Henry's Law and Gas Solubility Explained

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  • čas přidán 22. 11. 2016
  • www.thegreatcourses.com/course...
    I am Professor Davis, and in this short clip I explain how Henry's Law can be used to calculate the solubility of a gas using its partial pressure and its Henry's Law constant.
    This clip is just a short sample from my new 60-lecture course available from The Great Courses. Learn more about the course at the link above and learn more about me and my other projects at / chemsurvival

Komentáře • 88

  • @kerryjohnson1066
    @kerryjohnson1066 Před 3 lety +19

    The only explanation that's helped me understand Henry's Law. Much love from Washington!

    • @samuraijosh1595
      @samuraijosh1595 Před 3 lety +1

      Yo, a recent comment!

    • @Emoney131
      @Emoney131 Před měsícem

      @@samuraijosh1595 hello from the future! buy NVDA !

  • @sreeguru7055
    @sreeguru7055 Před 3 lety +1

    Thank you. Great explanation

  • @revanwallace
    @revanwallace Před 6 lety +5

    When beer and soda peopled talk about the "volumes of CO2" in their beverages, what exactly do they mean? Based on this video, I would say that a beverage under 4 atm of pressure (or 59 psi) at room temperature would have 2.7 liters of CO2 (at STP) dissolved in it for every liter of water. That sounds like 2.7 volumes of CO2 to me...but my "PSI to Volumes" charts say differently. So what is the right definition of "volumes of dissolved CO2"?

  • @henrygagejr.-founderbuildg9199

    Well said. It happens my name is Henry and I love the science of absorption, adsorption, phase change, energy transfer etc because of my work with Hempcrete. Would love to start a conversation with you.

  • @m.r.5129
    @m.r.5129 Před 5 lety

    This was helpful.

  • @nellvincervantes3223
    @nellvincervantes3223 Před 4 lety +18

    How did you get the new pressure for CO2, 4x10^-4 atm?

    • @user-qn9ym6hz2c
      @user-qn9ym6hz2c Před 3 lety +5

      It's the partial pressure of CO2 in air. About 400 ppm.

    • @sofiasirajsirajabdu4258
      @sofiasirajsirajabdu4258 Před 3 lety +4

      @@user-qn9ym6hz2c how did he came up with22.4?

    • @khairaniputrimarfi8453
      @khairaniputrimarfi8453 Před 3 lety +3

      @@sofiasirajsirajabdu4258 that's a standard constant which is apply in 0 degrees c (STP), and 24.4 for 25 degrees c (RTP)

  • @sumitbarik6247
    @sumitbarik6247 Před 2 lety

    Can any one answer what is the relationship between the Henry's law constant and CO2 and affect on PH.

  • @nabu7354
    @nabu7354 Před 3 lety +1

    what about temperature? is that not in the equation?

  • @prathamhalder4620
    @prathamhalder4620 Před 2 lety

    thanks for such a lovely explanation. love from India

  • @andrejulian8378
    @andrejulian8378 Před 3 lety

    what could be the reason for the exclusion?

  • @siddharthkumar4279
    @siddharthkumar4279 Před 3 lety +2

    Thank you sir. Much love from india❤️❤️

  • @dakshjashnani6584
    @dakshjashnani6584 Před 3 lety

    Very helpful to clear my concept .......... from a student of class XI

  • @saurabhmodh1899
    @saurabhmodh1899 Před 6 lety +5

    Nice Expanation

  • @nabu7354
    @nabu7354 Před 5 lety +3

    Thank you for this explanation. I'm confused why they call it "dissolved" which usually refers to a solid dissolving into a liquid changing its physical structure. it just seems that it is only referring to the presence of CO2 (in its gas form) in the liquid, which needs a considerable amount of pressure to force it into that liquid anyway. So does its structure/physical properties change in any way when described as "dissolved" or is it still in its gas form? I'm confused as it seems to contacdict the physical phases graph of CO2 to refer to it as "dissolved". Apologies if this is a stupid question.

    • @magnuswootton6181
      @magnuswootton6181 Před 2 lety

      if you matched it one co2 for every h in the water, the co2 would probably class as a solid now u compressed it down so much. i think its about 20,000 psi to do it. (9-10 tonnes of pressure.)

  • @vadtallalabhai
    @vadtallalabhai Před 4 lety +1

    Thanks for video

  • @brandongriggs6934
    @brandongriggs6934 Před 4 lety +5

    Assuming the solubility of CO2 in water when the can opens was not negligible, would we subtract that amount from our final answer? Also, where did you get the partial pressure of 4.0*10^-4 atm from? Thanks! :)

    • @MdJunayed
      @MdJunayed Před 2 lety +2

      Partial Pressures of Atmospheric Gases table... 0.3mm Hg = 3.9 x 10^-4

  • @andreichicos
    @andreichicos Před 7 lety +2

    Useful

  • @riepie13
    @riepie13 Před 7 lety +45

    Just leave us hangin like that ?!

    • @isiTsotsi
      @isiTsotsi Před 4 lety +6

      Yes, this is actually an ad and doesn't have the honesty to say so at the beginning. He didn't even talk about a partial pressures.

  • @dr.pathak1954
    @dr.pathak1954 Před 4 lety +5

    Veryy helpful.
    Love from India.

    • @ChemSurvival
      @ChemSurvival  Před 4 lety +4

      I'm so glad it was useful to you! Love back from America.

  • @nyhyl
    @nyhyl Před 4 lety +10

    Why does it drop to 4.0 * 10^-4 atm? The standard atmospheric pressure is 1 atm and not 0.0004 atm.

    • @marladeklotz6693
      @marladeklotz6693 Před 4 lety +26

      .0004 atm represents the amount of CO2 in the atmosphere as a partial pressure. All the atmospheric gases act independently and add up to 1 atm.

    • @beulahnarendrapurapu2029
      @beulahnarendrapurapu2029 Před 4 lety +6

      There is 0.04% CO2 in the atmosphere (approximately). So according to Daltons Law of partial pressures, the partial pressure of CO2 should be (mole fraction or fraction of molecules)*(total pressure)= (0.04/100)*(1 atm) = 0.0004 atm

    • @athiholotibusinesstalk321
      @athiholotibusinesstalk321 Před 4 lety +2

      Where’s did we get 0.04% now. From the statement we have 4atm Pco2.

  • @raghavendrapotluri5861
    @raghavendrapotluri5861 Před 5 lety +2

    Is there a law or formula to calculate what time is required for the dissolved gases to affervate (come out of the liquid) once the pressure is removed???

    • @yashdeole1413
      @yashdeole1413 Před 5 lety

      No

    • @ishowspeedsuyi
      @ishowspeedsuyi Před 4 lety +2

      I think Graham's law of diffusion or effusion will help you indeed which states that rate of effusion is directly proportional to pressure/square root of molecular mass.
      And well that's a comparative law! You can use to compare two different effusions or diffusions!
      Hope this helps :)

  • @winnervinny396
    @winnervinny396 Před 6 lety +1

    Very interesting

  • @blueblood-_-
    @blueblood-_- Před 2 lety

    The lecture was amazing but it would have been even better if you discussed mole fraction relation .

  • @mokshsurya1681
    @mokshsurya1681 Před 2 lety

    Keep it up sir 🙏

  • @oseremeeromosele8578
    @oseremeeromosele8578 Před 7 lety +7

    Where is the 22.4 L/lol derived from?

    • @ChemSurvival
      @ChemSurvival  Před 7 lety +12

      PV = nRT
      When:
      P = 1 atm
      n = 1 mol
      T = 273 K
      R = 0.082 L*atm/(mol*K)
      V must be equal to 22.4 L

    • @MrAntsunator
      @MrAntsunator Před 6 lety

      ChemSurvival But the problem says that it's room temperature (25°C = 298,15K).

    • @tarveshmaheshwari
      @tarveshmaheshwari Před 5 lety +1

      @@MrAntsunator Hi, *Note that In PV=nRT, both side the unit of temperature is in Kelvin, so it doesn't matter weather the temperature is in Kelvin of Celsius. If 25°C = 298.15K then R must be in Celsius also...* I hope you understand that...

  • @b3bravebybrain167
    @b3bravebybrain167 Před 3 lety +1

    Thanks sir

  • @rudrasaiprasad
    @rudrasaiprasad Před 4 lety

    Where did you got the value of k

    • @khushichogle1266
      @khushichogle1266 Před 4 lety

      Rudra sai prasad it’s a constant....you have specific value for each gas

  • @furtherpoint
    @furtherpoint Před 3 lety +2

    Very helpful thanks for this video 💖 from INDIA

  • @abdelrahman_alrawi
    @abdelrahman_alrawi Před 3 lety

    thanks a lot

  • @06howea1
    @06howea1 Před 3 lety

    This may help us solve risigg sea temps and sea acidification

  • @bscc181
    @bscc181 Před 3 lety

    Thank u sir

  • @leosev
    @leosev Před rokem

    Thanks for the video! But isnt it true that CO2 doesnt obey Henrys law???

    • @ChemSurvival
      @ChemSurvival  Před rokem +1

      You're correct. The CO2/water system is a particularly non-ideally behaving system when it comes to Henry's law and maybe wasn't the best choice for an example. This is largely because of the complex equilibria among dissolved carbon dioxide, carbonic acid bicarbonate and carbonate ions that results when CO2 is dissolved in water. In hindsight a different gas or a different solvent might have been a smarter choice. Nonetheless, the fundamentals of Henry's law are well covered I think.

  • @shripratapsinhjihindividha5556

    Love from India 🖤🖤🖤
    From a jee aspriant 🖤🖤🖤

  • @brettruss3359
    @brettruss3359 Před 5 lety +1

    killed it

  • @pradeepkumarp6870
    @pradeepkumarp6870 Před 4 lety +1

    I have good idea to increase solubility of gas in water without increase pressure...

    • @vevo5086
      @vevo5086 Před 4 lety

      what is this idea.i wanna get a wider understanding of this topic.
      another point can we be whats friends.

    • @pradeepkumarp6870
      @pradeepkumarp6870 Před 4 lety

      @@vevo5086 surface of water and area of gas is too high... so it is required more pressure for solubility... So we divide it to very small particle... Its up to 300 - 500nm tube for water... 2000-2500 milli litter for gas... We can achieve this... Definitely we increase solubility of gas...

  • @jasjeetsingh9458
    @jasjeetsingh9458 Před 3 lety +3

    Henery's law is P=kS and not what stated in the the video.

  • @Munda0.94
    @Munda0.94 Před 2 lety

    Thanku sir😍 I'm from India🖤

    • @ChemSurvival
      @ChemSurvival  Před 2 lety +1

      You are very welcome!!!!

    • @Munda0.94
      @Munda0.94 Před 2 lety

      @@ChemSurvival thanku 🖤 so much sir again

  • @suheshraj2677
    @suheshraj2677 Před 2 měsíci

    Badiya hai mere pass😊

  • @jaysingh-pj2oq
    @jaysingh-pj2oq Před 3 lety

    Hey

  • @quartzzz165
    @quartzzz165 Před 3 lety

    hi sheldon

  • @piyushlohani5
    @piyushlohani5 Před 3 lety +1

    Easy to understanding love from India I am a jee aspirents

  • @Silver_Eagel_95
    @Silver_Eagel_95 Před 3 lety +1

    Hello

  • @theexamgyani6371
    @theexamgyani6371 Před 4 lety

    Rajkiran Sir Rocks

  • @crazzetrain
    @crazzetrain Před 4 lety +2

    could you give us the weather report while you're there?

    • @ChemSurvival
      @ChemSurvival  Před 4 lety +3

      Partly cloudy with a 100% chance of the partial pressure of a gas being proportional to the concentration of that gas dissolved in the solution below it...... duh

    • @crazzetrain
      @crazzetrain Před 4 lety

      ChemSurvival 😂😂

    • @shripratapsinhjihindividha5556
      @shripratapsinhjihindividha5556 Před 4 lety

      @@ChemSurvival 😂😂👍👍👍

  • @amanmo862
    @amanmo862 Před 3 lety

    Just proved soda gets flat over time once opened

  • @DubMastersNetwork
    @DubMastersNetwork Před 6 lety +1

    there is a problem in this answer

  • @nraishanzr3333
    @nraishanzr3333 Před 4 lety +2

    he looks like a freakin meteorologist on TV loll

    • @ChemSurvival
      @ChemSurvival  Před 4 lety +4

      Today's prediction... 100% chance of you subscribing to my channel B-)

  • @brandonpetrovich2023
    @brandonpetrovich2023 Před 4 lety

    Soda.

  • @enrihoward6077
    @enrihoward6077 Před rokem

    Never trust anyone that does scientific notation for .12.

  • @Wolfeywolf16
    @Wolfeywolf16 Před 6 lety +6

    That dramatic music at the beginning....really???

    • @ChemSurvival
      @ChemSurvival  Před 6 lety +5

      Just having a little fun with Movie Studio.... Don't be hatin' :-)

    • @Wolfeywolf16
      @Wolfeywolf16 Před 6 lety +1

      ChemSurvival uhhh...im not

    • @ChemSurvival
      @ChemSurvival  Před 6 lety +2

      good to hear (and I hope you liked the rest of the video more than the intro). Plenty more videos on my channel that I hope you will check out, also.

    • @Aguafrescas
      @Aguafrescas Před 4 lety

      Yes it was necessary