3 Applications of Taylor Series: Integrals, Limits, & Series

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  • čas přidán 13. 07. 2024
  • Taylor Series are incredibly powerful, and in this video we will see three different applications of Taylor series to previous problems in Calculus. We can use them to integrate tricky functions, compute limits, and also compute the exact value of series that previously we could only claim converged.
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Komentáře • 44

  • @folsomboy86tbone15
    @folsomboy86tbone15 Před 2 lety +4

    Thank you, Professor. Your examples are very nice to have when I'm tutoring students.

  • @kevinpeng4059
    @kevinpeng4059 Před 4 lety +2

    Awesome video! perfect explanation of why in the heck I learned Taylor Series

  • @mikehughes6582
    @mikehughes6582 Před rokem

    The best explanation I've seen.

  • @krishna8976
    @krishna8976 Před 3 měsíci

    Excellent video. Last part was explained beautifully

  • @scxry5597
    @scxry5597 Před 28 dny

    Also wanted to thank you, great video.

  • @shadon_official2510
    @shadon_official2510 Před 4 lety +2

    Thanks for the video.

  • @kirpasingh9741
    @kirpasingh9741 Před rokem +3

    Very helpful in solving problems of iit entrance (jee advance).

  • @sergiolucas38
    @sergiolucas38 Před 2 lety +10

    excellent video. in advanced math though, im struggling to understand a lot of weird taylor expansions that pop up from nowhere :)

    • @navjotsingh2251
      @navjotsingh2251 Před rokem +1

      Sometimes you just need to accept the Taylor series, no matter where it appears 😅

  • @crickiworld
    @crickiworld Před 2 lety +1

    Awesome..

  • @jacobstarr9010
    @jacobstarr9010 Před 3 měsíci

    Taylor series are actually goated for doing tough limits.

  • @schizoframia4874
    @schizoframia4874 Před 2 lety +3

    Woah 🤯 he has a huge chalkboard

  • @garrettgeffre1792
    @garrettgeffre1792 Před 3 měsíci +1

    Love the man’s Gusto, but it would be a lot better if he wrote it out as he was talking.

  • @PhuongLe-ki7cb
    @PhuongLe-ki7cb Před 3 lety +1

    Great

  • @limchunyong6048
    @limchunyong6048 Před 4 lety +1

    Hi Trefor, very helpful video! One question, for your example on limits at 5:00, why do the larger powers go to zero faster?

  • @bubblegum-iz8zu
    @bubblegum-iz8zu Před 4 lety +1

    Thank you, now what if the upper limit of the integral is infinity? Could you still use Taylor series to solve it?

    • @aashsyed1277
      @aashsyed1277 Před 2 lety +1

      yes, of coure!

    • @carultch
      @carultch Před rokem

      There is a way to do the full domain integral of the bell curve without infinite series, that involves squaring it, generating a 3-D bell curve, and transforming it to polar coordinates to carry it out. The coordinate transformation turns dx dy into r dr dtheta. This generates r*e^(-r^2) as the integrand, which we can solve with simple substitution. The volume of the 3D bell curve is pi, and sqrt(pi) becomes the area of the original 2-d bell curve.

  • @arandomghost8819
    @arandomghost8819 Před 3 lety +1

    Sir when are we allowed to interchange and integral and summation?

    • @AssemblyWizard
      @AssemblyWizard Před 2 lety

      When it is a power series (each term is x^n multiplied by some number that doesn't depend on x, just on n) then you can always do that. Also interchanging derivative and summation.

  • @finwefingolfin7113
    @finwefingolfin7113 Před 3 lety +1

    Great video ... but I always understood that the integral of the normal distribution curve does have a name "The Error Function" ?

    • @carultch
      @carultch Před rokem +1

      Yes and no. The error function erf(x) is slightly different than the integral of the normal distribution curve. It is the integral of the normal distribution curve, but with a scaling constant and an asymptote at y=-1 and y=+1, that is set up this way for its applications in differential equations. For the CDF of the normal distribution, we want asymptotes at 0 and +1, so the function is shifted and scaled.
      The integral of the standard normal distribution curve in terms of erf(x) is as follows:
      integral Z(x) dx from -infinity to X = 1/2*erf(X/sqrt(2)) + 1/2
      And the integral of the base form of this function, e^(-x^2), in terms of erf is:
      1/2*sqrt(pi)*erf(x) + C

  • @douglas5260
    @douglas5260 Před 4 lety +1

    can you please make a video on how to integrate a summation? I got a little lost at 2:08

    • @douglas5260
      @douglas5260 Před 4 lety +4

      I think maybe I understand, you would integrate every term of the summation and sum the resulting integrals, and these are actually the terms of the new summation on the solution

    • @franzmaina3080
      @franzmaina3080 Před 2 lety +3

      Yes the method is like that, but he forget to specify that the series converges uniformly in [0,1]. Without this hypothesis you can’t switch the integral sign with the summation sign. {Sorry for the answer after a year ;)}

    • @douglas5260
      @douglas5260 Před 2 lety

      @@franzmaina3080 thanks!

  • @AssemblyWizard
    @AssemblyWizard Před 2 lety

    I was expecting you to give the disclaimer that swapping the integral and summation isn't always allowed but it is in this case

  • @stevengraham9330
    @stevengraham9330 Před 4 lety +1

    I don't get how you integrated the general term

  • @zunairaseemabkhan9934
    @zunairaseemabkhan9934 Před 4 lety

    Application of mechlerun series are Similar to taylor??

  • @martinhazard5982
    @martinhazard5982 Před 3 lety

    Landau symbols????

  • @abhishekRajput-hl7zi
    @abhishekRajput-hl7zi Před 2 lety

    from india

  • @rareli6394
    @rareli6394 Před 2 lety

    Help

  • @jayanthromale3389
    @jayanthromale3389 Před 3 lety

    Why didn't you use the basic formula of power series in evaluating integral of e^-x^2, the derivative of e^-x^2 will change

  • @duckymomo7935
    @duckymomo7935 Před 5 lety +12

    Taylor Swift or Taylor Series?

    • @crimfan
      @crimfan Před 3 lety +1

      If you type "taylor" into any search bar, she shows up first.

    • @carultch
      @carultch Před rokem

      "Taylor" of the Taylor Series is Brook Taylor.

  • @martinhazard5982
    @martinhazard5982 Před 3 lety

    wrong, you must use the symbols of landau

  • @haywingpong5371
    @haywingpong5371 Před 2 lety

    講嘢唔駛咁大動作嘛

  • @yopenzo
    @yopenzo Před 3 lety

    Mr. Bazett, Tarzan speaks better than you, that is, slowly, clearly and finally in an understandable way. Cheers, yop.