so, the original matrix has five columns, and the general solution has one particular solution and three null space solutions for a total of four columns in the "solution matrix". i thought that the number of columns in the general solution was supposed to be the same as the number of columns in the original matrix. is this rank nullify theorem?
Thanks Pavel ...I was starting fresh with this vid and hadn't got up to speed ...It makes sense to me now [I forgot each null space alpha/beta/etc needs to sum to zero all rows in the matrix] Apologies for not deleting the question and many thanks for this excellent course. [I did lose my way in a later vid :) ...but I probably just need to look over some earlier vids again]
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Where can I get a copy of the matrix program used in ths demo.
Scientific Workplace
so, the original matrix has five columns, and the general solution has one particular solution and three null space solutions for a total of four columns in the "solution matrix". i thought that the number of columns in the general solution was supposed to be the same as the number of columns in the original matrix.
is this rank nullify theorem?
Terry Price You can decompose the particular solution into two column vectors.
Someone remind me why we use a multiple of 1 of the matrix zeros in the null space? Why not use a 0 multiple?
Which spot in the video are you referring to?
Thanks Pavel ...I was starting fresh with this vid and hadn't got up to speed ...It makes sense to me now [I forgot each null space alpha/beta/etc needs to sum to zero all rows in the matrix] Apologies for not deleting the question and many thanks for this excellent course. [I did lose my way in a later vid :) ...but I probably just need to look over some earlier vids again]
Thanks! I think there's a gap right around the topic of the null space that confuses everyone. I'll try to fix it soon!