The Product of Two Nonzero Matrices can be the Zero Matrix!
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- čas přidán 16. 09. 2021
- We find a matrix B that satisfies AB=0 where A = [[1, 2][3, 6]].
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Nice! Thank you for all these awesome videos. :)
Amazing explanation ❤
Thank you very much❤
Thank you so much!! You just saved my butt haha
Amazing video. Just have one question... Let's say we have A and need to find B such that A B = 0. Is there a name for matrix B?
I am from India. Your explanation is great 👍😊. Love from india ❤️❤️❤️❤️❤️❤️🙏
But how to find when we have 3×3 matrix and given that AB=BA=O (null matrix)?
Dr weselcouch,ive been wondering a question,are there any non0 functions such that the derivitive of that function is the laplace transform of the same function?
Interesting!
did i make a mistake
also i did respond by saying x^(-b)-1/(b-1)!*x^(b) right bcos that is the one
So if you are asked if the ring of matrices 2x2 is integral domain,you can answer no and give this example
That's right!
Can a matrix of order 3 be found such that when it is multiplied with another sqare matrix of the same order the product is a zero matrix?
Yes this works for higher dimensions as well.
Awesome
How to find such a matrix when your original matrix A is very large for say 110 by 110 matrix?
Good question. I would find the null space A and then take 110 different elements of the null space to be the columns of the new matrix.
@@DrWeselcouch Thank you so much. Now I have got a generic idea. It would be more helpful if you make a video explaining about details of null space.
Everything makes sense to me except the end. Did you just randomly pick 1? Why did you pick 1?
+1 i didnt get what he did at the end
@@nessrinenebli6994 Yeah he just chose 1 for the sake of simplicity since he can define his own variables from what I understand
You didn't point out that is true only because in matrix A, the 2nd row is twice the first.
It can only happen if the determinant of the matrix is 0.
Well couch???
Should both be singular or only one needs to be?
If A is nonsingular, then multiply both sides of the equation on the left by A^-1 showing B=0. Similarly if B is nonsingular.
Here's one vote in favor of keeping your new catchphrase.
Lol I like it!
??? I don't understand
It confusing