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Conquer International Math Olympiad (IMO) with Your Outstanding Algebraic Skills

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  • čas přidán 15. 08. 2024

Komentáře • 17

  • @MyComedy-rp8dl
    @MyComedy-rp8dl Před měsícem +1

    Very nice explanation

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Thank you so much my friend for your support👍👍👍

  • @jagadeesann9527
    @jagadeesann9527 Před měsícem +1

    Thank you sir

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Thanks a lot my friend for your continued support! I really appreciate it👍👍👍

  • @domedebali632
    @domedebali632 Před měsícem +1

    Very nice explanation prof.

  • @iqtrainer
    @iqtrainer Před měsícem +1

    Another great video prof🎉

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Thansk a lot my friend for your support👍👍👍

  • @MrGLA-zs8xt
    @MrGLA-zs8xt Před měsícem +2

    I dont like synthetic division but long division just like you prof. Good thing I do not see uneducated comment now

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Haha thanks for your support my friend👍👍👍

  • @user-wj1qb3qu1y
    @user-wj1qb3qu1y Před měsícem +1

    Case I : x=y=z then
    x²+x=2 then x=1,-2
    and solution x=y=z={1,-2}
    Case II
    x≠y≠z
    But how we prove this??
    The best polite proffesor in youtube my greeting

    • @drpkmath1234
      @drpkmath1234  Před měsícem +1

      Hello my friend. I used further factoring for case 2. I always appreciate your support👍👍👍

  • @wannabeactuary01
    @wannabeactuary01 Před měsícem +1

    Fabulous explanation - Perhaps missing a statement re symmetry or is this picked up by x = y = z?

    • @wannabeactuary01
      @wannabeactuary01 Před měsícem

      I do watch to the end - but the new video choices do block left of board.

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Hello my friend! Yes symmetry was the key in my solution development haha thanks for your comment👍👍👍

  • @godQlol
    @godQlol Před měsícem +1

    x + yz = 2 #1
    y + zx = 2 #2
    z + xy = 2 #3
    #1 is equivalent to:
    x^2 + xyz = 2x
    (x - 1)^2 = 1 - xyz
    Similarly, we have:
    (x - 1)^2 = (y - 1)^2 = (z - 1)^2 = 1 - xyz #4
    #1 - #3:
    x + yz - z - xy = 0
    (x - z)(1 - y) = 0
    Similarly, we have:
    (y - x)(1 - z) = (z - y)(1 - x) = 0
    x = y = z or x = y = z = 1
    Consider when x = y = z =/= 1:
    We can rewrite #1 as:
    x^2 + x - 2 = 0
    (x + 2)(x - 1) = 0
    x = y = z = -2
    Hence {x, y, z} = {1, 1, 1} or {-2, -2, -2}
    QED [ Fun algebraic question :) ]

    • @drpkmath1234
      @drpkmath1234  Před měsícem

      Nice solution my friend! haha thanks for sharing it👍👍👍