Motion under gravity Tricks jee Neet | Short Tricks motion under gravity Class 11th Physics JEE Neet
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- čas přidán 7. 09. 2024
- Motion under gravity short tricks
motion under gravity jee Neet
motion under gravity class 11th by Abhishek sahu
Short Tricks for motion under gravity
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The problem is that my competitors are also watching this video 🥵
Hm
Anna onnu kuninjirikkuvo😂
Sir Maine yahi se pada tha or mera half- yearly exam me 38.5/40 aaya Thank you❤ Really best teacher on youtube.
Sir ji....kya gajab trick bataye ho. Ese hi trick btate rahe to ek bhi student fail nahi hoga.
I salute you sir ji.
I'm 68 years old
One of the best teacher
He helped me a lot to tackle problem on motion under gravity 😊
Kuch ni karna kuch ni karna kehkar sir apne sb kara diya 😂 ekdum fantastic💫👌
Sir , there are no words literally for this amazing lecture literally for each n every conditions u just gave a trick to solve a question literally within 5 seconds. Literalllly ((within 5 seconds )) .. great damn salute and thanku very muchh ❤️❤️❤️❤️
I can imagine how easily this type of physics questions be solve . Literally it's very helpful for me thanks sir keep it continue 🙏🥰❤️
Kya ye trick sabhi questions per legegi. Please reply me.
@@allcollection8079 khud s apply krke dekhna hota h bhai
Sir you teaching so amazing 🔥 sir mai etna mast tricks friend k pass shear nahi kar sakta❤️
This is very very useful trick thanks for it very very much. It made us easy to solve the questions related to this concepts. And also please share. Tricks for vector🙏 and Motion in plane.
.
In the first qs the fourth answer will be -50 m/s it is a vector quantity and - sign denotes it direction which is towards downwards
Thank you bhaiya this video is very helpful for 11th class student + Neet student
Sir thank u very much plz do more videos 😍
What a super trick. thank you sir.
Best teacher for me on CZcams... Thank from bottom of my heart 💖
Sir make more and more videos!!
❤️Love with your energy 💓
Thank u so much sir 🔥🙏🙏 Because of your tricks muzame physics ke related phobia kam hua🔥 🙏🙏 💜💜
# best tricks 🔥🔥🔥🔥💯
A stone is dropped from the top of a tall tower and after 1 second another stone is dropped from a balcony 20m below the top.if both the stones reach the ground at the same instant,calculate the height of tower.
Sir ye ques me aapki banayi hui trick kaam nhi kr rhi hai.
A boy standing at the top of a tower of 20m height drop a ston. Assuming g=10ms^-2 , the velocity with which it hits the ground is..
Agar itni amezing tricks video me ho to video chahe kitni bhi lambi ho....it is worth it, so long video me bhi hame koi problem nahi hai, great tricks sir.
can this trick work in all types of que related to motion under gravity
Very Helpful Video sir ,i hv been stucked on this TOPIC from soo long and now i just grabbed it in 25 mins ..ur tricks are soo easy to learn ..but maybe not for all (it depends) but i liked this explanation
Thanku so much:^)
This was really Helpful ✧
sir this vdeo is very very helpful thank u very much sir😀😀😀
Thank sir
Aapse physics pdke physics bhutt easy lgti h
Thank you sir this video please next topic acceleration par ik video bana do
Best teacher and best lecture on CZcams💯👊
Really fantastic trick sir.heartly thank you sir❤❤❤❤.
Amazing tricks
You are my favourite teacher than PW ❤️
Literally watching in 2024🫢
Thanks sir This TRICK is very useful for ME.
😉
Any Exceptions for this tricks????
Plzz mention them sir!
when g=9.8 m/s2
Waahhhhh sir maza aa gya 10 sec ,ai question bn ja rheeee❤❤❤❤❤❤😊😊😊
Very very very amazing trick sir.Thanks for the trick and plz made the tricks for us like this in future
Free falling object from H heigh
Object's time to reach ground t= √2h/g :2h/g in root
Object's velocity to reach ground v= √2gh(root 2gh)
Velocity me - hoga bro
Thank God !! I found this video I was literally messed up😭 I couldn't solve motion under gravity problem but Sir you are my saviour 🙏🏻💗
sir pls make video on how get air 1 in 2 sec as well
Bro in neet 1 question 1 mini for solve ...so apply short trick....you never understand it.😊
Last 3 question is really solved by shot trick but it is also drive by equation of motion
Rekha please tell me is this tricks helpful for neet exam??
Yes it is helpful but I think so for neet you know what is concept bhind this question so I prefer to u that first solve this problem by equation of motion and then by trick like if u caerly see this video then replace 10 by g u got a finite formula to solve this problem where g is acceleration due to gravity
@@rekhabhasin9494 ok Rekha
Hey can u tell me how did we get 5 t square??
Amazing......
Plzz upload more
Its really helpfull👌👍
sir please provide the content in sequence .. please and your way of teaching is awesome.
sir please make one vid. covering previous year questions from this topic... 🙏❤️ please sir🙏🙏
Yes sir pls make this vedio
you are best teacher
Boom my eyes were drowning into excitement
Sir short vort kuch nhi hota concept hota h sabse solid... exam tk kitni tricks yad krenege 😂
Bhaiya sirf trick k bhrose q ho ??? Aap hoge intelligent.... Jinhe Sare concept yaad ho jate honge ... Hume to jo topic yaad nhi hote ya fir jo concept smjha nhi aate unhi ki trick rat te hein 😅😅😅
This is just used for confirmation
❤ tricks only for school level not for compitative level and trick may failed❤
For me as a competition level even the mingest trick of physics is also blessing.
Tum ye likhne ke liye vedio pee click ker hoo kyaa 😅
The trick you tell us.....that's amazing nd very helpful for JEE and NEET. I will save this video for future tricks and tips. And thank you sir for providing us the tricks🥰🥰
Aap aur subscriber deserve karte ho video bht accha tha👍👌
Thank you so much sir for amazing tricks 😲😍😍
Thanks sir please keep posting such videos for all concepts in physics for 11 and 12
Sir when 2 balls are dropped after time interval of 1 second distance of separation between them is 20 m the answer according to your formula is different and on internet it is different please clear
Thank you sir for this amazing lecture. Keep sharing such amazing tricks with us it will be very helpful to everyone preparing for NEET (UG).Thank you once again sir.
Are these actually useful?
Yes it is.
Wow! sir
Sach me bohot achhi trick bataai h aapne 😊😊😊
U r best 👍💯 sat sat naman aapko guru ji 🙏🙏🙇🏻♀🙇🏻♀🙇🏻♀🙇🏻♀🙆🏻
Such an amazing video
I really like it and it is very useful thnku
Sir aap bahut achha padhate hain
Very nice sir
Dill khush hogya sir tricks dekh k ❤❤❤❤abb apply krke dekhugi 😁
best tricks video . thanks a lot sir
Sir super se bhi upper wali trick bhut bhut dil se thank you ❤️❤️❤️❤️❤️
For second problem wt u have done is not a shortcut itself....just use this equation 5t²-ut-s=0 ...
So 5t²-20t-25=0 ...In the next step u get t=5... shortcut credits : bigchill physics 💚🦋✨
From upward to downward S = 4×5 - 1/2 × 10 × 16 = 60 m .so it is proved upward to downward hatting point 60 m way and sir find downward to upward 20 m way . given distance is 120 m and sum of solve point is 60 + 20 = 80
Niche aate time formula hota hain s = ut + 1/2gt²,
Naki s= ut - 1/2gt²
Sir how to solve this problem please explain me
A body is thrown vertically upwards with an initial velocity u reaches a maximum height in 6s . the ratio of the distance travelled by the body in the first second to the seventh second
There is one thing sn=an+ something
Sn = u+a/2(2n-1)
Bro 11:1 is answer
First step find initial velocity and putting this velocity in the formula=u-1/2×a(2n-1)
This video is very useful sir..... thank you so much....🙏
Your teaching is so good that i can't express to!your hard work will always give you the best results!N one request that please upload chemistry videos of class 11th
Thank u so much sir. Love u ❤️🥺
Thanks sir 🙏
Nice video
Thanks 👍 sir
thankyou sir for this type of amazing lecture
sir plz give us more and more tricks....💜
Sir last question mai aapnai S negative q liya hai means( -s=0-5t²)mai -S q liya
Can you please explain me?
Sir your teaching style is awesome 😎
Infact sir mujhe bas aaphi ki physics itni achhi tarah samajh aati hai
Thank you very much sir ...
Sir galileo odd no. Vala samajh nahi aya.... Eg water droplets are dropping with a time interval of 1 sec... Find the position of 1st and 2nd drop .... Sir isme height ka ratio 5:20 ------- 1:4 aya... How???
yesss 5m or 20 m aa raha hai
last walli trick to bhohat aachi thi
Thank you Soo much sir plz keep posting such physics videos. It helps us a lot
Thankuuu so much sirr😊😇😊😇
Thank you so much sir for this amazing content we really need it.....❣️❣️❣️
Please say More and more tricks to solve the problems in one second
What a awesome trick sir ❤
Amazing tricks...it is very helpful 🙌
Hi
Kha se ho ap
Lovely your short tricks.TRICKS MASTER of physics.
It is not trick it is a formal which he was using
@@rekhabhasin9494 not only he now we😂
Also using
Thanks for teaching 🙏🙏🙏
9:12 max height reached from ground should be 45m? sir
20+25
sir please upload more video on motion under gravity
Thank u 😊 so much sir .
Bestttt video in the worldd
Awsm sir mzaaa aagya phli baar motion under gravity me😊😊✌🏻😍
Adorable 🎇
Thanku so much sir
Maja aagya sir
Sir or aise hi vedio bnaie hme question ko kaise solve krna hota hai uska idea milta hai...thnks for this vedio..
2024 attendance 👍👍
The best teacher in CZcams I saw🎉
this video is quite amazing and intresting.....every method is fantastic😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍👍👍👍👍👍😍😍😍😍🤗🤗🤗👌👌👌
Hats off giiiiii😎😎😎 impressed....
Goated video sir , deserves a lot of respect
Vooohoooo bht hard sirr mje ye derivation ettu se bhi nhi arhe thy lkn ab concept chmk gya🔥🌟🌟
just awesome !!!!!!!!!!1
Sir agar initial velocity ki 2/5 kitni height par hogi nikalni h to kya karenge
Waah brother kya trik bataya hai apkaa lakh lakh shukarita🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Thank you for such wonderful tricks
Thank you so much sir for such amazing concept ❤
Thanxxx sir.....❤️
Thoda dhire hota to aur jyada achha hota...best video sir✌️
I like Sir's diolog (kuch nahi karna hae🤣🤣😄👍 ) love u 2000 time sir