Using Log Properties to Simplify Expressions... Without a Calculator

In this video we will simplify expressions using log properties without a calculator.
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[@xs-2004]

For problem #12: I think the problem should be e to the positive x to solve it like you do

[@xs-2004]

Then minus 6 times e to the negative x then minus 1=0

[@themathandphysicstutor]

@@xs-2004 Hi Xinna -- When you factor out a GCF you always take out the smallest exponent, in this case -x is smaller than positive x which is why e^-x gets factored out first leaving you with... e^-x(e^2x-e^x-6)=0... Upon further factoring you end up with e^-x(e^x-3)(e^x+2)=0... If you would like to double check the factoring is correct, you can always re-multipy everything to get back to where you started :)