REAL ANALYSIS -04 || Union of countable sets || Countable sets

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  • čas přidán 4. 07. 2022
  • In this video we shall prove how union of two countable sets is a countable set
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Komentáře • 20

  • @bazilaayoub6762
    @bazilaayoub6762 Před 2 měsíci +1

    Ty sooo much

  • @shalini7514
    @shalini7514 Před 6 měsíci +1

    Your explanation is well

  • @ayaanfarooq3854
    @ayaanfarooq3854 Před 2 lety +2

    👌👌👌

  • @farzanarasool6858
    @farzanarasool6858 Před 2 lety +2

    👌👌👌👌👌👌👌👌🔥

  • @Paridhi754
    @Paridhi754 Před rokem +1

    Great explanation..

  • @laaribjahan5307
    @laaribjahan5307 Před 2 lety +2

    🥰🥰🥰

  • @Tabis19
    @Tabis19 Před 2 lety +2

    Nicely explained _Keep it up brother^_^

  • @Syed_Musadiq
    @Syed_Musadiq Před 2 lety +2

    Best wishes 🥰 ,,, Keep going, consistency is the secret 🙊,,,

  • @roufgulzar6683
    @roufgulzar6683 Před rokem +1

    Good Bhai Sara padau

  • @shalini7514
    @shalini7514 Před 6 měsíci

    Hlo Bhai where 1st define fun
    f(x)=a. : x=1,2,3,,,,,,,,m
    x
    C. :k>=m.
    k-m
    This is satisfies 121 fun
    Your 1st define function is wrong that is not 11 fun

    k

    • @sakibwani5695
      @sakibwani5695  Před 6 měsíci

      in Ax: x runs from 1 to m
      so x covers points from 1 to m
      now in another part Cx-m I'm supposed to take those points that aren't common with the above part so here in Cx-m I'm taking x>m i.e x>=m+1
      u r saying i should take x>= m thn m is the common point in both partions
      thn this is clearly not a disjoint partition