Classical Mechanics | Lecture 6

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  • čas přidán 10. 09. 2024
  • (November 1, 2011) Leonard Susskind discusses the some of the basic laws and ideas of modern physics. In this lecture, he focuses on the motion of objects. He starts with a general example of a wedge on a frictionless plane and uses it as the building block for more complicated theory.
    This course is the beginning of a six course sequence that explores the theoretical foundations of modern physics. Topics in the series include classical mechanics, quantum mechanics, theories of relativity, electromagnetism, cosmology, and black holes.
    Stanford University
    www.stanford.edu/
    Stanford Continuing Studies
    http:/continuingstudies.stanford.edu/
    Stanford University Channel on CZcams:
    / stanford

Komentáře • 113

  • @joabrosenberg2961
    @joabrosenberg2961 Před 2 lety +14

    An example of a wedge; Second example of double pendulum 27:00; Hamiltonian and Harmonic Oscillator in Phase space 53:30; Hamilton Equations 1:13:30; Q&A 1:29:00

  • @glendeloid9210
    @glendeloid9210 Před 10 lety +65

    These are amazing lectures. Susskind's presentation is perfectly clear and perfectly paced, with the relaxed energy and humor of a big personality, but without the arrogance and implied intimidation that so often accompany it.

    • @markkennedy9767
      @markkennedy9767 Před 4 lety +10

      I completely agree. He's at the top of his profession and he makes you feel he's just figuring things out himself as he goes. Making the student want to think about it. A great quality in a teacher.

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

    • @lucasmcguire1554
      @lucasmcguire1554 Před 7 měsíci

      Perfectly put. He has confidence without arrogance, very good but somewhat rare combination

  • @halilibrahimcetin9448
    @halilibrahimcetin9448 Před 4 lety +5

    Thanks to Leonard Susskind , I feel more confident to learn more advanced topics.

  • @camilodominguez4678
    @camilodominguez4678 Před 4 lety +11

    " If you know the rules of Lagrangian Mechanics, it's a mechanical exercise, a completely mechanical exercise you can be dumb as hell and still solve the problem"- Leonard Susskind.

  • @ozzyfromspace
    @ozzyfromspace Před 6 lety +8

    These lectures get better and better every class!

  • @tobywhite1100
    @tobywhite1100 Před 11 lety +13

    This is fun, sort of. Susskind has a great sense of just how fast he can push without getting me totally confused and giving up. I feel like a greyhound chasing a mechanical rabbit. I never quite catch up, but I can get close enough to stay in the race if I keep running as fast as I can. (There's probably some Lagrangian to describe that kind of motion, but I don't even want to know it)

  • @TheMaximumGForce
    @TheMaximumGForce Před 12 lety +18

    Loving this series! cant wait to get to quantum mechanics!

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

  • @seandafny
    @seandafny Před 9 lety +46

    this man is in love with harmonic oscillators.

  • @roberthumphreys5594
    @roberthumphreys5594 Před 5 lety +6

    Check out his "Theoretical Minimum" series of books, available on Amazon and other booksellers! They're great, especially for people approaching the subject for the first time, or coming back having forgotten calculus!

  • @abhishekcherath2323
    @abhishekcherath2323 Před 7 lety +9

    I'm not getting the same expression for the kinetic energy for the double pendulum
    Nvm got it
    I'm amazed how well I'm understanding this. Prof is so good at explaining this stuff

  • @ArabyGUC
    @ArabyGUC Před 4 lety +4

    1:20:03 Here one has to smile with satisfaction at the simplicity and elegance of the derivation :)

  • @EdSmiley
    @EdSmiley Před 4 lety

    Anybody who doesn't have an intuitive feeling for how complexly odd the double pendulum's equations of motion laid out by Dr. Suskind are in practice should look at a CZcams video of a double pendulum. You'll be glad you did!

  • @habblebabble70
    @habblebabble70 Před 11 lety +4

    Canonical momentum is essentially a definition of momentum given by the LaGarange equation. It is, by definition, the partial of the LaGarange with respect to the time derivative of the space coordinate (most recognizable as velocity). I recommend wrestling with the LeGendre transformation when you get the chance. Since the LaGarange, in general, is not always in a conservative field, the units tend to change when the cononical momentum is taken.

  • @jessstuart7495
    @jessstuart7495 Před 6 lety +11

    I think there is a sign error at 38:00. The cos(alpha) term should have a (theta_dot + alpha_dot) factor, not (theta_dot - alpha_dot).

  • @seandafny
    @seandafny Před 9 lety +5

    Very nice and smooth. I hope the rest go like this. Hamiltonians seem so much less complicated then them lagrangians.

    • @seandafny
      @seandafny Před 9 lety +1

      Sean Dafny Though Lagrangians seem more useful.

    • @aeroscience9834
      @aeroscience9834 Před 7 lety +1

      Sean Dafny really? I find the lagrangian to be simpler

  • @hasanshirazi9535
    @hasanshirazi9535 Před 4 lety

    This is a best explanation of Lagrangian and Hamiltonian.

  • @jamesdowns72
    @jamesdowns72 Před 5 lety +1

    His explanation for how beautiful the Hamiltonian is is how you can see these phase portraits and gain an understanding of the cycles and non convergent behavior, etc... but I keep thinking to myself, "but you could take Newton's equations and just plot x vs xdot and see that too..." Also, I am slightly confused how he initially explains that it was vitally important in coming up with the Lagrangian that it must be T-U, not T+U, in order to obtain the equations of motion after applying the Euler Lagrange equation. Then Hamilton comes along and decided, "no, it's better to make it T+U" after all? Is his formulation kind of like an add-on or adjustment to the Lagrangian so that it can still give the equations of motion using the Euler Lagrange operations but also does not change with time? What does it mean, intuitively, that the action that the Lagrangian minimizes is T-U? Is it that as kinetic and potential energy trade back and forth through the course of a system in motion, that it is done so in such a way that their difference is kept as minimal as possible? Since there is no constraint on holding total energy constant with time in the Euler Lagrange, is this achieved just accidentally?

  • @karolispetruskevicius8178

    Hi all. Hope you have all enjoyed these lectures as much as I did. I was just wondering if anyone knows where I could find original lecture notes for this series? Much appreciated!!

    • @cubbtom
      @cubbtom Před 9 lety +5

      Karolis Petruskevicius www.lecture-notes.co.uk/susskind/

    • @seandafny
      @seandafny Před 9 lety +1

      Thomas Cubbins THANK YOU SO MUCH I LOVE THE WORLD ! U ARE AWESOME !

  • @thebestofthebest9494
    @thebestofthebest9494 Před 8 lety +5

    Bon appetit, Leonarodo!

    • @jubilaeumskagen
      @jubilaeumskagen Před 7 lety +5

      Scone energy transfers into Susskind energy. Use the lagrangian to calculate the laws of chewing noises.

  • @Sans_K5
    @Sans_K5 Před rokem

    thanks sir for these amazing lectures❤🙏

  • @brainstormingsharing1309
    @brainstormingsharing1309 Před 3 lety +1

    Absolutely well done and definitely keep it up!!! 👍👍👍👍👍

    • @joeboxter3635
      @joeboxter3635 Před 3 lety

      +mg was right and he changed it to -mg at the urging of the same student who tried to convince him derivative sin is -cos.
      If you have d/dt of momentum = -mg then you are saying the F (derivative of momentum) is acting on a falling object is not in the same direction as the acceleration. Both have to be in same direction and hence same sign.
      The F is down and mg is down. So the signs on both sides have to be same. If sign is reversed then resulting Force would be in opposite direction of the mass time acceleration: g.
      When you do L = T - V, V = mgy. As y increases V increases. L = T - mgy. He had this right.
      Then take partials bringing the contribution from d/dt (dT/dq-dot) = mg.
      Lastly, let's say he was right: F=-mg. Then this means F + mg = 0. But the gravitational force is suppose to be conservative. The plus on left breaks this. On other hand, F = mg, then F - mg = 0 is valid as we would expect for a conservative force. So it has to be F = mg.
      This man absolutely knows his physics. But he lets his students questions and comments fluster him into making mistakes. No wonder he admitted in lecture 3 that he makes algebraic mistakes. It's cause he is not in a quiet place to think but has to perform in the presence of confusion.

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this guy solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @leonig100
    @leonig100 Před 10 lety +1

    At 1.30 there was a discussion on dimensions. q initially is the definition of a coordinate system and in my view the dimensions of this must be position as one of the students said. How does the dimension demonstrated by th professor relate to this?. Is the coordinate system selected in a special way to make this true? Perhaps another way to put it is how does one express this in terms of the coordinates geometrically.

    • @toshiro0o
      @toshiro0o Před 9 lety

      To answer your final question: straight lines. The coordinates he chose were proportional to those of space but by a factor that has units of its own.

  • @Yan_Alkovic
    @Yan_Alkovic Před 3 lety +1

    His q at 1:36:00 actually has units of square root of action, surprisingly

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this guy solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @mrfrankincense
    @mrfrankincense Před 9 lety +2

    Is the first problem supposed to be that it is kept on the plane by a normal force?

    • @toshiro0o
      @toshiro0o Před 9 lety

      You can think about it as being kept on a horizontal frictionless surface if there is gravity, but the way he explained it was that it was in absence of gravity or any potential field, so if initially you give it motion that keeps both pendulums in the same plane that's how it will stay. He just didn't mention the initial conditions or he was just thinking of 2D space.

    • @orientaldagger6920
      @orientaldagger6920 Před 3 lety

      Yes if you do the balance of force thing, but not really relevant here.

  • @joeboxter3635
    @joeboxter3635 Před 3 lety

    +mg was right and he changed it to -mg at the urging of the same student who tried to convince him derivative sin is -cos.
    If you have d/dt of momentum = -mg then you are saying the F (derivative of momentum) is acting on a falling object is not in the same direction as the acceleration. Both have to be in same direction and hence same sign.
    The F is down and mg is down. So the signs on both sides have to be same. If sign is reversed then resulting Force would be in opposite direction of the mass time acceleration: g.

  • @chamberlainandrew2672
    @chamberlainandrew2672 Před 10 lety +1

    Is P_theta really conserved? I think the Lagrangian involves theta and P_theta is not a conserved quantity since V involves theta. Prof. Susskind just mistake T as T-V. Someone agree with me?

    • @ZraveX
      @ZraveX Před 10 lety +1

      He is discussing an example where there is no gravitational force. So V = 0, and P_theta is conserved. Otherwise, you'd be right, and he mentions that at 40:30

    • @chamberlainandrew2672
      @chamberlainandrew2672 Před 10 lety

      Woo, seems right. But I really can't remember what's it about since it's too long time ago.Anyway, thank you~

    • @sathyanarayanansubramaniam5125
      @sathyanarayanansubramaniam5125 Před 2 lety

      He has assumed V=0

  • @rfmo8385
    @rfmo8385 Před 9 lety +1

    do you have to use the rectangular (x,y) components of velocity when you write down the kinetic energy?

    • @toshiro0o
      @toshiro0o Před 9 lety +1

      No, those just happen to be the easiest components to figure out a lot of the time. For example, you can also use polar coordinates (for 2D space, as that is what he was using) where the kinetic energy can be written with the sum of the radial and angular velocities squared. As long as what you write for velocity is actually the length of the velocity vector.

    • @bautibunge737
      @bautibunge737 Před 5 lety

      you can use any coordinate, but for most of them it may be difficult to find out how is the expression of the kinetic energy. Most of the time you just write your coordinate system as a function of cartisian or polar and then work out the kinetic energy from there

  • @welovfree
    @welovfree Před 11 lety +1

    is there a textbook and exams to follow this lectures?

  • @willie5069
    @willie5069 Před 5 lety

    I am desperate to find out how he came up with the omega parameter at 1:03:40. I can not seen to get form the standard fornm wuth K and m. Any helpl would be greatly appreciated.

    • @y09t9b3
      @y09t9b3 Před 5 lety

      At 1:32:00 he explains how he derives omega from k and m via a change in coordinates.

    • @TheLevano22
      @TheLevano22 Před 3 lety

      There is a known formula for springs: T = 2pi * sqrt(m/k). f = 1/T, so we have to take both sides to the power of -1, which will result in: f = (1/2pi)* sqrt(k/m) or w = sqrt(k/m).

  • @matschreiner
    @matschreiner Před rokem

    1:29:30 - 'Quantum Mechanics would go to hell in a handbag if you tried to take some of these other cases' Haha,

  • @hemantjoshi8388
    @hemantjoshi8388 Před 8 lety +1

    why did he change coordinates from x to q?

    • @martingreen436
      @martingreen436 Před 6 lety

      He just uses different labels for the same thing depending on the context.

    • @y09t9b3
      @y09t9b3 Před 5 lety +1

      With that change in coordinates it is easier to visualize the orbits in phase space.

  • @user-fe5ml2hm4n
    @user-fe5ml2hm4n Před 7 lety +4

    at about the last 2 min, why people laugh at "why neutrino can't go faster than the speed of light" ? Is there a western cultural background that I don't know? ( I'm Asian )

    • @Afewwilliams
      @Afewwilliams Před 7 lety +4

      there was an experiment that came out around the time of these lectures where the experimenters thought they had observed neutrinos travelling faster than the speed of light. The discrepancy was subsequently explained.

    • @user-fe5ml2hm4n
      @user-fe5ml2hm4n Před 7 lety

      Oh thanks, I knew that experiment but didn't exactly know it was neutrino :3

  • @davidv2986
    @davidv2986 Před 3 lety

    Fantastic lecture! I don't understand why the change in p q dot at 1:17:10 can be re-expressed by p (delta q dot) + q dot (delta p); it seems to me that it should equal p (delta q dot) + the transformed q dot value (delta p) or alternatively q dot (delta p) + the transformed p value (delta q dot). I'm probably doing something wrong, any help would be greatly appreciated. :)

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this type solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @angst_
    @angst_ Před 3 lety

    When he works out the equations of motion, he's doing a "partial lagrangian"? Can anyone tell me what that's called so I can learn more about it? Thanks! I probably haven't taken the math needed for this course, but that hasn't stopped me yet. It's a very interesting topic.

    • @davidv2986
      @davidv2986 Před 3 lety +2

      He takes the partial derivative of the Lagrangian w.r.t. a given variable, be it q or q dot. It's where you differentiate a multi-variable function w.r.t just one of the variables and assume the other variables are kept constant.

    • @angst_
      @angst_ Před 3 lety +1

      @@davidv2986 Thank You

  • @savanadoll1003
    @savanadoll1003 Před 2 lety

    hey where can i get your lectures on electromagnetism...😁😁😄😄😄....

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this type solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @amirhosseinkzm9278
    @amirhosseinkzm9278 Před 2 lety

    Thank you very much.

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

  • @06KingDave
    @06KingDave Před 11 lety +1

    A great textbook to learn classical mechanics from is (imaginatively titled) "Classical Mechanics" by Herbert Goldstein which includes great explanations and problems. If you want I can send you p.d.f 's of the book itself and solutions to the problems.

  • @michaelgarcia812
    @michaelgarcia812 Před 2 lety

    It appears that the way he solved the inclined plane problem, by assuming the point mass remains on the inclined plane, in no way reflects reality if the inclined plane is accelerated in a direction away from the point mass. In reality, the inclined plane would leave the point mass since it is not exerting a force on the point mass. This could be addressed by utilizing Newton’s laws of motion. The problem is posed as a reversible problem by requiring the point mass to remain on the inclined plane, while in reality it is not. Caveat emptor.

  • @physicspoint3356
    @physicspoint3356 Před 2 lety

    May God bless you sir

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this type solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @welovfree
    @welovfree Před 11 lety +1

    pdfs would be great yes you can send them

  • @manoranjansahu7161
    @manoranjansahu7161 Před 4 lety

    Is anyone aware of the book on General Relativity by Prof. Suskind

    • @orientaldagger6920
      @orientaldagger6920 Před 3 lety

      Prof. Suskind? Who is that?

    • @meowwwww6350
      @meowwwww6350 Před 3 lety

      What?? Please tell me the name of the book please

    • @manoranjansahu7161
      @manoranjansahu7161 Před 3 lety

      @@meowwwww6350 Well on page no 392 of "Special Relativity and Classical Field Theory", Prof. Susskind mentioned this. "See you in General Realtivity"

    • @meowwwww6350
      @meowwwww6350 Před 3 lety +1

      @@manoranjansahu7161 oh!! But it'll be fun if he writes a theoretical minimum Series on general relativity!!

    • @manoranjansahu7161
      @manoranjansahu7161 Před 3 lety

      @@meowwwww6350 Let's hope it becomes reality

  • @cubedude76
    @cubedude76 Před 11 lety

    excuse my possible ignorance but what exactly is canonical momentum? From the way he is using that term it sounds like momentum in a particular direction (like a component of momentum). and why wouldn't it always have the same units?

    • @aeroscience9834
      @aeroscience9834 Před 7 lety +1

      cubedude76 canonical momentum is the partial derivative of the lagrangian with respect to the time derivative of a coordinate. Therefore, it's unit depends on the unit of the coordinate in question. See the earlier lectures in this series for more info on canonical momentum

  • @forheuristiclifeksh7836
    @forheuristiclifeksh7836 Před 10 měsíci

    6:00

  • @seandafny
    @seandafny Před 9 lety +3

    lhh dis nigga said Herman 😂😂

    • @tomaszdzieduszynski
      @tomaszdzieduszynski Před 8 lety +3

      +Sean Dafny It's a reference to the older version of those lectures from 2008, where the 2nd pendulum bob was actually called Herman. :D

    • @seandafny
      @seandafny Před 8 lety +1

      Tomasz Dzieduszynski hahaha. These lectures were entertIning for reasons I would otherwise not have guessed.

  • @achillesmichael5705
    @achillesmichael5705 Před 2 lety

    Cameraman was sleeping during this one

  • @orientaldagger6920
    @orientaldagger6920 Před 3 lety

    What a terrible choice of coordinates for the block on an incline plane.

    • @joeboxter3635
      @joeboxter3635 Před 3 lety

      I think +mg was right and he changed it to -mg at the urging of the same student who tried to convince him derivative sin is -cos.
      If you have d/dt of momentum = -mg then you are saying the F (derivative of momentum) is acting on a falling object is not in the same direction as the acceleration. Both have to be in same direction and hence same sign.
      The F is down and mg is down. So the signs on both side have to be same. If sign is reversed then F is opposite direction of the mass time acceleration: g.
      When you do L = T - V, V = mgy. As y increases V increases. L = T - mgy.
      Then take partials bringing the contribution from d/dt (dT/dq-dot) = mg.
      So left side is F and right side is mg.
      Another way to think of it is the gradient of mgy is already negative. And you have to put a negative in front to get it to equal the force. Thus the signs are positive on both sides of the equation.

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      Can it be denied that this guy solves the most difficult problems? czcams.com/video/pkw92_Jpv1E/video.html

  • @utku1903
    @utku1903 Před 7 lety +2

    Herman lol

  • @prakashchaudhary4559
    @prakashchaudhary4559 Před 12 lety +1

    NOT

  • @xinzeng-iq7zv
    @xinzeng-iq7zv Před 4 měsíci

    why is this guy stuck on algebra

  • @Chiavaccio
    @Chiavaccio Před 2 lety

    👍

    • @lelomambueliane4915
      @lelomambueliane4915 Před 2 lety

      the best video ever seen on classic mechanics czcams.com/video/pkw92_Jpv1E/video.html

  • @06KingDave
    @06KingDave Před 11 lety

    Hi, sorry it took me so long to reply youtube inbox is messed up... If you pm me your e-mail I'll send it as soon as i can. Cheers ; )

  • @doydark4ever
    @doydark4ever Před 11 lety +3

    this teacher always made algebraic mistake

  • @Prussiaaccount
    @Prussiaaccount Před 12 lety +2

    FIrst!

  • @jmath8988
    @jmath8988 Před 5 lety

    The eating is loud lol.