Hi Sir , Thank you for your valuable video, but I have a question please. At 2:00 min there is number 5 shows as ( 162.5 >= 5 ) from where we got this 5 ?
It is a required condition for the test to be valid. The test requires np and n(1-p) to be >=5. I didn't focus on it in the video because some people use 10 (rather than 5), some use other values, and some don't mention it at all.
The area in the table is the "less than area". Since out Z is positive, we need the area in the right tail which is 1 - "less than area". If Z were negative, we will use the "less than area" without subtracting from 1.
You explain it better than any teacher, thanks!
Thank you for this learning material, and I wish you the best 👍
I wish you the best too, buddy.
Very good explanation
Thanks and welcome
you really saved my exams
Hello sir, could you please do a video on EOQ and EPLS Models in Inventory. thank you
thank you sooo muchhhh
Hi Sir , Thank you for your valuable video, but I have a question please.
At 2:00 min there is number 5 shows as ( 162.5 >= 5 ) from where we got this 5 ?
It is a required condition for the test to be valid.
The test requires np and n(1-p) to be >=5. I didn't focus on it in the video because some people use 10 (rather than 5), some use other values, and some don't mention it at all.
@@joshemman so is it called as ( significant level ) or it has another name ?
and thank you for your replay
@@abuda7em20No, it (the 5) is not the significance level.
alpha is the significance level.
how did you get the answer 2.32 was
👍
why did we minus it at 3:15. (1-0.9898)?
The area in the table is the "less than area". Since out Z is positive, we need the area in the right tail which is 1 - "less than area".
If Z were negative, we will use the "less than area" without subtracting from 1.
how did u sove the hypothesis test because im getting a different answer i got 5.80
The numerator is 0.72 - 0.65 = 0.07
Content of denominator square root: =0.65*0.35/250 = 0.00091
Taking the square root gives 0.0302.
Z = 0.07/0.0302 = 2.32
Please sir can you help me with your email address thanks 🙏