Genetics problem ChatGPT failed to solve
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- čas přidán 28. 03. 2024
- The number of chromosomes present in a human skin cell is 4 more than the number of chromosomes present in the sporogenous cell of a Wheat plant.
Also the number of chromosomes in the endosperm of a wheat plant is 3 more than the number of chromosomes present in the cheek cells of a Goat.
The number of chromosomes in the ovum of a goat is 2 less than the number of chromosomes present in a female European honey bee's skin cell.
The Primary spermatocyte of an elephant has 40 chromosomes more than that of the chromosomes present in the photoreceptor cells of Male European honey bees.
If the number of chromosome present in a root cell of Arabidopsis Thaliana is 4 less than the half number of chromosomes present in the spermatozoa of Elephantthen determine the number of Chromosomes present in the male gamete of Arabidopsis Thaliana.
Solution:
Number of chromosomes in a human skin cell: 46
Number of chromosomes in the sporogenous cell of a wheat plant: 46-4=42
Number of chromosomes in the endosperm of a wheat plant: 63
Number of chromosomes in the cheek cells of a goat: 63-3 =60
Number of chromosomes in the ovum of a goat: 30
Number of chromosomes in the skin cell of a female European honey bee: 30+2=32
Number of chromosomes in the primary spermatocyte of an elephant: 40 + 16 =56
Number of chromosomes in the photoreceptor cells of a male European honey bee: 16
Number of chromosomes in the spermatozoa of an elephant: 56/2=28
Number of chromosomes in the root cell of Arabidopsis thaliana: 28/2=14-4=10
Number of chromosomes in the gamete Arabidopsis thaliana 10/2=5
For predicting breeding value of a cow on basis of Information on Itself, Its dam and paternal half sibs we use
(a) Analysis of variance technique
( b) Maximum likelihood technique
(c) Multiple correlation technique
(d) Multiple regression technique
For predicting the breeding value of a cow based on information on itself, its dam, and its paternal half-sibs, the most appropriate technique is:
(d) Multiple regression technique
Multiple regression allows the inclusion of various sources of information (the cow itself, its dam, and its paternal half-sibs) to predict the breeding value by estimating the contribution of each factor. This method effectively combines these different pieces of information to make the best prediction of the breeding value.
@@GeneticsLessons thank you so much sir , your videos are very help
Great explanation! ❤
Thank you! 😃
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The mean of the scores on a certification exam is 300, the standard deviation is 50, and the scores are normally distributed. Approximately what percentage of students score 200 or lower on the test?
Ans 2.28%
I have a lot of videos on this topic - just check my last 50 vireos on the channel.
@@GeneticsLessons okay sir , please see my other questions
Can you please answer this question sir....
In a given species of flowering plant the colour of the seeds is exclusively determined by the color of its seed coat. Seed coat colour in this species is determined by the nuclear gene with two alleles. The white W allele is dominant over brown w allele. If a plant with brown seeds ww is crossed as a female with pollen from a white seed WW plant what will be the seed color and the genotype of the embryo in the resultant seeds obtained from this cross
Brown seeds with Ww embryo (answer)
White seeds with Ww embryo
Brown seeds with ww embryo
White seeds with ww embryo
Now it is brown seeds with Ww embryo as the answer. Is it because the seed coat is from the female parent and female parent is brown. But the progeny of the cross embryo is Ww because embryo colour is not determined by the seed coat
White seeds with Ww embryo
Thank you sir......
Hello, I am having trouble understanding the answer for this question and I was wondering if you could help me with it?
You have at your disposition a restriction enzyme E, which recognizes DNA and cuts it as shown below. If you have DNA fragments cut with enzymes E, F, G, or H, which can you ligate to another piece of DNA cut with E? SELECT ALL THAT APPLY
DNA cut with enzyme G
DNA cut with enzyme E
DNA cut with enzyme F
DNA cut with enzyme H
The answers are DNA cut with enzyme G and DNA cut with enzyme E. I sort of understand why DNA cut with enzyme E is correct but I don't understand why DNA cut with enzyme G is correct. I was working out the problem and I thought DNA cut with enzyme H makes more sense than DNA cut with enzyme G. I would greatly appreciate your help.
I can't post the image link but I posted it on my channel if you want to see
Just put in google cos and share a link here "choose every one with the link can see it".
If the amount of variation in height that is associated with variation in weight Is 49%, what Is the correlation between these variables?
Ans : 0.7
I know it is solved by underroot but why , can you please explain sir
The variable that is the Correlation Coefficient is R^2. To cancel out a ^2 in a variable, you take the square root on both sides.
So in this case, convert percentage into a decimal. 49% = 0.49. R^2 is equal to 0.49. Then, take the square root on both sides to get R by itself. √R^2 = √0.49. R = 0.7
Highest genetic gain can be achieved by accurate estimation of breeding value of
(a) Sires of dams
(b) Dams of sires
(c) Sires of sires
(d) Dams of dams
What should be the correct ans ans why ?
The correct answer is (c) Sires of sires.
Accurate estimation of breeding values for sires of sires (grand sires) tends to yield the highest genetic gain because these sires contribute significantly to the next generation's genetic makeup. They have a broader influence on the gene pool due to the number of offspring they produce, which in turn becomes parents themselves. Therefore, focusing on accurately assessing the breeding value of sires of sires ensures that the beneficial traits are effectively passed on and amplified in the population.
@@GeneticsLessons thank you sir but why not dams of sires. ? They can also contribute
@@ridafatima7102 It's just that an elite bull can inseminate 1000 cows a year - and an elite cow can give birth to one litter per year..This is a matter of economic feasibility.
@@GeneticsLessonsokay .. thank you so much sir
👍
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Sir , you have solved my one genetics doubt in your one of the video, How to send you question , i have exams in 5 days can you please ans my little doubts
You may post it here - if you have photo - post it on google and make available to everyone and post a link here.
In a statistics class, the probability of earning a grade of either A or B is equal to .50 and the probability of a grade of C is equal to .30. What Is the probability of a grade of either A, B or C?
Ans : 0.8
Use sum rule.
@@GeneticsLessons okay sir
Can you please do this question for me. An Rh negative women married to a heterozygous Rh positive man has three children. The probability that all three of theiŕ children are rh positive is
1:2
1:4
1:8 correct answer
Zero
This couple have 50% (1/2) chances that their child will be Rh + so 1/2 x 1/2 x 1/2=1/8 for all 3 to be Rh+. or 1 to 8 or 1:8
Thank you sir.....that was helpful
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