Continuity of Multivariable Functions

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  • čas přidán 6. 04. 2021
  • Welcome to my video series on Multivariable Differential Calculus. You can access the full playlist here:
    • Multivariable Differen...
    Videos by Zack Cramer, University of Waterloo. Textbook reference: Calculus: Early Transcendentals by Jon Rogawski, Colin Adams, and Robert Franzosa

Komentáře • 22

  • @sunraiii
    @sunraiii Před rokem +1

    Great video, and the trick at the end, transforming cartesian to polar coordinates to have one less variable to worry about and approach (0,0) “from all directions”, is really cool!

  • @MrCEO-jw1vm
    @MrCEO-jw1vm Před 2 měsíci

    really good explanation! thanks

  • @m.varunreddy7365
    @m.varunreddy7365 Před 2 lety +1

    Beautiful video, loved the visuals(graphs,3d), they help me understand faster... thank you suur!

  • @reijo6079
    @reijo6079 Před rokem

    Thank you so much, this really made helped understand how to solve basically any kind of problem like this and also how to make functions continuous in certain points!

  • @Stefabro
    @Stefabro Před 2 lety

    you're really good at explaining, thank you for all your help!

  • @danieljulian4676
    @danieljulian4676 Před rokem

    Nice presentation. First commendation is the figure at the beginning that shows a discontinuity in a surface over the domain R^2, which really brings home the bivalent situation at the discontinuity. You cover the topic (which is a standard one) and include all the usual points, including the transformation to polar coordinates. When you mention applying L'Hôpital's rule, valid on domain R, the series expansion of the function is (at least) implied, and this is also valid in domains beyond R. With the function you chose, the linear term is sufficient to show the limit exists, unless I'm forgetting something important.

  • @MiguelSantos-lu8uj
    @MiguelSantos-lu8uj Před 2 lety

    Great video! Very underated channel with amazing quality. Love from Portugal

    • @mathemation
      @mathemation  Před 2 lety +1

      Thank you, Miguel! So glad you have been enjoying this content :)

  • @user-is9os1th3z
    @user-is9os1th3z Před rokem

    Very helpful video with a very good explanation thank you so much

  • @lav6978
    @lav6978 Před 2 lety +1

    Arigato gozaimuch for the wonderful explanations

  • @dzdeparsio4676
    @dzdeparsio4676 Před 2 lety

    Thank you so much

  • @abdelrahmanabdelrahman8149

    you are so good

  • @mwilamwamba1787
    @mwilamwamba1787 Před 10 měsíci

    Thank you🎉

  • @satarnaghizadeh6623
    @satarnaghizadeh6623 Před 8 měsíci

    Awesome ❤

  • @ijustwanttoseealiadabbing2270

    love you

  • @matrixtrace
    @matrixtrace Před 2 lety +2

    Last example: would it be legal to make a substitution z=x^2+y^2, without transforming to polar coordinates?

    • @mathemation
      @mathemation  Před 2 lety +1

      Yes, that's fine. This works because (x,y)->(0,0) if and only if x^2+y^2 -> 0. Effectively, this is the same as transforming to polar coordinates.

  • @isaacmarcelino_
    @isaacmarcelino_ Před rokem

    How do we know the best paths to take?

  • @rogersowden2369
    @rogersowden2369 Před 2 lety

    Hey i checked your video before this but I couldn't see anything about x^2 + y^2 = p^2? where do I find these cartesian to polar conversions?

    • @mathemation
      @mathemation  Před 2 lety +2

      The conversion between Cartesian and polar coordinates are discussed here: czcams.com/video/_MXTd_ZUKFg/video.html

    • @rogersowden2369
      @rogersowden2369 Před 2 lety +1

      @@mathemation Thanks for the quick reply! You're awesome! Subbed

  • @shams8917
    @shams8917 Před 2 lety

    💛