The angle theta is 45 degrees. As for the first method, I think that this could be easily done with assuming that corresponding angles are congruent. Just assume that once that construction is made. I think that just using that postulate kind of justifies the SAS postulate. And I am definitely going to add this problem with how to use trig identities in geometry no matter the amount of methods used. I could be wrong and I think that would be wrong if the postulate of corresponding angles being congruent is not applicable in the second method.
Stesso percorso qui,roba che ci ho perso anni di vita. E il bello è che usando le formule giuste(quelle di Werner,non quelle di duplicazione o somma) ne uscivi con pochi semplici passaggi.
How can you draw DE so that angle made by segment s DC and DE is "theta"when you don't have the measure of the angle. In eagerness to prove you are making illogical statement.😮😮😮
@@user-fw9bl6qm1y , equation solutions depends on how you define your domain. If you say X is real no,complex number etc. your analogy sounds as illogical as drawing angle of unknown measure. Yes in high school geometry one is taught how any angle can be copied . But that is not that accurate. And there's nothing wrong in admitting the mistake
Even Tita is an unknown angle and has its own definition. Why didn’t you ask from the beginning and say that the triangle should not be drawn and the angle Tita is twice its size and you don’t know its measure?
The angle theta is 45 degrees. As for the first method, I think that this could be easily done with assuming that corresponding angles are congruent. Just assume that once that construction is made. I think that just using that postulate kind of justifies the SAS postulate. And I am definitely going to add this problem with how to use trig identities in geometry no matter the amount of methods used. I could be wrong and I think that would be wrong if the postulate of corresponding angles being congruent is not applicable in the second method.
La mia soluzione è 8(cosθ)^4-8(cosθ)^2+1=0...che dà soluzioni θ=22,5..θ=67,5(no)
Stesso percorso qui,roba che ci ho perso anni di vita. E il bello è che usando le formule giuste(quelle di Werner,non quelle di duplicazione o somma) ne uscivi con pochi semplici passaggi.
{20°A+20°B+90°D}=130°ABCD{130°ABD ➖ 180°ACD} =50°ABDACD 2^25 2^5^5 2^1^1 2^1 (ABDACD ➖ 2ABDACD+1).
Sorry for the sincerity! Every time you post this, no one understands! I don't know what kind of math this is! Maybe it's from Mars! 😂😂😂
How can you draw DE so that angle made by segment s DC and DE is "theta"when you don't have the measure of the angle. In eagerness to prove you are making illogical statement.😮😮😮
When we solve an equation and assume that it has a solution, we symbolize it with x. Is this illogical even if the equation does not have solutions?
@@user-fw9bl6qm1y , equation solutions depends on how you define your domain. If you say X is real no,complex number etc. your analogy sounds as illogical as drawing angle of unknown measure. Yes in high school geometry one is taught how any angle can be copied . But that is not that accurate. And there's nothing wrong in admitting the mistake
Even Tita is an unknown angle and has its own definition. Why didn’t you ask from the beginning and say that the triangle should not be drawn and the angle Tita is twice its size and you don’t know its measure?