Fourier Series - 12 | Solution of 3.22(a)-(a) of Oppenheim | Chapter3 | Signals and Systems

Solution of problem 3.22(a) - (a) of Alan V Oppenheim

[@manjeetraj1336]

Sir 1.13 ka bhi solution kar digiye
Please sir

[@SgtScratchnSniff147]

At the end where you factor out -1/(2jpi) from -1/-(2jpi), wouldn't you still have one positive term and one negative term, making the middle term sine?

[@mathosyguru]

yes, so in 2nd term of answer there will be sin2pit at place of cos2pit.

[@mathosyguru]

thanks

[@laraibabbas553]

Sir plz upload 3.23 and 24