Math Olympiad Algebra Problem || 4^X=48 || Find X

Math Olympiad Algebra Problem || 4^X=48 || Find X
Welcome to our channel! In this video, we will be tackling a challenging Math Olympiad question involving exponential and algebraic equations. We will walk through the problem step by step, providing clear explanations and helpful tips to help you solve similar problems in the future. Whether you're preparing for a competition or just looking to improve your math skills, this video is perfect for you. Let's dive in and solve some equations together!
#mathematics
#olympiadmaths
#algebra
#matholympiad
#matholympiadproblem
#exponentialproblem

[@user-ee7nw2rx9s]

Зачем все это?
Если с=а^х, то х=log (a) c.
Одно действие, максимум 30 секунд на решение.

[@CAustin582]

At first I thought you were going to do a solution that doesn't involve logarithms, but then you used log at the end anyway. In that case, you can just calculate log48/log4

[@bachnguyen-te3su]

thanks admin , I hope you will produce more videos

[@MathSync]

Absolutely, your overwhelming support and affection inspire me to commit wholeheartedly. I am deeply touched by the love I receive from viewers like you. My heartfelt thanks for your uplifting encouragement.☺️

[@pgbrandon]

I don't see any errors in the process that was used, but the process itself is a lot more complex than it needs to be. x=log48/log4 gets you your answer much quicker.

[@drisslahlou2726]

X=log48/log4