ideas of stepping the current down? I was thing of using resistors in parallel configuration .
if you connect 24V 1A or 24V 1000A it doesn't make any difference when you connecting it. Only when you consume or use higher current, if the convert can't handle it, either it disconnects the output or the module burns. in your case the module will simply reduce the voltage and and allow up to 5V to pass. the 5V depends on the load. if the load needs 2A, then 2A will pass.
@@robojax OK thanks. As you can see from my electrical knowledge I am a hobbyist
@@robojaxRobojax I get confused, guess you mean 5A not 5V.
I need 5v to 9v 2a converter. Im confused which one to get this one or step up converter ? I need this for a guitar amp it needs dc 9v 2a. So i was thinking to use my powerbank it outputs 5v and upto 2.4a so possible to draw 9v 2a using any of this booster or converter ? What would you suggest ?
9v 2A is 18W and your supply could only give 5v 2.4A which is 10.8W, so it's not possible.
Hellow sir i have another question
Can i put 20a max current on this module?
Ty for the response
Hello, current does not matter at input. you can put 1000A battery. this module takes current only for the load that it needs.
Low input amp?
sorry missed your comment. what do you mean by "low input amp" ?
Could you please try with INPUT 5V , OUTPUT 12V , load 1.5A?
you can do it easily.
would 2pcs of XL009 in parallel connection would double the ampere capacity?
Yes BUT you have to set exactly output voltage.
@@robojax thank you sir, i think this solves my problem👍👍
when input 3.2v - 3.3v module get something is go boost to up 28v😅
hello bro i have one question please ..can i use it for regulate turbine voltage.?
Yes this is exactly does that. For example your turbine is 12V to 18V and you want always 9V, this will always give you 9V.
Hello, xl6009e1 can i use it to run an electric bike motor
Hello, if your bike motor has two wires which is called DC motor then yes.
hey robojax I accidently cranked up or down the pot in the circuit. How do I fix it?
Hello, if it is broken, then you gotta replace it. The value is on the pot as 204 or 105 or any other 3 digit. if not broken, turn it about 10 to 20 turns to bring it back.
@@robojax value on mine now is about 260 ohms
is it broken ?
Mt 3608 is better than xl6009????
watch MT3608 review here czcams.com/video/LMKiPE_2Uu4/video.html and decide which one is better. The word "better" is relative. So you watch and decide if it is better 'for you' or not.
Which is better , xl6009 or lm2529 ???
two different things XL6009 is 5A www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf and LM2596 is 4A converter www.ti.com/lit/ds/symlink/lm2596.pdf?ts=1607320532696&ref_url=https%253A%252F%252Fwww.google.com%252F we can't compare them. it is like a sedan and SUV.
Can i input 12 v battery 20 ah
And could get 24 v 5 amp?
Hello, that is exactly I made the video so you watch and get the answer. I don't know unless I watch it. so you watch.
Can i use xl6009 for 12v modem using power bank???
Check for your output voltage, see how much current (ampere) is needed and if your modem power bank has that much power or current, yes you can use it. It must be DC.
Hii I'm using the same module, but it's overheating. Even the solder melting. Plz help me..
Either reduce load. Or reduce input voltage. If it does this without load, then the module is bad.
@@robojax yes its with no load. And multiple modules burned. All those boards are faulty?
@@amargupta.8847 Obviously not, as his is not. No, they are generally very reliable in my experience. Are you connecting it correctly?
@@englishrupe01 yes . I checked the polarity and limited my current to .5 amps at input. And no load is connected except multi meter... . And I agree with the circuits that I buy from chaina. I ordered many boards and never happened like that. Maybe the batch I ordered might be flawed ( may be used different valued caps or inductors). I will check in detail and update soon. Tq sm for the response ,🤗
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
Can i use it for input 5 volts 2 amp (power bank) to boost up 15 volts 1 amp to power a modem router? Thanks..
Unless I watch the video, I won't know. So please watch and see the tests and you will know.
@@robojax lol
No just multiply volts and amps 5v x 2 amp = 10watts 15v x 1amp = 15 watts so from a 2 amp supply it is not possible even if it was 100% efficient
Hello, i need 3mA at 24V, my supply is 5V, 1A, can this module do this?
yes. you supply 5V x 1A= 5W that is total power. You need 24V x 0.003 =0.0072 or 7.2mA. this is about 60 time of this device can supply and it should work fine.
The boost tests were particularly bad. I just ordered one if these before i seen your videos. I got it to go from 12.3v to 14v and my load is 500ma.
I want input 5v from power bank and i want run my router and onu 12v 0.5A 2device??
yes u can power it
@@AbhishekKumar1902 You don't know that, it depends how much current can be drawn from the power bank which will be more than 0.5A as it's boosting the voltage which lowers the current.
Can we add heatsink on its board?
people use smart ways to attached heatsink. Sure if you can attach it to the chip, it will help greatly.
Just put a grain of thermal plaster or a piece of thermal adhesive tape.
Can I use this for steping down 24V 10A to 12V 2A?
I believe I made this video to answer questions like this. please watch it to get the answer. I have spent over 10 hours to make this video. You can will watch it for 20 minuets and get all experience and usage of equipment and knowledge.
@@robojax ok thx. I will re watch it again
you are welcome.
Which thing is used to increase current ma to A
The maximum current is fixed in this module Your load determines if you want to draw high current or low current. connecting smaller resister at output will draw higher current . (i) is current in Amper I = V/R
@@robojax i had a current 30ma and i need a cuurent 2A what can i doo
you had 30ma and need 2A? sorry didn't get it. you had 20mA where?
Xl6009 vs mt3608 which is best
here is the video on that czcams.com/video/LMKiPE_2Uu4/video.html watch and compare
Can I use this for 3.7 to 5v
I believe I made this video to answer these type of questions. Please watch it without skipping. you will get the answer.
its rated with 25 watt max and 20watt with no cooler...
the chip manufacturer rating is misleading. When you buy this module, you don't expect to attach anything. just input power and the load. That's why I am doing the test so user knows what to expect from the item they purchase.
@@robojax when chinese rated something... expect you can only get half of it but not bad for the price lol...
Can i give 3.3 v and get 5v 2amps output
this is Buck converter or step down converter. You need boost converter. So my videos on boost converters czcams.com/channels/kcBSig_Iu4ZnAIeCeG1TVg.htmlsearch?query=boost
@@robojax Umm....i think you are confused with all your videos Robojax, lol. This one is a buck boost.
Yes, that should be OK
Thank you so much for the video.
Would you please make a video on the ( CJMCU-758 ACS758LCB-050B-PFF-T Linear Current Sensor Current Module ) ????
You are welcome. Sure I will. I just put it on my list.
how many amp your input source?
Poutput=Iout X Vout and Pin=Iin X Vin to find the current subtract add 15% power to the input so Pin + 15%Pin = Pout. the 15% is losses of the module.
@@robojax yes but are you using battery? if battery C-rate might be a factor it's failing. I've used this successfully with 18650 in 2s2p w/ 15W LED COB LED.
like your example, 30v 4a. Can your 12v supply do 11.5a ? Also 12a draw is already over specification thus will fail.
No sound ..
Turn the volume Up. 1000s of people have watched it. It has sound
Ridiculous ‘testing’ in boost mode. Milliamps would have been sensible.
What is input current
I did not provide it but I have noticed that these converters have about 90% efficiency which is 10% loss. So they need 10% extra power at input. for 9V and 3A output 9V x3A=27W, add 10% to it would be 1.1x27 =29.7W. Now if you need to get this power from 12V input, then 29.7W÷12V =2.48A at input.
Input current depends of the output, but in video you can’t see variations in the input it means that power is enough for the tests, the regulator is what fails
Input ampere???
I believe I made the to actually show exactly the input current (input ampere as you call it). have you watched the video?
This madule is max 15 watt with heatsink
It had 5A rating at all 1.2V to 32V output voltage. See it on datasheet: www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf
I like anti-clockwise to increase output voltage, just like a water tap!
Yes but some people like it like volume control on Car to increase the volume.
@@robojax
Oh yes, I can see that
All these xl chips are god awful, just get a classic uc384x based converter instead or a monolithic power systems sycnronous one.
I need 3 pcs, this items...
they are very cheap on eBay and aliExpress.
I can't find this item, link please, please
what a bull$h!t
thanks for you great video , now i'm knowing i cant run even a fan using this!
Glad I could help
Failed Failed Failed Failed Failed....lol
Yes. They put misleading title for modules. LOL
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
Hello, please search my channel. I've tones of reviews on other modules including the boost converters.