Equations of Motion (Physics)
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- čas přidán 5. 04. 2018
- Equations of Motion Made Easy! Newton's Equations of Motion also known as SUVAT equations are explained in detail here. We have compared the upward and downward motion.
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Thank s
Sir can I contact you
thank you sir very well explained in easy manner
ANSWER OF THE FIRST QUESTION EXPLANATION :
1. u {initial velocity} = 0
a {acceleration} = 2 m/s square
t {time} = 5 s
v {final velocity} = ?
So here we have to find the final velocity.
So we take the first equation.
v = u + at
= 0 + 2 x 5
= 10 m/s
So the final velocity is 10 m/s
So the speed or velocity of the car after 5 s is 10 m/s
Please like if helpful...
Can you send 2 and 3 question answer also
Did u got the ans
Can I get 2. I'm confused
We need teachers like this in school
Yes
@Ashwanth A S What do you mean ??
Absolutely....right
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Yeah
Anyone 2024?
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Yes me , class 9th
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Legends are watching this 1 day before exam
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Haha I am
Me not
@@tanishqdokewar2233 oh
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my understanding just went from not having a clue what any of this meant, to being able to get it right most of the time. Great video.
Happy to hear that video was helpful :) Do check out more videos at www.manochaacademy.com
Q1 - According to first equation of motion
v = u + at
Here ,
v = ?
u = 0 m/s
a = -2m/s square
t = 5 s
Put the value in equations
v = 0 m/s + (2 m/s square * 5s)
v = 0 m/s + 10 m/s
Hence speed of the car is 10 m/s.
Q2 - According to third equation of motion
2as = v square - u square
Here ,
s = 10 m
v = 0 m/s
u = 72 km/h or 20 m/s
Put the values in the equation
2*a*10 m = 0 square - 20 square
20 m * a = 0 - 400 m/s square
a = -400 m/s square / 20 m
a = -20 m/s square
Q3 - According to the third equation of motion
2as = v square - u square
Here ,
a = (-10 m/s square) because the acceleration due to gravity is in upward direction
v = 0 m/s
u = 10 m/s
Put the values in the equation
2 * (-10 m/s square) * s = 0 square - 10 square
-20 m/s square * s = -100 m/s
s = -100 m/s / - 20 m/s square
s = 5 m
2. According to the first equation of motion
v = u + at
Here ,
v = 0 m/s
u = 10 m/s
a = -10 m /s square
t = ?
Put the values in the equation
0 = 10 m/s + (-10 m/s square * t )
10 m/s square * t = 10 m/s
t = 10 m/s / 10 m/s square
t = 1s
As the time taken by the ball to cover 5m distance is 1 sec so it will take 1+1 sec = 2 sec to reach the thrower
I too
Got same answer too
You're asked to find the speed!
Why did you use 20m/s when it isn't in the question above
Please explain
@@serifatayotunde8385 when you convert 72 km/h to m/s , the answer is 20 m/s.. m/s is the SI unit so we can't use km/h
1. v = u + at = 0 + 2*5 = 10 m/s
2. v2 = u2 + 2as --> 0 = 400 + 20a
a = -400/20 = -20 m/s2
3. t = u/g = 1 s (Single sided journey)
Total time = 2t = 2 s
s = ut + at2/2 = 10 - 5 = 5 m
Aayein
I have a physic test tomorrow about this topic😭😭😭
All the best for your Physics test!! You can also watch this related video on Motion Sums and Graphs if it is helpful for your test: czcams.com/video/VEfccaYUFZY/video.html
Me tooooo
I have physics and chemistry
Same 😞
same😕
Number 2
Using V2=U2+2as
Convert 72km/h to m/s
=72x1000/60x60= 20m/s
V=0
U=20m/s
S=10
a=?
0^2=(20)^2+2ax10
0=400+20a
20a=-400
a=-400/20
a=-20m/s^2
I hope Im able to help those that were so confused at first like me
Q1) u= 0
a=2
t=5
v=?
(1)v=u+at= 0+(2 x 5)= 10m/s
Q2) a=?, u=20 m/s(72 km/hr- m/s), v=0, s=10
(3) s= v^2- u^2/ 2a
10= 0^2 - 20^2/ 2x (a)
a=-20^2/ 2x 10
a= -400/200
a= -4m/s
Q3) Use equation v=u +at to find time= 1/20
then use equation s=ut+1/2at^2= 1/4 or 0.25 m
2nd question 2nd part
-2m/s
is the answer....
thanks ,your answers were quite helpful..
@@pankajsood9089 -400/20=-20m/s² is the ans
but he has written -400/200,according to that the answer is -2..
\
Second question's answer is -20m/s2
Your explanation is more than enough! Your videos should be tagged by CZcams for students 👏👏
Number 2
Using V2=U2+2as
Convert 72km/h to m/s
=72x1000/60x60= 20m/s
V=0
U=20m/s
S=10
a=?
0^2=(20)^2+2ax10
0=400+20a
20a=-400
a=-400/20
a=-20m/s^2
I hope Im able to help those that were so confused at first like me 🙏
Superb Sir... I am seeing this video in 2020 again... Salute to u
Thanks for watching again
@@ManochaAcademy Welcome sir
Q.1) Given : initial velocity = 0 m/s, acceleration = 2 m/s^2, time = 5 s. To Find : speed of the car. To find the speed of the car we can apply the 1st equation of motion i.e v = u + at, v = 0 + 2*5, v = 0 + 10, v = 10 m/s. Therefore the speed of the car after 5 s is 10 m/s.
Q.2) Given : Initial velocity = 72 km/hr. Now we have to convert 72 km/hr in m/s i.e 72 * 5/18 = 20 m/s. displacement = 10 m. final velocity = 0 m/s. To find : retardation of the brakes. Now to find the retardation of the brakes we can apply the 3rd equation of motion i.e v^2 - u^2 = 2as, (0)^2 - (20)^2 = 2a(10), 0 - 400 = 20a, - 400 = 20a, - 400/20 = a, - 20 m/s^2 = a. Therefore the retardation of the brakes is - 20 m/s^2.
Q.3) Given : Initial velocity = 10 m/s, acceleration due to gravity = - 10 m/s^2, Final velocity = 0 m/s. To find : height & time taken. Now to find the height reached by the ball we can apply the third equation of motion i.e v^2 - u^2 = 2as, (0)^2 - (10)^2 = 2(-10)s, 0 -100 = -20s, -100/-20 = s, 5 m = s. Therefore the height reached by the ball is 5 m. Now to find the time taken to come back to the thrower we can apply 1st equation of motion i.e v = u + at, 0 = 10 + (-10)t, -10 = -10t, -10/-10 = t, 1 sec = t. Now the time taken for the ball to reach the height of 5 m was 1 sec. So, the time taken for the ball to reach to the person who throwed the ball will be 2 seconds.
Sir I have solved the top three questions kindly tell me the answers are right or wrong.
Thank you so much I got confused
@@sk14_yt44 You are Welcome.
Hey! What made you use the 3rd equation? Especially since we were finding retardation. What does v2 mean? Final Velocity squared?
@@jaronrallos3844 I used 3rd equation of motion because due to that formula we can find the answer in fraction of sec.
Op bhai 💗
1. final velocity (v)= 10m/s
2. acceleration (a) = -20m/s^2
3. i) time (t)= 1s
ii) displacement (s)= 5m
Won't the time be 2 seconds? The time it uses to reach maximum height is the same time it will use to travel back from maximum height to the thrower, right?
@@kimsimby9615 yes it will be 2s
Sir you are doing the best you can. Where have you been in all my school life? Physics is now a piece of cake for me. Thank you sir! Thank you Manocha Academy.
Thank oh sir for such a good explanation
1)10m/s
2)-2m/s^2
3)h=5m
T=2s
Hlo sis how did you get these answers
The ball when at the top, it is in motion exactly as much as it is in motion, when it is at the bottom. That is because the ball is always in motion within space-time. All you can do is change its direction of travel of the ball within the 4D environment known as space-time.
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Really, no physics channel teaches as practically as you do. I understood well😊
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True
Respected Sir u r a great teacher and I m ur fan. How I van attend ur Series/Chapter vise lectures on CZcams. hope for swift response.
Thanks a lot :) Do check out more videos at www.manochaacademy.com
Please give me the date of live class on equation of motion
Super sir.......it is helping even for the students who are little slow.... Very well explained....🙏🙏🙏👍👍👍👍
Aap jaise logo ki bahut jaruart hai sir hum students ko.
Yha to sab bas ratta marne me mahir bnate hai jo mujhse nahi hota.
Pahli baar lga ki mai sahi jagah par time investment kr rha hu.
U r The great Teacher.......
Sir please make one video to solve the equation of motion
Thanku sir for clear my all doubts of this topic .
Most welcome
1(10)
2(-20)
3a(5)
b(1)
Sir i m extremly requesting you to make a video on thermal conductivity and if possible so plz cover the whole lesson of thermodynamics
Mind blowing Sir u teach In a very polite manner
Thanks and welcome
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This lecture helps so many students like me every day..thnku so much for making this..
It's my pleasure
Sir
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I have subscribed to you since 5 years and i have been a very big fan of you. I wish you would have millions of views and subscribers
Thank you sir
Crystal clear explanation sir! An apt example of experiential learning.
I am a chemistry teacher but physics has a special place in my life.
Ngl this is very helpful as I am starting my grade 11 this year,thank you very much
You are doing a great job providing all the lectures for free. I really appreciate that. Your content and video quality are really good. Thank you, you just gained a subscriber.
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Best teacher clear concept 👌🙌 and in less time
Thanks
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Not just Better than byjus , vedantu , topper .. but also effective and hardworking ...
Glad to hear that.
HOW TO FIND THE EXACT EXACT EXACT CIRCUMFERENCE OF CIRCLE.
Procedure
Step 1. Draw a square, 2 diagonals and inscribe a circle in the square. Thereby side and diameter will be the same Step 2 : Subtract 2 diagonals from the perimeter of square Step3. Divide step2 with 8 Step4. Add 3 times of the side. to Step 3
At the end we get the EXACT circumference of the inscribed circle
Hello everyone. I am currently doing 9th term 2 examinations. even though this chapter isn't there in my term 2 examination, i had to study it as these formulas were to be used once again. so plz pay attention to this motion chapter.
In question no. 2 and 3 time is not given so, we can Put Time= Distance/Speed instead of time.
And both distance and speed is given in the questions.
Really helpful.., teachers like you is a really great boon for every student
You are a born teacher. Your students must be happy and lucky to have you as their teacher just like us over here on CZcams.
Glad you liked. Keep watching
Respected Sir
Physics and math are the hardest subjects for me. This was the video I was looking for. THANK YOU SO MUCH SIR.
I request you to make more videos on physics, not only for me but for all the viewers of your wonderful teaching!!!👍😀
Expert teacher
Hats off to you sir 👌🏻🙏🏻
Sir you are really the best teacher
a.) 10 m per second
b.) 5 m per second per second
c.) time to get to top = 1 sec
Time taken to come back to the thrower= 2 seconds.
Really appreciate your efforts Sir. Thanks.
Thanks a lot :) 1st and 3rd answers (a and c) are correct!! Try the 2nd question again, retardation should be 20 m/s2.
3rd Question asks to calculate maximum height also.
Let me know if you have any doubts!
I got the second one correct sir
I was searching the ans of 2 thank you sir '
This teacher like gold
Hai
Yes
Yes
Very good teacher if he is in my school I will get physics full marks
Not gold diamonds
Thank you sir for do this video
I understand about equations of motion very much
It's really good sir .. Who are study persons they watch this video. Really it's good guys watch this .
Sir I easily solved the 1st and 3rd Question using the Equations . But I was unable to do the 2nd one , could you explain it ? Also I have a doubt in how to explain the equations of motion graphically ? Please explain sir , you are explaining very well , it is quite helpful for me .
Regards ,
Abhilash Kar
IX
i got -20 m/s^2
Sir you are pro at teaching appreciate your teaching style
Thanks and welcome
Lack of quality of education in offline made a graduate to reach here and u proved my destination is perfect one to learn physics concepts thanks alot
Yaaa great to see the motion from the ball, initial velocity, from the top and the bottom . I see carefully from the speed of the motion of the ball of the velocity of the ball around of it.
Q1) v=u+at
u=0, a=2m/s ,t=5s
v=o+2×5=10m/s
Correct!
the video is so good like everything but please try to make a short video cuz there are student like me who are trying to cover whole syllabus 2 days before my exams.😅
Someone like me trying to cover up the whole syllabus 1 week before the exam 😂😂💔. Jamb no be my mate
Awesome understanding through practical sir.
Thanks alot sir,you really help me in understanding motion,God bless you sir🙏🙏
sir answers
1.10m/s
2.A=20metre/sec square
3.distance= 5m,time=1sec
please show me your workings
Very good explanation sir
Sir I felt you are best in explaining topics about physics, I clearly understand your teaching sir, thank you sir🙏
Thankyou....I'm starting my studied for new career ...focusing on physics...this video was great simplifies things nicely a great introduction
Please could you make a video solving these equations.
Sir, Could you please upload the answers in *your comment description* cuz It would be extra useful, since its hard to look for the answers when ever in doubt ;)
yes
I was searching for these equations that I can understand with exmaples. It was the only video I found best!
Thank you sir i understood this consept well and is the best educational you tube channel
Thank you very much Sir. Nicely explained. Is there a video for graphical representation of linear motion? Also it would be good if u could also add videos on numericals?
1) V=10m/s
2)a=20m/s²
3)maximum height is 5metets
Time taken back to thrower is 2 seconds
Thanks for this you are changing the world by changing future of youths❤️
All of the concept in this video I understand very well. Thank you so much sir
Teacher my answer are;
Qn 1=10m/s
Qn2,retardation =20m/s^2
Qn3;max height=5m
Total time=2s
Please teacher confirm if my solutions are correct. Thanks for all the videos, really helpful.
this is what i got
Pls how did you solve the Q2?
You teach with good technic.
U practically prove for us....tq u very much...🙏
you made my soul satisfied ...the way u give real life examples and clear the concepts of physics is really admirable .the best ever teacher in physics , will be waiting for many more videos in future. Thank you
It's my pleasure
My test is tomorrow and you've explained this way better than my teacher. A big Thank you all the way from Zambia.
I will let you know if I pass
You've failed as you didn't inform😂??
Q1: Ans: Speed of the car after 5s is 10 m/s
Q2: Ans: -20 m/s2
Q3: Ans: Maximum height reached by the ball is 5 m
Time taken to come back to the thrower is 2 sec
Excellent!! All your answers are correct :)
Can u explain the answer for third question 🤔
How s =5m????
@@shreevigneswaran2112
U=10m/s
S=?
a= -10m/s^2
t=?
Here we use
V^2=U^2 +2as
0=(10)^2+2×-10 ×s
0=100 -20s
20s=100
S=100/20
S=5m
I hope helpful 👍
Really wonderful guide..
Never heard such a wonderful class yet based on this lesson ❤️
1. Ans=10m/s
2. Retardation of the bus= minus acceleration= -20m/s²
3. Maximum height= -5m
Time taken to reach maximum height=1s and to come back to the thrower =1s. Total time for the motion =2s
Sir your method is awesome...that's how I wanted to learn
Glad to hear that
Wish I had teachers like you
Sir,You are real hero for student .
explanation of the 2nd question: Given:
final velocity (v) = 0 (since the vehicle comes to rest)
initial velocity (u) = 72 km/h => 72 x 5/18 = 20 m/s
displacement = 10 m
to find retardation (negative acceleration),
v² = u² + 2as
=>(0)² = (20)² + 2(a x 10)
=> 0 = 400 + 2 x 10a
=> 0 = 400 + 20a
=> 20a = -400
=> a = -400/20
=> a = -20
therefore the acceleration is -20 m/s
a=-20m/s2
yh but they are asking retardation which is negative acceleration, which is again 20 m/s
Sorry to ask I'm just confuse I know u =72 so how did that 72*5/18 got in please
Amazing physics tutorials!
I'm watching this in 2021 and i hv my exam tom this vid was really helpfull much better than any other video i could find on this topic. Your explanation is really good sir i just went from clueless to being able to do most of the sums. Thqu so much sir pls keep uploading gr8 videos
Sir you are great tomorrow I have a science periodic test in which motion is coming I have not studied at all and when I see you video I shocked and now I am ready to give tomorrow test thanks a lot
Happy to hear that you liked the video :) All the best for your test!!
Solution for Question 1:
Given,
Initial Velocity (u)= 0
Acceleration (a) = 2m/s²
Time (t) = 5 seconds
Final Velocity (v) = ?
We know, v = u + at
v = 0 + (2m/s²×5s)
v = 10m/s
Thus, the speed of the car after 5 seconds is 10m/s.
Please explain why it is not 10m/s^2 ??
@@j.os_h Here, we need to find Final Velocity. Note that Final Velocity has the same sign as speed (m/s). Thus, we write it as 10m/s.
We write the magnitude of Accleration as m/s². Therefore, if you write any value as m/s², then the value you are referring is acceleration. Example, 10m/s².
Dear Sir,
Can you please explain your audience the meaning of the equations of motion. Like, why we took out the half of acceleration times displacement and etc. This would be very helpful if you will make a separate video on this topic.
Regards,
Myth
Thank you sir. Understood the concept. Also the video was simple and practical. Once again a hearty thanks sir.
ALL CONCEPTS CLEAR 😀😀 YOU GOT MILLIONS OF VIEWS INSHAALLAH☺☺
Thank u so much sir for this amazing session....things are crystal clear
Answers to the H.W questions 15:35 are :-
1.)10m/s
2.)-20m/s^2
3.)s=5m and t=1s
Bhot hard
This video was so helpful, please help with projectile motion.
thanks sir as i recieve a physics teacher who teach with principel and concept.
Q1 answer is 10m/s
Q2 answer is-20m/s²
Q3 answers are 1sec and 5m
Sir from where are you I scored 70 out of 70 in my exams because of you only
what a wonderful teacher he is!
I have checked out many videos to understand these concept 🙂but this is the best video ever 👍thanx
you are such an amazing educator thank you.....
So nice of you
Does it basically mean that whatever information is given to us after the = sign, we have to check that whether all the info. given in the question is the value of everything after the = sign in every equation?
This is the best video for explaining for people who have exams in 12 hours
This is one of the best teachers
In the world he takes time on his explanations, examples and he puts the examples into real life experience which makes it easier for the student watching to learn and retain for a very long time🙌
I think this teacher should be awarded.
Best teacher ever!!