Math Olympiad Problem | Nice System of equations Problem | Math Olympiad Training

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  • čas přidán 8. 06. 2024
  • In this Math Olympiad problem video, we'll tackle System of equations Problem to help with your Math Olympiad training. Get ready to challenge your math skills!
    #exponential
    #exponents
    #exponentialproblem
    #maths
    #mathematics

Komentáře • 15

  • @nexio5454
    @nexio5454 Před měsícem +2

    With small numbers like this, you can just list perfect squares under 45 and find by try and error. I solved it in 15 seconds like this :))

    • @MrRedEngineer
      @MrRedEngineer Před měsícem

      I agree. But I don't agree with that mention how fast you solve buddy. Lower your ego and accept his solution.

    • @nexio5454
      @nexio5454 Před měsícem

      @@MrRedEngineer I accept his solution and it's definitely the most elegant solution. I didn't mean to show off and I'm sorry if my comment seems like I did.
      The problem being presented as an olympiad problem (which it clearly isn't), the goal would be to solve fast hence my solution and my exemple

    • @matholympiadonlinesolver
      @matholympiadonlinesolver  Před měsícem

      Thank you

  • @Abby-hi4sf
    @Abby-hi4sf Před měsícem +2

    Always a+b > a-b , so you should not have four cases . I will assign the greater factor to the greater eqn

    • @coderhub-tech7942
      @coderhub-tech7942 Před měsícem +1

      Does not apply if b is negative, think again

    • @Abby-hi4sf
      @Abby-hi4sf Před měsícem +1

      @@coderhub-tech7942 Let us not forget that every negative number squared is always positive. All variable a, b, c, are sqared on the question
      So the answer is a= +/- 3 , b= +/- 6 and c= +/- 2

    • @coderhub-tech7942
      @coderhub-tech7942 Před měsícem +1

      @@Abby-hi4sf true, but you are factoring a²-c² or c²-a² depending on your approach, which can include negative numbers, so your argument doesn't work there

    • @Abby-hi4sf
      @Abby-hi4sf Před měsícem

      @@coderhub-tech7942 Whether you are factoring a²-c² or c²-a² , the fact remain that each variable is sqared .ex
      a²= (-a)² and (-c)² =c² so
      a²-c² = (-a)²-c² = a²-(-c)²

  • @coderhub-tech7942
    @coderhub-tech7942 Před měsícem +1

    Tried calculating based off the thumbnail, i got c²-a² = -5 so (c+a)(c-a) = -5, using that and a little brute force, the 4 possible values are c = ±2, a = ±3. From there you get b = ±6 which is the solution

    • @matholympiadonlinesolver
      @matholympiadonlinesolver  Před měsícem

      Ok thank you

    • @bledlbledlbledl
      @bledlbledlbledl Před měsícem

      the way i went about it was very similar to that. looking at the thumbnail, a² must be 5 more than c². starting from 1 and just squaring a few numbers, it didn't take long to notice that 3² was 5 more then 2². from there, finding b² was just a subtract

  • @kiloperson5680
    @kiloperson5680 Před měsícem

    Might I ask what country are you from?