Subgroups of S4 group || short tricks || Permutation Group important concepts

Hi
Please find more group theory videos here
Group Theory: • Group Theory
#permutation #Permutationgroup #s4group #orderofelements #sngroup #subgroupsofs4group #subgroupsofsngroup
#csirnet #subgroups #primeordergroup #Cyclicsubgroups #cyclicgroup #Noncyclicgroup #shorttricks #subgroups
please subscribe the channel and share videos 🙏subgroups of s4 groups4 group elementselements of s4 groupsubgroups of a groupLagrange theoremnumber of subgroups of s4 groupabelian groupCyclic group in discrete mathematicsjam mathematics coachingcsir net jrf mathematicscloud gate

[@Smoothcurveup52]

Thanku so much ma'am,you have explained very nicely, really wonderful lecture

[@dr.upasanapahujataneja1707]

🙏

[@sakibgour4041]

Sb kuch clear ho gya mam thanku so much

[@sandeepjaiswal7505]

Nice explanation ma'am thanks for help us

[@learningtogather8358]

Very helpful ma'am
Ek hi question pe sab concept chupa hai

[@sonambhardwaj1520]

Useful video mam 😍 thanku so much ...... ❤️

[@mohammedarshad5210]

Very good explanation mam keep rocking 🔥💥

[@vishalpatil1937]

Very nice explanation mam

[@ronneysaini7763]

Mam aapne Non cyclic me kaise choose kiye h element smhj me nahi aye

[@subhanulkarim5256]

Thankyou madam it's very helpful

[@dr.upasanapahujataneja1707]

Keep watching

[@shoebansari4131]

Thank u ma'am 🥰 Love you.

[@Ayesha_01257]

Thankyou so so much 💕

[@namratapatil1813]

Thank you

[@kajalprajapati8523]

Thanks mam

[@touheedanwar3250]

thanku sooo much mam

[@akashprusty4352]

Thanku mam

[@VikashYadav-fx4vx]

Is U(10) isomorphic to U(12)

[@Shiksha291]

Nhi

[@zubairsmathtutorials4542]

Mam is there any short trick to write elements of S4

[@dr.upasanapahujataneja1707]

Write element n then its inverse

[@zubairsmathtutorials4542]

@@dr.upasanapahujataneja1707
Plzz explain mam

[@LiamC328]

How to find the subgroup of S3 generated by a cyclic permutation (1, 2, 3)?

[@Sarvagya-du1kv]

@Liam Casilimas Since we know that S3 is isomorphic to D3 and as we know that D3 has total 6 subgroups which we can deduce either using formula 𝜏(n) + σ(n) or making subgroup table for D3 and applying divisor method . Out of these 6 subgroups of D3 ,5 subgroups are cyclic which again can be deduced either using formula 𝜏(n)+n or using subgroup table for D3 and applying divisor method. Since here we are only concerned about cyclic subgroups therefore we will stick to that. As we know now that D3 has 5 cyclic subgroups constituting 1 subgroup of order 1 , 3 subgroups of order 2 and 1 subgroup of order 3 and since S3 is isomorphic to D3 that implies S3 will exhibit the exact same properties as D3 . Therefore S3 will have only one cyclic subgroup of order 3 and that cyclic subgroup will have cycle permutation (123) as generator, the cyclic subgroup is, H ={ e =(1)(2)(3), (123), (132) } < S3 , ∴ NO. of cyclic subgroups of S3 generated by (123) permutation is only one . NOTE: Here (123) as well as (132) both are generators of the cyclic group H ( since O(123) = O(132) =3= O(H) ), since one is inverse of the other and as we know if x generates a cyclic group then x−1 also generates the very same group. Hopefully the answer was comprehensible enough for you . cheers !

[@ujalaamir3813]

nhi smj a rhi