These are from my 100 integrals part 2: These double integrals are from my 100 integrals part 2 video 👉 czcams.com/video/jQz1gQ24OHc/video.htmlsi=e0TNMkCmiHveTda2
what a coincidence, while i was watching part 2 of your 100 integrals, suddenly this video notified me right away. hahaha ty for this! would help for my exam
Can you make some videos explaining triple integral and calculus 3? I'm taking Engineering Mathematics 2 this semester and I started struggling 😅😅 Love your work tho, big fan I was following you for around 3 years at this point
Arctan (x) Tan = x (Recall TOA) Make a right triangle in which, x is the opposite, and 1 is the adjacent. There you will get the sin(x) which is opposite over hypotenuse
this was long ago so i hope you passed your exam but from what i know you can always change them if it's a smart decision, just draw your region and see under which functions x and y stand
generally you do this to find the volume under a plane given by f(x,y) in the bounds of the integral. Now if f(x,y)=1 your integral will give you the surface defined by the integral bounds. For example if you integrate over square bounds like {0
These are from my 100 integrals part 2: These double integrals are from my 100 integrals part 2 video 👉 czcams.com/video/jQz1gQ24OHc/video.htmlsi=e0TNMkCmiHveTda2
Thank you 😮😮😮
what a coincidence, while i was watching part 2 of your 100 integrals, suddenly this video notified me right away. hahaha ty for this! would help for my exam
he finally did it...
Can you make some videos explaining triple integral and calculus 3?
I'm taking Engineering Mathematics 2 this semester and I started struggling 😅😅
Love your work tho, big fan I was following you for around 3 years at this point
Thanks Dr🎉
thanks alot ....we need in triple intigral too😁😁
hey i dont understand why in 6:15 sin(tan^-1(x))= x/√ (1+x^2) ?
tan^-1(x) is arctanx or 1/tanx ?
Arctan (x)
Tan = x (Recall TOA)
Make a right triangle in which, x is the opposite, and 1 is the adjacent.
There you will get the sin(x) which is opposite over hypotenuse
on question Q89 i got 26/3, don't understand where the other 1/3 comes from
When doing the integral of sqrt(u)du, you get 2/3sqrt(u^3) due to the power rule, which you then multiple the outside 1/6 by to get to 1/9
i dont really understand why he could change dx and dy. What did it depend on?
Because sometimes you can not integrate in the initial statement
@@lilfelicia no i meant i didnt understand the explanation in how it works
it depends on Fubini's theorem
this was long ago so i hope you passed your exam but from what i know you can always change them if it's a smart decision, just draw your region and see under which functions x and y stand
Volume? Aren t double integrals for surface area?
generally you do this to find the volume under a plane given by f(x,y) in the bounds of the integral. Now if f(x,y)=1 your integral will give you the surface defined by the integral bounds. For example if you integrate over square bounds like {0
@@lightshadow2707 Thank you for your time. Extremely well explained. Now it makes sense of course. Thank you ❤️
Great job. Thank you. You looked a little bit tiree. Need some deserved rest ?
Thank you. These questions are from my “100 integrals part 2” video so I had already done 80 nonstop up to this point. 😆
Jacobian 😆
you need to work more on yourself first
We all do. I aim to improve everyday. You?