Vigenere Cipher 🔥🔥

This video is about Vigenere Cipher in Cryptography and system security or Network Security in Hindi.
In this lesson, I teach:
* Vigenere Cipher Encryption
* Vigenere Cipher in Hindi
Purchase notes right now,
more details below:
perfectcomputerengineer.teach...
Cryptography and System Security Playlist:
• Playlist to Cryptograp...
System Programming & Compiler Construction Playlist:
• Playlist to System Pro...
*Mobile Computing Playlist:
• Playlist to Mobile Com...
*Digital Signal & Image Processing Playlist:
• Digital Signal & Image...
* Artificial Intelligence:
• Playlist to Artificial...
*Gears used for this CZcams Channel:
linktr.ee/perfectcomputerengi...
*Let's connect:
Instagram: / planetojas

[@mohammadikramm]

If P+K < 26 then key will remain same and if P+K > 26 then key = P+K - 26.

[@afaqdey]

U made the MOD work so easy, don't even need a calculator :)

[@Jaa_Puchhke_Aa]

Not >26, it's >25*
Because we start assigning "a"=0
If it's 26, you don't need to calculate.. the answer is simply "a"

[@saiyanwarrior3047]

Love u bro u made a new formula love u

[@amanshaikhvlogs]

Thanks A LOT FOR THIS VIDEO, HELPFUL, EXAM IN 10 DAYS

[@kalyani5964]

Best explanation ever 🎉

[@vktultrainstinct]

The answer to the question is
ZICVTWQNGRZGVTW

[@kavitaprajapati659]

Correct

[@Dharmikside73]

Wrong

[@BHAJANKHATABHAKTI]

0:42

[@AliHamza-qb8zr]

Correct answer

[@AshishKoli-ub2pz]

Thank you brother ❤

[@staranonymous7656]

Thank you sir ❤

[@abusufyan2208]

😊😊

[@imrahill7]

Thank you

[@hitesh6459]

Thanks ❤

[@mdfajlarabby3942]

thank you

[@AbhishekSharma-hd4ds]

best ever

[@misdaqmehdi4785]

Perfect and too the point love from PK ❤

[@jainabdinmoenshaik2530]

provide link for the watch you worn!!

[@gautamkumarverma2929]

Vernam and vigenere cipher techniques me kya differences hai

[@dhartiodedara8023]

This js vernam cipher (one time pad )

[@KHURRAMSHAHZAD-jl5qi]

voice is just like Amir Khan.

[@Gearshift_innovator]

ans to correct hai lekin aolve krne me aaadha ghnta lag gyaaaa

[@subrajitbhowmik706]

mera kaal exam hain 😅🤣

[@chjibrann]

what if key's length greater than the plain text's length ?

[@manishplayz6687]

Double the plain text until it matches the length of key but most of time key is shorter the pt

[@juvekarmaitreya1833]

ZICVTWQNGRZGVTW Answer to HW question.

[@munirakbar2090]

Before last TW there is "Y" also

[@ASHISHKUMAR-de9jn]

Home work question solution:
ZICVTWQNYRZGVTW

[@amanshah9414]

Cipher : z I c g x l d w f s x t I m y
sir this correcet ???

[@gamesgotppal]

nope

[@sumangole3594]

import string
def alphabet_table():
alphabets_ = {}
alphabets = string.ascii_lowercase
for i, alphabet in zip(range(26), alphabets):
alphabets_[alphabet] = i
return alphabets_
def key_table():
keys = {}
alphabets = string.ascii_lowercase
for i, alphabet in zip(range(26), alphabets):
keys[i] = alphabet
return keys
def get_keys_for_alphabets(text):
return [alphabet_table()[char] for char in text]
def vigenere_cipher(text, key):
len_of_text = len(text)
len_of_key = len(key)
if len_of_text > len_of_key:
desired_length = len_of_text - len_of_key
padded_key = (key * ((desired_length // len(key)) + 1))[:desired_length]
new_key = key + padded_key
cipher_keys_list = get_keys_for_alphabets(new_key)
else:
cipher_keys_list = get_keys_for_alphabets(key)
plain_list = get_keys_for_alphabets(text)
cipher_text_list = [(p + k) % 26 for (p, k) in zip(plain_list, cipher_keys_list)]
cipher_chars = [key_table()[val] for val in cipher_text_list]
cipher_text = "".join(cipher_chars)
return cipher_text
if __name__ == "__main__":
print(vigenere_cipher("wearediscovered", "deceptive"))

[@theoctaveclub]

Z I C O T W W N G R Z H V T W
hope i am right

[@omegajain3570]

no you are not

[@omegajain3570]

Z I C V T W Q N G R Z G V T W
This is the correct answer bro

[@vinayplays]

@@omegajain3570 yes bro

[@munirakbar2090]

Z I C V T W Q N G R Z G V Y T W