Solving Second Order Differential Equations
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- čas přidán 9. 02. 2021
- engineers.academy/level-5-hig...
This video continues from previous videos on solving first-order differential equations and introduces the second order differential equation. This video addresses how we can solve homogenous second order differential equations with three worked examples.
First Order Differential Equation Videos:
Part 1: • Solving First Order Di...
Part 2: • Solving First Order Di...
More Second Order Differential Equation Videos:
Example 1 - Linear Motion: • Second Order Different...
Example 2 - Mechanical System: • Second Order Different...
Example 3 - RLC Circuit: • Second Order Different...
Non Homogenous 2ODE: • Solving Non-Homogenous...
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I've spent like 2 hours on youtube trying to find a video to review this method of solving DE's. Its been 2 years since I've had DE. Thank you for pulling through
It's a brilliant method of explaining the DE especially in solving RLC Circuit Problems / Analysis. many thanks.
Wherever you are. May God bless you for this tutorial 🥺🙏🏼
This is really helpful honestly. Thank you
This is excellent, well explained!
Awesome stuff. Thank you!
I've been struggling to understand RLC circuits since I took differential equations 3-4 semesters ago. I didn't find any luck with my book, lecture, or other youtube videos. This video made me really understand what's going on. Thank you so much!
Glad it was helpful - there is a specific RLC example linked in the description also.
Excellently explained. Very clear.
Excellent teaching Sir
Great teaching
Very useful video and examples for exam preparation. Thank you!
excellent explanation
Thankyou
wow the best teaching ever
Excellent
🥰🥰
Thank you! I can now use this in solving RLC Circuit Problems / Analysis
Glad it is helpful - there is a specific RLC example here also czcams.com/video/w9Z4Ly98Lcw/video.html
God bless you 🙏🙏
Thank you so much
Thnku Sir🙌
Wonderful presentation
Very good video and very useful leading up to my exam. Ps I think it’s homogeneous not homogenous
My bad - I always thought the two words meant the same thing!
very useful video
Hi. For example 3, when you substituted the imaginary component of m in for Beta, why did you disregard the negative imaginary component? Surely you could sub in - sqrt(11)/2 and achieve a completely different but valid answer? (great video btw)
Its the magnitude of the imaginary component that is used as beta here in this particular formulation, ignoring sign.
Hello sir, in the 2nd example, how did you get the 9/4 and -9/4? Thank you!
By solving the two simultaneous equations to find A and B. See here: czcams.com/video/fftnk5tVMTg/video.html
What if the 2nd term is not given?
If you mean that there is no dy/dx term in the equation then you can still use the auxiliary eqn but the value of b would be zero.
Thank you so much