Mechanics of Materials: Lesson 20 -Statically Indeterminate Superposition Material Between Two Walls
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- čas přidán 6. 08. 2020
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loved the rubber band comparison! that really helped me understand the elongation concept in these problems
i 2nd this. jeff is the man.
Jeff, i just want to say youre a saint. thank you for teaching this!
Thank you very much! This video really helps me understand the compatibility condition and method of superposition!
when he sang 'let it grow" I lost it xd
whew just in time for a midterm! Thanks Dr.
All Your videos are awesome! Just proof of quality. Amazing work how You are able to explain the problems!! Thank You so much!
Mr. Jeff Hanson you are simply the best. Thanks alot
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
My professor reads from a slideshow, and has been doing so since ratemyprofessor was created. Thank you for teaching us
Great video. Thank you. I also appreciate your enthusiasm. It helps keep things interesting and the subject from being bland.
Dr. Hanson, you will help me pass my MoM exam tomorrow!
Thank you very much for this amazing explanation !!!
This man is a national treasure
Thanks a lot, greetings from Mexico
you are the best lecturer ever. Greetings fro PNG.
You a real one sir, thank you!
Thank you so much for doing what you do
all videos are amazing. thank you
Hey Jeff, I was curious, with this could you calculate the displacement at the point of the force - node 2?
This video helped so much
Thank you for well explanation..
Jeff you're saving my exam right here
Thank you sir!
My Hero !!!!!!!!!!!!!!!!
You are the best
why didnt we add the 0.15 to the 600 because RD was reactind to the steel becaause it elongated
God bless this man
is there any lesson that includes force method sir ?
Will not the stiffness of the wall matter here? I mean, are we considering it as an incompressible wall for this calculation?
absolute g right here
Why didnt we add 0.15 mm to the thick part of the shape? because when the wall is pushing down the biggest part is 600+0.15 mm
When calculating the restoring force Rd for the larger diameter section why do you use the original length (600mm) in the PL/AE equation? Do you not have to take into account the 15mm gap? Or is this gap already accounted for? see timestamp 11:11
You ALWAYS use the original length of the material.
It's a 0.15mm gap. Accounting for this would make almost no difference to the answer.
Are these kinds of questions applicable to the FE exam?
i love u jeff x
Sir please why wasn't the Ra and the Rd negated
why is Ra + Rc = 200, i need to know why to be able to solve another problem that the axial force is going in the other direction
in above problem mistake Reaction at A and reaction at D considered equal to solve Rd.
that's why wrong calculation.
3:08 🤣
I wish he was my dad.
I’m pretty sure the reactions are wrong
Anyone high AF?
You made a mistake when solving for the reaction of D. The answer is correct, but thats because your calculations are wrong and the method is wrong so you just made up numbers. Please do it again.
So rude!