Statics - Chapter 6 (Sub-Chapter 6.6) - Frames and Machines

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  • čas přidán 7. 08. 2024
  • Statics
    Chapter 6.6
    Frames & Machines
    (OMG it is them Machines!!)
    We cover how to solve problems for frames and machines, especially how to draw the free body diagram for different types of frames and machines.
    The objective for this section, Students will be able to:
    a) Draw the free body diagram of a frame or machine and its members.
    b) Determine the forces acting at the joints and supports of a frame or machine.
    Among the items that will be covered:
    - What are frames and machines, the definitions
    - Steps for analyzing frames and machines
    - Identifying two force members
    - drawing free body diagrams
    - equation of equilibrium
    - Examples of problem solving for frames and machines problems
    - Various examples of different frames and machines, and how to draw their free body diagrams
    Frames and Machines problems are always quite interesting in the final exam, as many students seems to be quite intimidated by such problems. Just by looking at the diagram of the structure, is enough to send shiver into the students' spines and enough to make them concede defeat and not even attempting to answer the question.
    In this lecture I would like to illustrate to the student that these questions are not as difficult as they may think. Sometimes the solution is so simple that it sometimes shocks the students. The thing is, if you never tried and attempted such question prior to the exam, you will never realize that it is much easier that it seems. The structure that seems complex will continue to intimidate you, perhaps due to fear of the unknown.
    Well, if you are taking engineering course, you shouldn't actually let some diagram of simple frames or machines to intimidate you, right?
    One significant step is to be able to draw the free body diagram. If you are able to correctly draw the free body diagram, then half of the battle is already won. What is left is just equation of equilibrium and solving the equations. Well, sometimes simultaneous equation can happen, but that is just part of life, I guess.
    If you are searching for frames and machines statics, this is the video for you. Hopefully it helps =)
    Playlist for Statics Lecture Videos as well as Tutorial Videos:
    • STATICS - Lecture & Tu...
    Lecture Slides for the Lecture Videos:
    drive.google.com/drive/folder...
    ---------------------------
    Statics is the branch of mechanics that is concerned with the analysis of loads (force and torque, or "moment") acting on physical systems that do not experience an acceleration (a=0), but rather, are in static equilibrium with their environment. When in static equilibrium, the acceleration of the system is zero and the system is either at rest, or its center of mass moves at constant velocity.

Komentáře • 44

  • @sayhan3631
    @sayhan3631 Před 3 lety

    Assalamualaikum Dr, for 35:57, I think there should be a weight at one of the members which has point G on it (centre of gravity). Should we draw the arrow and write down the weight ?

    • @sayhan3631
      @sayhan3631 Před 3 lety

      Also Dr, for 38:11, why didn't we need to draw the member BC (a 2 force member) that connects between the 2 pulleys ?

    • @SaifuddinRehan
      @SaifuddinRehan  Před 3 lety +1

      yes you are correct, the weight force should be drawn and labeled

    • @SaifuddinRehan
      @SaifuddinRehan  Před 3 lety +1

      @@sayhan3631 if the question ask for FBD for all component, then it should be drawn...
      if we just need to draw FBD for the use of calculation, two force member are not compulsory as the point corresponding to both end of the two force member in the 2 FBD involved will be in corresponding to each other

    • @sayhan3631
      @sayhan3631 Před 3 lety

      @@SaifuddinRehan Thank you Dr, also in 43:08, the FBD of pulleys C and D are not drawn. Is it because it is not needed ?

    • @sayhan3631
      @sayhan3631 Před 3 lety

      Dr, for 48:00, why don't we draw the action-reaction force at A with a 45 degree angle, instead of splitting it into its x and y components ?

  • @muhammadnaufal6762
    @muhammadnaufal6762 Před rokem +1

    THANK YOU DR !!!

  • @zikryhuzaimi
    @zikryhuzaimi Před 4 lety +3

    Thank you!!! This video helped me a lot in this topic =)

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety +1

      you are welcome
      hope you will have no problem to get the full mark for these kind of problems if it comes up in the exam

    • @zaimmustafa9752
      @zaimmustafa9752 Před 4 lety +1

      ye do

  • @fatinnani0196
    @fatinnani0196 Před 3 lety

    Tq Sir...I will pray for you and your family 😊

  • @najmiaiman9225
    @najmiaiman9225 Před 4 lety

    love your videos

  • @zeniusworship
    @zeniusworship Před rokem

    thank you so much, i'm really helped by your video, i hope the best for you and your family, greetings from indonesia

    • @SaifuddinRehan
      @SaifuddinRehan  Před rokem +1

      you are very much welcome..
      all the best in your studies too..

  • @kasitadaniel8716
    @kasitadaniel8716 Před 3 lety

    Thank you !

  • @ibrahimergen9615
    @ibrahimergen9615 Před 3 lety

    thanks man very good video

  • @arp9763
    @arp9763 Před 4 lety

    W.C salam brother. you are really great.

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety +1

      salam
      alhamdulillah
      any good that I have ultimately belong to Allah
      but thank your for the compliment =)

  • @stevenm3914
    @stevenm3914 Před 4 lety

    something that is really confusing me is if when setting up a problem I should use internal forces or reaction forces to set up the the equation of equilibrium. In addition am I able to take a moment at a joint where there is only a tension force from a cable or do I need to have x and y reaction to be able to use momentum of equilibrium.

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety

      when you mentioned use internal forces, do you mean by using method of section? (where you cut off the member to have internal forces?)
      you have to differentiate two separate things:
      1. identify whether there is a moment reaction at a particular joint or not (for example pin joint will not have moment reaction, fixed support will have moment reaction)
      2. applying equation of equilibrium, where summation of moment about a specific point is equal to zero (if the body is in equilibrium, then summation of moment will always be zero)
      Identifying whether there are reaction forces and reaction moments is based on how each body is reacting to each other, and how each support prevent movement or rotation..
      * This will affect you FBD
      Equation of equilibrium is used to solve for structure in equilibrium, where for 2D you have summation of Fx, Fz, M all equal to 0, while for 3D you have summation of Fx, Fy, Fz, Mx, My, Mz all equal to zero.. (of course for summation of moment, you have to select where the point from which you calculate the moment from, this is not to be confused with the reaction moments mentioned above)
      * This is after you already established your FBD
      Hope this helps
      If anything still unclear, do let me know

  • @SaptadipDip
    @SaptadipDip Před 4 lety

    Thank you so much!
    May I know the the video link that has solving part in the classroom?

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety

      the recording when i was giving the lecture and solving problem in the classroom are in this playlist:
      czcams.com/play/PLHV_TAKwT1136mLWsutPPdD98rksQwWOn.html
      however i think the class for this particular topic may be when my camera was becoming worse in term of failing to focus due to some scratch in the lenses, where unfortunately part of the recording became blur (you may check the respective recording of the respective class session)

    • @SaptadipDip
      @SaptadipDip Před 4 lety

      Thank you so much!

  • @AverageNeighbor
    @AverageNeighbor Před 4 lety +1

    Really good video, just had a question about the FBD at 56:27, is there suppose to be another T pointing downward on point C?
    The text question asked to find Dx and the answer given in the back is Dx=18kN which is possible when taking the moment @ A
    M@A=Dx(2)+6(0.3)-6(3.3)-6(3)*=0, the (6(3)*) being the tension I'm asking about.

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety

      ah yes, you are correct, there should be another force downwards at point C due to the tension from the cable.
      thank you for the correction
      (i wonder if it is possible to make any notes for the correction to the video)
      i will check first for the other question you asked
      ("The text question" - did you mean the next question?)

    • @AverageNeighbor
      @AverageNeighbor Před 4 lety

      @@SaifuddinRehan All good, and no it was a textbook question for chapter 6 that asked for reactions at A and D, this is one of the harder chapters but anything helps so thanks

    • @SaifuddinRehan
      @SaifuddinRehan  Před 4 lety

      @@AverageNeighbor Oh okay.. all the best, and hope you excel

  • @PLEASURE_MOKGANO
    @PLEASURE_MOKGANO Před 2 lety

    how to know the directions of the reactions on the supports?

    • @SaifuddinRehan
      @SaifuddinRehan  Před 2 lety

      which type of support?

    • @PLEASURE_MOKGANO
      @PLEASURE_MOKGANO Před 2 lety

      @@SaifuddinRehan pin connection

    • @SaifuddinRehan
      @SaifuddinRehan  Před 2 lety

      @@PLEASURE_MOKGANO for pin, we have to assume the direction, and after the calculation we will know the correct direction based on whether the answer is positive or negative value (positive means assumed direction is correct, negative means the actual direction is the opposite)

    • @PLEASURE_MOKGANO
      @PLEASURE_MOKGANO Před 2 lety

      @@SaifuddinRehan ohhh okay Thank you so much Sir

    • @SaifuddinRehan
      @SaifuddinRehan  Před 2 lety

      @@PLEASURE_MOKGANO you are welcome
      all the best in your studies