Find the centre and radius of the circle 3x^2+3y^2-6x+4y-4=0.| Circle | Coordinate Geometry | Lec318

#circle #coordinategeometry #mathspulse #chinnaiahkalpana #mpcircle

[@_v_s__creations_3897]

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[@MathsPulseChinnaiahKalpana]

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[@sujalbarman471]

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[@suresh.m8156]

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[@MathsPulseChinnaiahKalpana]

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[@chemustogeofrey536]

Centre and radius of 2x^2-2y^2-6x+10y+7=0

[@MathsPulseChinnaiahKalpana]

make coefficients of x^2 and y^2 to 1,
x^2-y^2-(6/2)x+(10/2)y+(7/2)=0
x^2-y^2-3x+5y+(7/2)=0
2g=-3
g=-3/2
2f=5
f=5/2
centre (-g,-f)=(3/2,-5/2)
use radius formula and find radius.

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[@ravikant_raj]

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[@santhoshikumar2320]

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[@g.satyanarayanreddy403]

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[@MathsPulseChinnaiahKalpana]

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[@kiransai.t306]

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[@DesiLomda]

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[@twinkleagarwal2639]

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