Calculating the mean of a histogram

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  • čas přidán 25. 08. 2024
  • The process used to find the mean of a set of data in which the values are labeled as intervals. This video only specifically applies to equal class width histograms. This is Not a type of Frequency Density histogram. If you are looking for that type of calculation I have another video for that. I repeat this is not a video that covers a frequency density histogram.

Komentáře • 90

  • @Rowse1994
    @Rowse1994 Před 5 lety +105

    Over complicated it could of just said multiply the middle of each class interval by the frequency and then divide that number by all the frequencies added up

  • @SnotRockets55
    @SnotRockets55 Před 6 lety +61

    THANK you. Teachers never explain how to actually DO math anymore.

  • @aces1608
    @aces1608 Před 4 lety +8

    My man good at teaching, pay respects.

  • @happypuddle1993
    @happypuddle1993 Před 3 lety +14

    The y-axis on a histogram is frequency-density, so the tallest bar is not necessarily the one with the most ones. (A very wide bar with the largest frequency would look shorter than a thin bar with not that many, even though more people were in the shorter bar)

    • @dminger1
      @dminger1  Před 3 lety +5

      When using univariate data, that is separated into equal class widths. It is not necessary to create a frequency density histogram. Yes I know when you do your studies many times teachers will focus on Frequency Density histograms, however, the reason for that is it allows for better comparison to other data sets. This is not what this video aimed at, this I a basic 7th grade Algebra I histogram. I made this video specifically for my students who were prepping for our state exam that could potentially require them to calculate the mean of a univariate data histogram of equal class width. The important part of this video is that my class widths are all equal. If my class widths were not equal then you would be correct that I must label the Vertical axis Frequency Density.

  • @jordanfrancis2502
    @jordanfrancis2502 Před 4 lety +13

    Thank you so much man this helped so much, I’ve been so bad at averages on histograms and this helped me ace all the work in histograms

  • @bltxcz3171
    @bltxcz3171 Před 3 lety +6

    Thank you so much, now i could pass my exam!! cuz teachers never really explain how to calculate anymore ;-;

  • @kismetgundersen9716
    @kismetgundersen9716 Před 4 lety +11

    Isn't the y-axis supposed to be frequency density, not frequency

    • @dminger1
      @dminger1  Před 4 lety +2

      The answer is dependent on how you determine your class intervals. Here is a site you can look to see that there are three different ways to group your classes and the y-axis is labeled based upon those. newonlinecourses.science.psu.edu/stat414/node/120/

  • @jojosiwafan
    @jojosiwafan Před 3 lety +21

    “quick video”
    the nine minute video 👁👄👁

  • @sweetlukejames7748
    @sweetlukejames7748 Před 3 lety +1

    Absolute 🐐 helped me on big test thx

  • @charliebayer4540
    @charliebayer4540 Před rokem +1

    Great video! Thanks for your help.

  • @jjack3380
    @jjack3380 Před rokem +1

    thank you so much for this video

  • @superkobster
    @superkobster Před 4 měsíci +1

    cheers minger

  • @timjanssen3078
    @timjanssen3078 Před rokem

    thank you very much for this video. it helped me a lot! you explain it very good, thank you!!

  • @Jsong-ft9fv
    @Jsong-ft9fv Před 2 lety +1

    Thank you!

  • @edwardjarman9074
    @edwardjarman9074 Před 6 lety +3

    Cheers Mate

  • @nicolasayala9114
    @nicolasayala9114 Před rokem +1

    Thank you! :)

  • @tiaibnmuaz5591
    @tiaibnmuaz5591 Před 3 lety +1

    That was so cool.

  • @emmajones3110
    @emmajones3110 Před 7 lety +1

    Thank you really helped clarify the fuzzier areas needed clear !!

  • @phoebecotes1857
    @phoebecotes1857 Před 7 lety +19

    THE ONE ON THE SIDE FREQUENCY DENSITY NOT THE FREQUENCY

    • @dminger1
      @dminger1  Před 6 lety +1

      Phoebe Cotes You do not label a histogram as frequency density when you have class-widths of equal length. I will relinquish to you the fact that in higher level statistics courses that yes a “true” histogram should technically be the frequency density. However it is not an absolute requirement to do so when the intervals are of equivalent length. So the video and all of its mathematical processes are correct and labeling the y-axis as frequency is not technically wrong. The concept of frequency density is important but as stated in the video this is a basic level problem. So there is no need to talk about density for this level of problem

    • @kismetgundersen9716
      @kismetgundersen9716 Před 4 lety

      @@dminger1 But if the class widths are equal lengths then showing it in a histogram is pointless

  • @rakhitomar301
    @rakhitomar301 Před 4 lety +1

    Thank u sir

  • @nirvantyagi6238
    @nirvantyagi6238 Před 3 lety +1

    Thank you

  • @Marie-wb3ec
    @Marie-wb3ec Před 3 lety

    why isn't the mode 39. isn't the mode the greatest number minus the smallest number, which is 46-7?

    • @dminger1
      @dminger1  Před 3 lety

      The Range is the greatest minus the smallest. The mode is defined as the most frequently occurring value.

  • @RM-hf4hq
    @RM-hf4hq Před 7 lety +3

    this really helped - thanks!

  • @eleanormcn3962
    @eleanormcn3962 Před 5 lety +3

    Oh hunny. My heart goes out to you. I’m in year 10, have zero formal maths qualifications, and know that in a histogram, they y-axis is frequency DENSITY. That’s literally the entire point of a histogram. Please, don’t quit your day job.

    • @dminger1
      @dminger1  Před 5 lety +4

      I don’t plan on it. However, you are sadly mistaken if you think that there is only one type of histogram and no others. Here is some literature to help you with your qualifications. newonlinecourses.science.psu.edu/stat414/node/120/.

    • @heir_1757
      @heir_1757 Před 3 lety

      Imagine being this ignorant lmao

  • @arusri4182
    @arusri4182 Před 5 lety +2

    Isn’t the y axis frequency density

    • @dminger1
      @dminger1  Před 5 lety

      Only if you want a density histogram. There three types of histograms. The purpose of a histogram is mainly to show continuous data. The three types are a frequency histogram, a relative frequency histogram, and a density histogram. It depends on how you wish to represent the data.

  • @s1eepy173
    @s1eepy173 Před 2 lety +1

    thiss helps

  • @bogdanmocanu6600
    @bogdanmocanu6600 Před 4 lety +1

    Very helpful, thank you.

  • @lucys954
    @lucys954 Před 3 lety +1

    I feel like this could of been explained in half the time 🤔

  • @owais4836
    @owais4836 Před 3 lety

    How would u determine the size of an individual class.
    For example find the size of the 2nd class
    45-59 with a frequency of 30

    • @dminger1
      @dminger1  Před 3 lety

      If the second class has a data range of 45-59, what you do is subtract the two numbers 59-45= 14, however, class sizes must include all applicable numbers in the class so what we do is add 1 to the value so the second class has a class width of 15. Based on your question about size of the actual class the frequency of the individual class is just extra information in the problem intended to confuse you from the question at hand. On the other hand, if you meant that you have a total sample size of 30 data pieces that span from value in 45-59. Then that is something different.

    • @owais4836
      @owais4836 Před 3 lety

      @@dminger1 thanks for the help

  • @Uzma1110
    @Uzma1110 Před 5 lety +3

    thank you so much

  • @confirmyourehuman
    @confirmyourehuman Před 6 lety +1

    this helped me a lot thank you !!

  • @APPLEDITS
    @APPLEDITS Před rokem +2

    I like how your trying, but this make completely no sense.

  • @mariamtomamassoud8105
    @mariamtomamassoud8105 Před 4 lety +1

    THANK YOU......

  • @fragz4636
    @fragz4636 Před 5 lety

    This makes so much sense thanks

  • @0xC272
    @0xC272 Před 6 lety +2

    4:48 for the actual method.

    • @dminger1
      @dminger1  Před 6 lety +1

      Here is a link to a better video that has all the times associated with it. Also is more in depth explanation. czcams.com/video/-haVXyCHMSs/video.html. Thanks for watching

  • @chewysofa550
    @chewysofa550 Před 4 lety +2

    Thanks, overexplained but keep it up.

  • @joecurtis692
    @joecurtis692 Před 4 lety

    This actually helped a lot 👍

  • @Costco_Employee
    @Costco_Employee Před 2 lety

    Wait but that’s not a histogram, that’s a bar graph.

    • @dminger1
      @dminger1  Před 2 lety

      Yes and no,
      I know it’s not a common statistical histogram but there are different versions of histograms if you want the real deal histogram video I have one on my channel

  • @zachstar9788
    @zachstar9788 Před 7 lety +4

    this guy waffles

  • @arnster1154
    @arnster1154 Před 7 lety +3

    you are a god

  • @harikeshprajapati3629
    @harikeshprajapati3629 Před 2 lety +2

    Your teaching style is not understandable

  • @aliyahturner8981
    @aliyahturner8981 Před 7 lety

    Mean, median and mode are measures of center. The average is the mean (arithmatic mean)

  • @itsaoifexo2772
    @itsaoifexo2772 Před 7 lety +2

    2:3

  • @droppingdimes5544
    @droppingdimes5544 Před rokem +1

    W

  • @YOOOOOOOOOOOOOOOOOOOOOOOOOOOO

    You must love the sound of your own voice. You really are good at taking information that could be told in 1 minute and stretching into a pointless nine minute video.

    • @dminger1
      @dminger1  Před rokem

      I don’t but when I was teaching 6th graders, they needed more explanation as they didn’t have enough life experiences to understand topics. So video May just not be relevant to you. Hope you have a good day

    • @YOOOOOOOOOOOOOOOOOOOOOOOOOOOO
      @YOOOOOOOOOOOOOOOOOOOOOOOOOOOO Před rokem

      @@dminger1 SHIIIIT mate, now I feel like an arse. Sorry for being a dick. I was angry cause I needed a quick answer, shouldn't have taken it out on you. The explanation was good because I understood it after watching. cheers.

  • @harvcheema1559
    @harvcheema1559 Před 6 lety +1

    Really helpfull

  • @abeleiva4497
    @abeleiva4497 Před 7 lety

    Great video, thanks.

    • @dminger1
      @dminger1  Před 7 lety

      Chris X glad it was helpful. Thanks for watching

  • @tomoswalker9485
    @tomoswalker9485 Před 5 lety +3

    HISTAGRAMS DONT ALWAYS HAVE THE SAME CLASS WIDTH

    • @dminger1
      @dminger1  Před 5 lety +1

      So when I said this was a very basic intro video. That’s what I meant. I know that they do not. This is as a basic of a histogram as it gets

  • @konahbrownell2167
    @konahbrownell2167 Před 7 lety

    Thank you so much!

  • @tomblanden3504
    @tomblanden3504 Před 3 lety +1

    minger

  • @Maher_sza
    @Maher_sza Před 7 lety

    thanks

  • @chuckumartin1667
    @chuckumartin1667 Před 5 lety

    @odetteochs

  • @eyibiojeremy7232
    @eyibiojeremy7232 Před 8 měsíci

    Bro too much talking just get straight to the point from the beginning

  • @paperstarsinglassjars
    @paperstarsinglassjars Před 3 měsíci

    minging

  • @yoooo458
    @yoooo458 Před 4 lety

    A bit unnecessary to keep it this long. If you're talking about mean why are you talking about what the mode is?

    • @aces1608
      @aces1608 Před 4 lety +1

      Dude he only took 30 seconds just to explain what the mode was, be grateful he even mentioned it.

  • @arayanjand9152
    @arayanjand9152 Před 5 lety +3

    just get to the bloody point

  • @laurend4354
    @laurend4354 Před 6 lety +1

    That’s not the frequency

  • @labreynth
    @labreynth Před 6 lety +4

    Why is this video 9 minutes long? You're just talking on about nothing important

  • @sayedabdullahqutb8851
    @sayedabdullahqutb8851 Před 7 lety +4

    ever looked at your video, yourself?

  • @Tradingwithoneman
    @Tradingwithoneman Před 4 lety

    u r just talking plenty

    • @dminger1
      @dminger1  Před 4 lety

      Argeed

    • @aces1608
      @aces1608 Před 4 lety

      Sir, I believe you have misspelled Agreed. Are you proficient in spelling? jk jk lol

  • @rickypatel001
    @rickypatel001 Před 6 lety

    nice try but failure. i will subscribe because i feel sorry 4 u