Physics - Mechanics: The Inclined Plane (2 of 2) With Friction
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- čas přidán 28. 08. 2024
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This lecture series will cover Newton's Second Law of Physics: F=ma.
In this video, I will demonstrate how this applies to an incline that has friction.
Problem Text:
A 50kg mass is placed on an incline that makes an angle of 30 degrees with respect to the horizontal. The coefficient of friction between the mass and incline is 0.2. Find its acceleration.
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the whole semester i didn't learn anything in the class but from your 7 min video i learned everything you are the best teacher i have ever seen, the way you teach i swear thats what teaching is called.
He explains this so much better than my teacher, who just made it very complicated and difficult. SMH
Thanks Prof. Biezen!
If only my teacher explained the problem like you do 35 yrs back. It could change my life altogather. Thank you.
I'm abt to cry bc of how happy I am now that I finally understand
I'll take this explanation over Khan Academy's any day.
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Also shoutout to math bff too!
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This man condensed 2 hours of lecture and text book nonsense into a 7 minute video that's easy to digest and understand. Thank you
lizbeth diaz
No incline means that mg sin(theta) = 0 and thus there is no acceleration
Thanks this really helped
True but this is an inclined plane problem.
I don't know if you'll read this, but you have genuinely saved my life
Glad we were able to help. All the best.
Helped my last minute due assignment, dropped a like
Glad this was helpful
I've been teaching two years and have only just discovered this CZcamsr. Very, very good videos -- excellent modelling of how to solve a physics problem.
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10 years later still helping people, what an absolute legend. My physics final is in 24 hours. Thank you so much.
Thank you and all the best on your final!
Mines in an hour and a half 😅
Haha, mines in 2 hours.
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In the end I was crying manly tears - of joy.
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when youtube channels deserves your tuition fee more than the school does :(
the joe leonard of physics. Just needs to get ripped and tell people to get off their phones. Love all these lessons!
Thank you. (working on the "get ripped" part). 🙂
I have spent hours watching your lectures to help me pass my physics midterm, thank you so much.
TYSM! You are ways better than our teacher who can't even explain the basics !!
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thank you, in 5 minutes you have done what my teacher haven´t explain properly in one year.
this video is the reason i am going to pass my physics test today! THANKYOU!!!
teaching skills are top class
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+Pat DeCesare any time
Calm down, Phil.
Im not sure how much to thanks you sir, i wish my teacher was 1/2 of you. My teacher was not even half of doing his work in the teaching. Im sorry for my english.
Thankss$ssss
Excellent explanation without a single missed step. Thank you for making this so much easier to understand!
You make Physics easy!!! Thanks bro.
I have a midterm tomorrow and I just now finally understand this! Thank you!
Love from INDIA🇮🇳
I understood the concept very well....
Thank you and welcome to the channel!
THANK A TONS, Sir Michel!! I understood everything. Please, continue to provide such a quality lecture !
This made so much more sense than my teacher, one question though, why is the perpendicular component of gravity cos and the parallel sin? What angle are you using to determine that?
We are using the angle between the verical (mg) and the perpendicular component to the incline of mg (mg cos (theta)) which is the same angle as the incline.
oh okay, thank you so much
Omg!!! Thank you so much!!! In my university, it has shut down due to Covid 19 and I was struggling with this!!! New subscriber!
Hang in there. We'll make it through.
Had a problem with to case on each other., on tth incline. Used this video and got the answer. Thank you very much.
Glad it helped! 🙂
This dude is absolutely awesome.
Thanks!
From #India.... thank u for explaining clearly.. I subscribed
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Hi professor Van Biezen, Today I don't have a physics question. But I wanted to thank you for all your videos and your explanation. I was studying physics for my MCAT examen of medicine. And for the part physics my results were 8/10. That is a very high score. And this result is thanks to your videos! So thanks a lot. And now I can do medicine and become a doctor because I passed my exam :) :)
That is great news. Congratulations! Keep up the great effort.
I don't know how to be thankful from your work to be honest with you, If you ever come to Ottawa, Canada, I will take you for a special dinner :)
Your thank you was sufficient and appreciated. Welcome to the channel!
Thank you very much for reminding me that the friction force is Normal force by coefficient cos I needed this to submit for assignment and its due today
Wow this video cleared up so much of what confused me last year. Super helpful!!!
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what a wonderful Teacher you are... you are amazing. you really have saved many people from failure. may GOD bless you. I am so happy for knowing such a wonderful teacher like you.
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Love from India sir ❤ Your teaching helped me a lot
Thank you. Welcome to the channel!
Despite the fact that you mention at moment 4:00 about the magnitude of the tangent force and the friction force and even "show it" by visually measuring the length of the vectors, the friction vector length's is NOT, graphically, shorter than the tangent vector's length.
tf u talking bout dawg dont confuse me more i have a hard test tmrw
You just made my life easier, thank you
You're God sent sir! Very much appreciated.
Glad to help 🙂
Thank you, Michel, for sharing your knowledge. You are making my Physics 201 much more clearer! Thank you!
your videos are............life changing
Thank you for your comment. We are glad they are helping.
the best teaching
Thank you. We appreciate the comment.
Amazing! Helping me prepare for my midterm.
Thank you so much!!!! I had no idea what I was doing because my prof didn’t show us how to get to those formulas.
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I'll subscribe because I understood two of your videos
Thanks for subscribing.
Best teaching
Love from india
Thank you and welcome to the channel!
anyone else's sound only come out of one headphone?
We didn't have stereo on the older videos. That is now fixed for the new ones.
ok still a fantastic video really helpful thanks!
AHAHAHHA OOMG I thought there was smthing wrong with my headphones and started hitting the table with them to work until I lost hope lmaooo xD I feel dumb
yeah man me to aahhaha
lol, I only had one head phone on
Thanks so much for this video! Helped a ton! there is also an app on the Google Play Store and I believe the App Store as well that does these problems for you which has helped me a ton. Its call "phizX Calculator". Physics in spelled phizX.
Just wanted to let you guys know, it could probably help you out!
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Audio in the ear I'm deaf in! Lovely
Yes, the older videos were recorded in mono sound only.
my teacher just skipped over half of this so it made no sense, thank you so much
This Professor is awesome! God bless you! and Thank You Sir!
This is brilliant
Thank you for making such a clear and easy to understand video! This helped me so much :)
Dear Michel - Isn't friction an eccentric force? Therefore shouldn't there also be a couple acting about the blocks COM? Your example is assuming that the friction force is going through the COM , so are you making the assumption that the block can be considered a particle with point mass?
Happy new Year , Sir and Many thanks for your videos.
Alberto from Tuscany!
Happy New Year to you as well. Tuscany is a beautiful part of the world. Welcome to the channel.
One thing that always puzzles me is why is the angle theta between the slope and the surface (30deg in the above video) the same between mg and mgcostheta. Geometry wasn't my forte!! Thanks.
Notice that the direction of mg is perpendicular to the flat part of the wedge and the component mg cos(theta) is perpendicular to the slanted portion of the wedge. Therefore the angle between the flat and slanted portion of the wedge must be the same as the angle between mg and mg cos(theta).
Thank you.
Thank you,sir,it clearly explains my problem
Great! Glad you found our videos. 🙂
U explain fabulously
God, thank you so much! I missed the day we learned this in class so this is very much appreciated.
Life Saver! Thank you so much!!
Simply Excellent explanation
wow just amazing.
i like the way you work out so neat and tidy
Excellent explanation! The video series really clarified my understanding.
can u please tell me what if the the block was not released from rest, but instead travelling up the slope
Then the block would slow down and eventually stop. At that point the block would be at rest and the problem would be exactly the same as shown in the video.
@@MichelvanBiezen that i understand but what about, if the question tells us to get the driving force
Significant figures might have to be the most pointless rule in the world
Hahahaha
In real life, like in a laboratory, they're extremely important.
@baldy hardnut haha, not really. When I got to the unie one of first things I have
learned were significant figures. Its important to know what you can and cant live without.
8 years ago salute sir🙏🙏
Yes, we have been working on these videos for 9 years now.
Wow, very easy way to do this math 😍
Thanks!
GREAT TEACHER 10/10
I love this explanation. Thank you so much
Glad it was helpful!
Thank you. clear and concise
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Make your separate video in Playlist including all chapters of Physics with each other starting from beginning chapter(Part in India) to end chapter (Part in India) As in 90s Decade Syllabus in Science College,B.N. College,St.Xavier's College and Gossner College in India.
That would be a HUGE task. We placed the videos in the order as found in most college text books used in the US
@@MichelvanBiezen Why not in India when during my birth In Akhand Bihar as mentioned in the above Colleges.
Thank you for this beautiful lesson 😊
You're welcome 😊 Glad you liked it.
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This man is doing God's work
Thank you! 😃
Thanks sir u cleared my concept...to much extent..respect frm india
Welcome to the channel!
Sir you are a genius
I'm brazilian and I don't even speak english well but it helped me a lot.
Great! and welcome to the channel!
This video helped me so much! Thank you!
GOAT status. Thank you sir
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oooooh yea I finally get it yessss
I have a test tomorrow on kinematics
Good luck on your test
Sir: Thank you for drilling in both theory and applying it in practice with your wonderful and very well thought out example. I say to myself at what angle will the box stop sliding? Well from one view when both Mg (sin theta) and Mg (cos theta)(mew) equalize. Perhaps taking the limit of theta as it approaches another value less than 30 degrees might reveal an answer. Please provide a nudge on how to go about doing this.
As you described it, when the net force goes to zero, the acceleration goes to zero and if the object starts at rest, it will not move when the two forces you described are balanced.
I am an 8th grader and I have a question for Prof. Biezen. What is the problem if we solve this by taking a vector with a magnitude of 50X9.8 Newtons and a direction of 240 degrees. Calculate the two component 490cos240 and 490sin240 and go from there... I tried it and it gave me the exact same answer as you got. Plz comment.
There are many different ways in which a problem like this can be solved. Ultimately use the method you are most comfortable with.
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If the coefficient of friction is greater than 1 or so that it will result in a negative number. (Ally on Ally dry and clean is 1.4)
Does that mean that the friction is so high, the object won't slide?
Thank you for your amazing way of teaching ❤
A coefficient of friction greater than 1 means that a force greater than the object's weight would be needed to move the object across the flat surface.
@@MichelvanBiezen Thank you
I learned with your Good+Friendly attitude. I got answer of this my Question.
Thanks you for teach us ! :)
You're videos are great ☺️, you explain it so well, thank you ^^
wow wish i watched this a month earlier