16 - Kirchhoff's Current and Voltage Law (Concept and Solved Examples)

In this video, Kirchhoff's current and voltage laws are explained. Kcl states that in a closed loop of an electrical network the sum of currents leaving a junction should be equal to the sum of currents entering the junction. Kvl on the other hand states that in a closed loop of an electrical network the sum of voltages dropped across the resistive elements should be equal to the source or applied voltage.
Solved Examples in there.
Link to other videos
Voltage Division
• 10a - Voltage Divisio...
Current Division 1 - How to divide current in a parallel circuit
• 11 - Current Division ...
Current Division 2 - More Examples on How to divide current in a parallel circuit
• 12 - Current Division ...
You can checkkout my Network Theorems playlist
• APPLIED ELECTRICITY
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[@charlestoneoyoo]

Damn...you are goated..I just understood this thing or the first time in 2years. Thank you so much

[@SkanCityAcademy_SirJohn]

You are most welcome

[@saxkreativehub]

This is the best Kirchhoff's law explanation I have ever received, thank you so much!

[@SkanCityAcademy_SirJohn]

Thanks so much

[@HanafiMdoka]

This is the best clear explanation I've ever had 😢God bless you 🙏

[@SkanCityAcademy_SirJohn]

Amen, and thanks so much

[@arnavhegde183]

I thank this man for teaching me something both my School and tution failed to do so

[@SkanCityAcademy_SirJohn]

Aww thanks so much

[@emmanuelquarshie-yx8gz]

you nailed it bro! Thank you for this video

[@SkanCityAcademy_SirJohn]

You are most welcome.

[@ntukwasi]

This was so helpful! There was a part of these concepts that had confused me in the past, but you cleared it up so easily! Thank you!

[@SkanCityAcademy_SirJohn]

You are most welcome Agu

[@megangibbs2627]

Thank you so much! This video was so helpful.

[@SkanCityAcademy_SirJohn]

You are most welcome

[@_WAYZZZFX]

Your explanations are so clear

[@SkanCityAcademy_SirJohn]

thanks so much

[@user-yg8kd6wg5w]

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[@SkanCityAcademy_SirJohn]

Thank you very much

[@LeoPetala-iv7bw]

Thank you very helpful

[@SkanCityAcademy_SirJohn]

You are most welcome

[@AlobwedeNehemiah-ff4mc]

Thanks for explaining

[@SkanCityAcademy_SirJohn]

You're welcome, thanks for watching

[@NontobekoNgidi-qb3eo]

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[@SkanCityAcademy_SirJohn]

Aww nice feeling for you. I'm really happy for you❤️🎉🎉😂😂😂
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[@FruHoseaTse]

thanks very much for your help today

[@SkanCityAcademy_SirJohn]

You are most welcome

[@Paganini-Liszt]

I am going for Electrical Engineering, good luck to you all!

[@SkanCityAcademy_SirJohn]

Good luck

[@Paganini-Liszt]

ty! really helpful video

[@SkanCityAcademy_SirJohn]

@Paganini-Liszt thanks so much

[@StephenBuah]

Please can you teach how to identify if a current is in series or parallel

[@osmankoroma6495]

Perfect 🥰

[@SkanCityAcademy_SirJohn]

Thanks so much Osman

[@tbkzinventor6371]

Nice vid helpful

[@SkanCityAcademy_SirJohn]

Thanks so so much

[@emmanuelchidera574]

I am little bit confused why there was a negative voltage drop between the I¹ & I²

[@SkanCityAcademy_SirJohn]

I don't get your question. Can you come back again

[@TobilobaAkintujoye]

Your loop 1,why don't you have a negative sign for 2I and negative sign for 8(I-I1),since current flows from positive to negative

[@SkanCityAcademy_SirJohn]

No please, it's supposed to be +2I like you see in the video because we take the conventional flow which is same direction as current I

[@tirimisiyuwaliyi107]

But what if we have another resistance of 5ohms parallel to 2ohms ......how to do that

[@SkanCityAcademy_SirJohn]

Well it changes the nature of the question. You can either use resistance combination or current division at the effected area.

[@frownsmiley]

niceee

[@SkanCityAcademy_SirJohn]

Thank you very much.

[@syafiqsalim3457]

brother the equation 2 why all devide by 8?

[@SkanCityAcademy_SirJohn]

Because we want to make I the subject

[@syafiqsalim3457]

@@SkanCityAcademy_SirJohn can we devide to any number?

[@SkanCityAcademy_SirJohn]

You can, but to make I stand alone you divide by the coefficient of I which is 8

[@emmanuelchidera574]

Yh
I'm confused there too

[@hatdogxpandesal8168]

bro u are wrong
g

[@SkanCityAcademy_SirJohn]

Can you please specify the time and why you think I'm wrong?