Velikost videa: 1280 X 720853 X 480640 X 360
Zobrazit ovladače přehrávání
Automatické přehrávání
Přehrát
To Get Certification, Click Here:
The final answer should be -2/3
Mam if mod z greater than 1/2. Then we consider only z=1,z=4. No need to take z=1/2
at
Isnt it -2/3 ?????
thank u girl i dont even know, very helpful
great explanation
Mam, u forgot to write - sign at the end.
for mod z>1/2 why shuld i consider 1/2 ? only 1, and 4 enough
calculate the inverse z transform of the following X(Z) = z( z²- 4z+5)/(z-3)(z-2)(z-1) ROCs:2<|z|<3,|z|>3,|z|<1 mam plz solve this one mam plzzzz mam
How to calculate n value if there are not given in question??
What if pole is in the form.of (z+1) ? Should we follow the same procedure?
Excellent madam👌👌
Mam if there is a pole of order greater than 1 than how to compute such ques(s)?
If n* value is not given ? What will we do ?
I'm sure the explanation is good but I hardly understand her accent
To Get Certification, Click Here:
The final answer should be -2/3
Mam if mod z greater than 1/2. Then we consider only z=1,z=4. No need to take z=1/2
at
Isnt it -2/3 ?????
thank u girl i dont even know, very helpful
great explanation
Mam, u forgot to write - sign at the end.
for mod z>1/2 why shuld i consider 1/2 ? only 1, and 4 enough
calculate the inverse z transform of the following X(Z) = z( z²- 4z+5)/(z-3)(z-2)(z-1) ROCs:2<|z|<3,|z|>3,|z|<1 mam plz solve this one mam plzzzz mam
How to calculate n value if there are not given in question??
What if pole is in the form.of (z+1) ? Should we follow the same procedure?
Excellent madam👌👌
Mam if there is a pole of order greater than 1 than how to compute such ques(s)?
If n* value is not given ? What will we do ?
I'm sure the explanation is good but I hardly understand her accent