Connected Particles - Force on a pulley | ExamSolutions
Vložit
- čas přidán 30. 05. 2016
- Here you will be shown how to calculate the force on a pulley exerted by a light inextensible string connected to two particles.
See more:
Playlist at: • Connected Particles
EXAMSOLUTIONS MATHS INDEX at www.examsolutions.net/maths where you will have access to all playlists covering pure maths, statistics and mechanics.
CZcams CHANNEL at / examsolutions
/ examsolutions.net
NEW INSTAGRAM: / posts
TWITTER: / examsolutions
THE BEST THANK YOU: www.examsolutions.net/donation/
I feel like i get M1 completely, then i do an exam and they throw a random ass question in for like 13 marks and im just like 'well fuck it'
This is me all the fucking time with mechanics. I mean I feel like I have all the knowledge on mechanics but nopeeee not gonna happen
LEGEND!! GOD BLESS YOU DUDE
Thank you for such a clear explanation.
can you do more of these videos for m1. Moments, lift etc....
Great video! Could we get some more mechanics this week as the M1 edexcel exam is on the 8th of June. Solutions to last year's paper would be greatly appreciated.
I am in 11class 2023 your comment is 7yr old too long time 😮😮
haha damn@@Saloni570
How would you find theta for the third example?
You will generally be given the angle of the inclined plane. So if the incline is 40 degrees, the angle at the top by the pulley would be 50 degrees. (40+50+90=180). So theta would now be 50/2 = 25 degrees. Hope that helps?
ExamSolutions Yes, perfect. Thank you!
Yes
Could anyone pls explain why on the ends of the pulley, the tension acts on opposite direction?
Please HELP, M1 EXAM IN 4 DAYS!:
I have a case similar to the 3rd type but with particles released from rest so that the hanging particle accelerates upwards and the particle on the fixed rough plane accelerates down the plane. The question is "What is the magnitude of the resultant force exerted by the string on the pulley." I don't understand why only tension in the string is used to solve it, and the weight of the particles and friction is ignored. Could you please explain?
(Reference: Edexcel M1 exam 3rd June 2015 Q8 part b) )
Best wishes and thank you for all your videos, they're great help!
it is now 2 days left
Only tension acts on the pulley itself which is the object you're trying to resolve the force on so the other forces can be ignored
can you use Pythagoras for the second one?
Yes
Can you make a video showing that way too
Resultant force = root (T^2+T^2)
+ExamSolutions OK thanks
Could you explain why the second one is F=2T cos 45? I thought cos45=T/F so F=T/cos45...
Yeah I'm struggling to understand how this makes any sense as well
@@kingvadanite1816 if you understand now, could you explain?
@@nathantj2915 I'm a bit busy at the moment, but I'm sure @TLmaths would be willing to reply.
That @ didn't work..
@@nathantj2915 try using the Pythagorean theorem to resolve case two, you will get it then.
Speak up can barely hear you with my volume at the loudest
Nah fam u have a shit phone