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Invertible matrices are square

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  • čas přidán 19. 02. 2019
  • Why invertible matrices must be square. Definition of invertible matrix and showing that a 3x2 and a 2x3 matrix cannot be square.
    Check out my Matrix Algebra playlist: • Matrix Algebra
    Subscribe to my channel: / @drpeyam

Komentáře • 37

  • @kedymera6164
    @kedymera6164 Před 5 lety +11

    let A be an mxn invertible matrix, so there exists a matrix B such that AB=BA=I
    for AB to be defined, we require B to be nxp for some p
    for BA to be defined, we require p=m
    but also AB=BA so in particular the dimensions of AB and of BA are the same
    dimensions of AB are mxm, dimensions of BA are nxn
    so m=n
    so A is square

    • @Sooboor
      @Sooboor Před rokem

      why do you assume that AB=BA?

    • @kedymera6164
      @kedymera6164 Před rokem

      @@Sooboor
      That's the definition of an invertible matrix: A admits a left inverse and a right inverse and those two inverses are the same. Of course you can have a matrix that is "semi-invertible" if you like, where A only admits an inverse on one side (e.g. {1 0} * {1 0}^T = {1} = I_1)

    • @Sooboor
      @Sooboor Před rokem

      @@kedymera6164 But if A is invertible, it means that AB=I_m×m and BA=I_n×n
      Then we need to show that n=m
      Btw amazing that you replied instantly when your original comment is from 4 years ago

    • @kedymera6164
      @kedymera6164 Před rokem

      @@Sooboor
      Oh I see what you mean! I suppose you don't have to assume AB=BA. If you got two different identities, the larger one will have rank > rank A and rank B, which is impossible.

  • @sugarfrosted2005
    @sugarfrosted2005 Před 5 lety +3

    I'm not sure invertible really makes sense on a structure that isn't closed under multiplication. I seem to recall there is a definition of the determinant of the non-square matrix. Ming Gu at berkeley mentioned it in passing in one of his lectures.

  • @aishwaryapotdar1348
    @aishwaryapotdar1348 Před rokem +1

    oh wow that ABABAB ohhh woke me up lol, you're too good

  • @compphysgeek
    @compphysgeek Před 4 lety +2

    When I grew up Maths was my first love. Then I met her younger and sexier sister Physics and fell in love. Now you show me how truly beautiful maths still is.

  • @jiyoonpark5022
    @jiyoonpark5022 Před 4 lety +4

    Nobody
    literally no one
    Dr Peyam: ABABAB oh~

  • @GhostyOcean
    @GhostyOcean Před 5 lety +3

    I thought (AB)C=A(BC) was only true for A,B,C being n×n matrices. Does the associative property of multiplication apply for all matrix multiplication?

    • @GhostyOcean
      @GhostyOcean Před 5 lety +2

      @@jigglygamer6887 oh okay, I see. I suppose I COULD prove it for myself but that seems like a lot of work that I'm not really wanting to do using the definition of matrix multiplication.

    • @M0rph1sm55
      @M0rph1sm55 Před 5 lety +2

      @@GhostyOcean Matrix multiplication is just concatination of the corresponding linear maps, which clearly is associative.

  • @trewq398
    @trewq398 Před 5 lety +2

    thank you for the explanation

  • @SartajKhan-jg3nz
    @SartajKhan-jg3nz Před 5 lety +1

    What do u mean by consistent? Moreover, when we apply a non square matrix, doesnt the rank always decrease from 3 to 2? If so, then D=0 this A is not invertible?

  • @inmpark
    @inmpark Před rokem

    Thank you for the video, can you elaborate on why Ax=0 having a free variable leads to having infinite number of solutions?

  • @aishwaryapotdar1348
    @aishwaryapotdar1348 Před rokem +1

    this helped me, thank you so much! :)

  • @crazyphil7782
    @crazyphil7782 Před 5 lety +2

    Pseudo- inverse is a thing

  • @SovietOnion
    @SovietOnion Před 5 lety +4

    Nice meme in your thumbnail

  • @srpenguinbr
    @srpenguinbr Před 5 lety

    8:00
    isn't the determinant about the unit cube, not the entire space?

  • @haohuynhnhat3881
    @haohuynhnhat3881 Před 3 lety

    15:00 why is inf = 0*inf?

  • @MrKosynus
    @MrKosynus Před 5 lety

    In case of 2*3 matrix, why Ax=0 does not imply that x=0? Yes, It has infinitely many solutions, but they include x=0, right?

  • @juandeluna2652
    @juandeluna2652 Před 5 lety +1

    Greetings dear Dr Peyam.

  • @cycklist
    @cycklist Před 5 lety +1

    Can't you just say that they're not invertible because there is no identity matrix defined for non-square matrices?

    • @drpeyam
      @drpeyam  Před 5 lety +2

      No because in theory if B has the right size, you could get the identity matrix

  • @simewn
    @simewn Před 5 lety

    I am sorry, but who is First on this video? What is going on here? I am confused.

  • @akshat5338
    @akshat5338 Před 2 lety

    NCERT Ch3 miscellaneous exercise....

  • @japotillor
    @japotillor Před 5 lety

    Don't you mean we don't want the determinant to be zero? I don't remember inverting a matrix with a zero determinant :p

  • @skeletonrowdie1768
    @skeletonrowdie1768 Před 5 lety +1

    Wow you sound so chill in this video, did the buddha come to your house this morning?? ;p

    • @drpeyam
      @drpeyam  Před 5 lety +2

      Hahaha! It’s more that I went for a run and I’m exhausted 😂

    • @skeletonrowdie1768
      @skeletonrowdie1768 Před 5 lety

      Hahaha awesome, runner's high!

  • @lavenderblues
    @lavenderblues Před 5 lety

    love