सिद्ध कीजिए कि √5 एक अपरिमेय संख्या है | Prove That √5 is Irrational Number | Class 10th NCERT Maths
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- čas přidán 9. 10. 2023
- सिद्ध कीजिए कि √5 एक अपरिमेय संख्या है | class 10 math chapter 1 vastavik sankhyaen | class 10th प्रश्नावली 1.3
aaj ke live session me humne class 10th ncert maths book ke exercise 1.3 se important questions sikha jisme sikha siddh kijiye ki root 5 ek aparimey sankhya hai. aparimey sidhh karne ka bahut aasan tarika is live class me bataya he. jisse aap root 5 ko aparimey prove krna sikh jayege. yeh class 10 maths exams me bahut baar pucha jata he. Irrational proof krne ke liye class 10th maths me bahut baar pucha jata he. Irrational proof krne ka bahut aasan tarika is video me bataya gaya he.
Agar aap ko Video achcha laga to like kre and hamare channel explain 4u ko subscribe kre hum aaise hi mathematics content apne chennel late rahte he.
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about this video:-
1) sidhh kijiye ki root 5 ek aparimey sankhya hai
2) proof root 5 irrational in hindi
3) aparimey sankhya kya hoti he
4) parimey or aparimey sankhya
5) aparimey sankhya siddh karna
6) root 5 aparimey sankhya udaharan
7) class 10th maths prashnavali 1.2
8) class 10th vastavik sankhyaen
9) root 5 ek aparimey sankhya hai siddh kijiye
10) parimey aur aparimey sankhya
#explain4u #aparimeysankhya #class10maths #ncertmathclass10
#aparimey_sankhya #aparimey #vastaviksankhya #realnumbers #liveclass10 #class10live #class10 #class10th #maths #ncertmaths
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सर मै यश ठाकुर मै अभी 10 वी में हू मेरे पेपर दिसंबर में है रूक जाना नहीं के आप एक दो विडियो में रीविजन करवा दो परीक्षा के हिसाब से प्लीज़ सर ।
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