Bloch's Theorem in Crystals

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  • čas přidán 28. 05. 2019
  • / edmundsj
    If you want to see more of these videos, or would like to say thanks for this one, the best way you can do that is by becoming a patron - see the link above :). And a huge thank you to all my existing patrons - you make these videos possible.
    In this video I sketch out a basic proof of Bloch's theorem in crystals and also talk about where it breaks down and why we might want to use it.
    This is part of my graduate series on optoelectronics / photonics, and is based primarily on Coldren's book on Lasers as well as graduate-level coursework I have taken in the EECS department at UC Berkeley.
    Hope you found this video helpful, please post in the comments below anything I can do to improve future videos, or suggestions you have for future videos.

Komentáře • 88

  • @Cunboss
    @Cunboss Před 4 lety +107

    "Space is curved anyway, so deal with it"
    That got real for a second lol.

  • @dheerajkumar2534
    @dheerajkumar2534 Před 4 lety +35

    Best explanation of bloch's theorem in YT

  • @_The_Alchemist_
    @_The_Alchemist_ Před 2 lety +8

    Clear and lucid explanation. Finally understood the Bloch Theorem after so much struggle.

  • @husseinh.thebyani508
    @husseinh.thebyani508 Před 4 lety +13

    It's an amazing explanation, Thanks a lot from Saudi Arabia

  • @zarintasnim2634
    @zarintasnim2634 Před 3 lety +2

    You explain things quite visually. It's so helpful to understand.. thank you!!

  • @taraschutora9166
    @taraschutora9166 Před 4 lety +5

    The best explanation so far in internet!!!

  • @PetitCorpsSalade
    @PetitCorpsSalade Před 3 lety +4

    Studying for my physical chemistry class, this is actually great! Thanks!!!!

  • @jaugretler9140
    @jaugretler9140 Před 3 lety +19

    I have a qm exam tmrw and only learned about this now. Wish me luck

    • @dwarapureddijagadeesh5374
      @dwarapureddijagadeesh5374 Před 2 lety

      Goooooooood luck
      You're a lucky person to get wishes from me

    • @dddhhj8709
      @dddhhj8709 Před 2 lety

      lmao you learned this is a solid state video 🤣.science is science

    • @Shudarsanpoudel
      @Shudarsanpoudel Před 4 měsíci

      What was your exam bro? I'm asking after 3 years

    • @jaugretler9140
      @jaugretler9140 Před 4 měsíci

      @@Shudarsanpoudel the subject was called: quantum physics

  • @behnammohammadi504
    @behnammohammadi504 Před měsícem

    Very clear explanation. Thank you very much for your time and effort. You helped me a lot and saved my time by this video

  • @oliviahoran4525
    @oliviahoran4525 Před 5 měsíci

    Wow, I was struggling so much to understand this bloch theorem but now sir you made me to love 🎉this bloch theorem, thank you so much for your efforts ❤❤❤

  • @saifamu1989
    @saifamu1989 Před 4 lety

    You have no idea how much favor you are doing for explaining these things...

  • @amandobhal4264
    @amandobhal4264 Před 4 lety +4

    Nicely explained.
    Thank you

  • @lawanyasingh4497
    @lawanyasingh4497 Před 4 lety

    best explanation of blochs theorem ..very informative

  • @romerofuentero
    @romerofuentero Před 2 lety +1

    Great video! cheers from Spain.

  • @m.sureshthanjavur9975
    @m.sureshthanjavur9975 Před 10 měsíci

    Smart and good explanation about Bloch theorem. I understand the theorem. Thanks a lot

  • @saicharanmarrivada5077
    @saicharanmarrivada5077 Před 3 lety +2

    Thank you sir for the wonderful explanation

  • @alicansaray2940
    @alicansaray2940 Před 3 lety +3

    Amazing video, thank you very much. Already subscribed by just watching one video.

  • @stringsam
    @stringsam Před 3 lety +1

    amazing explanation!!!

  • @fungi42021
    @fungi42021 Před 3 lety +1

    Great explanation 👍

  • @josemariacolingalvez2725

    Bro, thaks for the explanation, it was so cool

  • @dexterfang7516
    @dexterfang7516 Před 3 lety +1

    great video, thanks

  • @mausamgupta888
    @mausamgupta888 Před rokem +1

    Thank you so much sir 💞💞

  • @emankopeal4210
    @emankopeal4210 Před 2 lety +2

    Thank you for the amazing explanation (:

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 2 lety +2

      You are welcome! I shamelessly steal the best explanations I find from others, of course :)p

  • @Ayah_S_Taihi
    @Ayah_S_Taihi Před 3 lety

    So clear! Thanks :)

  • @navjotsinghdhiber3454
    @navjotsinghdhiber3454 Před 6 měsíci

    Thank you sir.

  • @kevinsweeney2809
    @kevinsweeney2809 Před 2 lety

    Thank you!

  • @brotherstech3901
    @brotherstech3901 Před 4 lety +1

    Enjoyed.

  • @tcl98387
    @tcl98387 Před 4 lety +7

    The new index at @10:44 should be (2*pi*s)/(N*a)

    • @chloe7808
      @chloe7808 Před 3 lety

      thanks, it got me confused !

  • @ghezzalimohamed2483
    @ghezzalimohamed2483 Před 7 měsíci

    you are the best

  • @sherinsaraphilip1869
    @sherinsaraphilip1869 Před rokem

    Thank you

  • @akashcallofdutymobile8888

    Thank you sir

  • @physicsdiva1871
    @physicsdiva1871 Před 2 lety +1

    Well explained

  •  Před 5 lety +16

    Hi Jordan,
    thank you for your videos, they are very good. Please, I have a question about this one. Just before you introduce u_k(x) function 10:30. There is a step where you rewrite PSI(x) function with index k in the exponent. Where did the "
    "a" go?

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 5 lety +16

      Whoops! k should be equal to 2*pi*s/(N*a), that’s a mistake on my part. k has units of inverse length.

    • @biswajeetpatro9990
      @biswajeetpatro9990 Před 5 lety +1

      Hey Jordan, can you share your mail id, can I contact you for any of my doubts?

    • @y3rzhan
      @y3rzhan Před 4 lety +1

      @@JordanEdmundsEECS was looking for the comment, thanks!

  • @md.rayidhasanmojumder5039

    At 9:28, where did Shi(x) go in the equation of Shi(x+a)? why did you wrote (x+a)/a over the exponential omitting the Shi(x)?

  • @delafrog
    @delafrog Před 3 lety +1

    Why should the wave function of a particle in a periodic potential be an eigenfunction of the translation operator? (As it was written in 2: 55) How does this derive from the equality of the values of the wave functions for "x "and" x+a"? It is not entirely clear why we should assume namely this relation- with the product, and not with the sum operation, for example?
    Other issue. Is it really necessary to make a periodic closure of the wave function on the lattice boundaries to prove Bloch's theorem?

  • @coursecczu152
    @coursecczu152 Před rokem +1

    at 9:22 why we add (x+a) to e ^i 2piS/N, where does it come from? could some one give me a hint?

  • @shanujwilson1204
    @shanujwilson1204 Před 4 lety +5

    A small question. Does this also explain if asked for super lattices? Like those infinite square wells?
    Thanks in advance. ♥

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 4 lety +2

      100% yes sir, you can use it any time you have periodicity.

  • @zacharythatcher7328
    @zacharythatcher7328 Před 3 lety +2

    So I understand this, and can see that crystal momentum is just spatial frequency. But I am having a lot of trouble seeing how photons come into the picture. I’m cool with Laue and Bragg, and I’ve seen that there is a classical way to prove that wave number is conserved at the interface with snell’s law. But why and how does all of that relate to band structure? Any good videos covering this?

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 3 lety +1

      Yeah so I have a video on "optical band structure" and a bunch of videos on optoelectronics/photonics (you might want to just see the introduction) I made studying for my prelim exam :)p. Photons come into the picture as they are the mediator that lets electrons go from states in the valence band to states in the conduction band (and vice-versa via emission).

  • @shivammishra6624
    @shivammishra6624 Před 3 lety +1

    Great

  • @jatinkashyap1491
    @jatinkashyap1491 Před 2 lety +1

    "Space is curved anyway, SO DEAL WITH THAT" some serious gangsta shades 😎! JK, love it.

  • @randydandy8196
    @randydandy8196 Před 3 lety

    So k is the crystal momentum and not the wave vector?

  • @maryfucci3131
    @maryfucci3131 Před rokem +1

    At 9:25, when you divide the (x+a) term by a, I don’t see why you only get and x/a left and not (x/a+1). Is it because (x+a) is equal to x? So you’re not actually diving out your just substituting x for the numerator x+a ?

  • @PresCalvinCoolidge
    @PresCalvinCoolidge Před rokem +1

    I'm confused because we still don't know u_k(x). It seems like we have not gained anything, we just traded not knowing psi(x) for u_k(x).

  • @beatthekraken7088
    @beatthekraken7088 Před 3 lety +1

    4.46 it is not clearly nonsense, it is the definiton of infinity in complex analysis, where the straight lines equal to circles. Why? Because 2 straights cut themselves in the same amount of points like circles. 1,2 or infinity (The breaking fact is that infitiy is always a point where they cut themselves) This is because e^ikx is non ambigious. Imagine a map on polar coordinates (stereographic projection from the north pole) then every radial path you take to infinity leads you to the north pole. It will help you if you draw the mapping of the square Rx[0,2pi) via exp(x+iy).

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 3 lety

      Yup, I'm familiar. It's a beautiful definition, and the world of pure math is a bizarre one indeed.

  • @atulbisht5774
    @atulbisht5774 Před 4 lety +1

    Helo sr nice explanation..I want to ask how u made such video....means device or software..plz reply

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  Před 4 lety +1

      iPad Pro/duet Pro on Windows 10 PC with Autodesk Sketchbook for drawing and OBS Studio for recording.

  • @TheIndolence
    @TheIndolence Před 11 měsíci

    What is happening when you say at around 9:05 "the e^(i2pi s/N) term has to be a function of x. Say, 'times x, and then we add an a to it". This seems completely arbitrary, and yet it's an essential step in the whole development to arrive at the final Bloch theorem. Why not a function of x in a way more complex way? Does it not work if it does not depend on x?

  • @mariamhasany5250
    @mariamhasany5250 Před 3 lety

    space is curved, is that referring to the Einstein's theory of general relativity?

  • @nomingirl
    @nomingirl Před 4 lety +3

    lot of thanks from mongolia ;)))

  • @caleb7799
    @caleb7799 Před rokem

    just gotta watch them uhms/ahs

  • @arunbrvce
    @arunbrvce Před 3 lety

    Very interesting explanation. I followed you very well up until the point where you established C^N=1 (i.e. C is the nth root of unity). Why do we need a fancy function to satisfy this condition? C=1 itself is a solution isn't it?

  • @FernandoMartinez-wf4jd
    @FernandoMartinez-wf4jd Před 2 lety +1

    Thank you for the headache 😂

  • @LL-mq7gj
    @LL-mq7gj Před 8 měsíci

    where did the a term go at 10:34?

    • @LL-mq7gj
      @LL-mq7gj Před 8 měsíci

      using your definition of k, i cannot reproduce your calculation of psi(x+a) at 11:30

    • @user-tz3hp6jo9d
      @user-tz3hp6jo9d Před 8 měsíci +1

      he tried to explain about a point in circle refer first 1min again

    • @LL-mq7gj
      @LL-mq7gj Před 8 měsíci

      @@user-tz3hp6jo9d thanks

  • @santalos5
    @santalos5 Před 3 lety

    I dont see the benefit of assuming its a circle? 04:00

  • @GBY13
    @GBY13 Před rokem

    The explanation from 9:00 is bit chaotic...

  • @miro.s
    @miro.s Před 3 lety

    If we use symmetry, wave function should be identical after shifting the position of some periods, not rotated in complex space. Wave function from principle of equivalence between atoms can not number them. From its perspective all of them are same, there is no other information. This is against what you are showing. You are describing circulant matrix where order matters.

    • @miro.s
      @miro.s Před 3 lety

      The same for electromagnetic potential functions, they are same after shifting some periods. The same in optics with periodic entangled coherent sources of light. These examples are totally against what you claim.

    • @miro.s
      @miro.s Před 3 lety

      You are showing not standing wave that is equivalent to the Mexican wave and present at all cycles, because atoms in that constellation can never reach synchronization all together.

    • @black1blade74
      @black1blade74 Před 2 lety +1

      Only the probability density is actually observable in this system so the phase can vary.

    • @pseudolullus
      @pseudolullus Před rokem

      @@black1blade74 Everything is fine unless there is some topological funny crap going on, of course :P

    • @pseudolullus
      @pseudolullus Před rokem

      @miros There is an extra degree of freedom in condensed matter physics which is both important and denied by your treatment. The phase indeed can vary and this is crucial for some effects.