Excellent video. Just a quick question. We have to add heat here in step 3 because removing OH as a leaving group is so unfavorable right? Also, would we consider the red boxed in product thermodynamic and the other 2 kinetic?
So step 3 is an intramolecular aldol condensation. We need the heat to favor the aldol condensation mechanism to form the alkene product - this is an elimination mechanism (which is favored by heat) where we lose H2O (hence the name condensation) from the OH and H (alpha carbon) which I discuss at 5:00 onwards. If we don't apply heat we would get the aldol product (with the OH group still attached).
Hello Quynh! You can check it out here: www.chadsprep.com/chads-elementary-biochemistry-videos/ There's a nice drop-down menu outlining the entire course. It was designed to follow a 1-semester survey course on biochemistry. Hope this helps!
@@ChadsPrep It's less so from this video but more so hypothetical. Because at 8:12 I noticed that a conjugated ketone could have been formed so I was just wondering. Thank you!
We have to consider both steric hindrance and the presence of donating groups (alkyl groups) in this case which reduce the electrophillic nature of the beta carbon
God bless you! You have no idea how much this video helped me! Thank you Chad so much!!!!
Glad it did, David - thank you!
Thanks for the repost Chad. You're a real pro!
You're welcome Peyman and thanks in return! I definitely don't want any errors out there confusing students. Super appreciate you catching my error!
Thanks u sir , this really help in my iit preparation
You're welcome - Happy Studying!
Hey, how did iit end up going?
Excellent video.
Just a quick question. We have to add heat here in step 3 because removing OH as a leaving group is so unfavorable right? Also, would we consider the red boxed in product thermodynamic and the other 2 kinetic?
So step 3 is an intramolecular aldol condensation. We need the heat to favor the aldol condensation mechanism to form the alkene product - this is an elimination mechanism (which is favored by heat) where we lose H2O (hence the name condensation) from the OH and H (alpha carbon) which I discuss at 5:00 onwards. If we don't apply heat we would get the aldol product (with the OH group still attached).
Hi Chad, Im wondering what your elementary biochemistry is. Btw thank you for your awesome videos
Hello Quynh! You can check it out here: www.chadsprep.com/chads-elementary-biochemistry-videos/
There's a nice drop-down menu outlining the entire course. It was designed to follow a 1-semester survey course on biochemistry.
Hope this helps!
Hi Chad, my organic chemistry class teaches one more chapter (carbohydrates and reactions of carbohydrates, etc) can you add to your playlist?
Alright Sophia! I'll have the first one ready in the morning. 😊
How's your class been going?
Robinson Annulation? More like "Really great information!" 👍
And another!
If the product ends up creating another conjugated ketone, can you expect the reaction Robinson Annulation to occur again?
Which example are you looking at?
@@ChadsPrep It's less so from this video but more so hypothetical. Because at 8:12 I noticed that a conjugated ketone could have been formed so I was just wondering. Thank you!
We have to consider both steric hindrance and the presence of donating groups (alkyl groups) in this case which reduce the electrophillic nature of the beta carbon
🙌
Thanks - Happy Studying!