(0 1) is uncountable|(0,1) is uncountable proof|countable uncountable sets|uncountable set proof

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  • čas přidán 28. 04. 2020
  • Subscribe Channel Rahul Mapari.
    In this video we discussed (0 1) is uncountable, (0 1) cardinality r. also we have some uncountable sets examples. what is exactly uncountable sets. we also claim that set of real numbers is uncountable proof. so that we can solve csir net real analysis questions on the base of countable uncountable sets. countable uncountable sets examples are very important in csir net mathematical sciences. so we prove in detail 0 1 uncountable proof.
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Komentáře • 86

  • @prof.lalitkumarpachori8508

    माझ्या वडिलांचे जगणे माझे आहे, परंतु माझे वडील चांगले आहेत. आपण आम्हाला शिक्षित करण्यासाठी जी मेहनत आणि प्रयत्न केले त्याबद्दल आम्ही नेहमीच आभारी आहोत मी तुमच्यासारखा गुरु मिळालो याबद्दल मी भाग्यवान होतो. प्रिय शिक्षक, मला नेहमीच पाठिंबा दिल्याबद्दल आणि माझे मार्गदर्शन केल्याबद्दल धन्यवाद. जर मला तुमचा आशीर्वाद नेहमी मिळाला असता तर मी यशस्वी झालो असतो. 😍

  • @inovexa4039
    @inovexa4039 Před 3 lety +2

    This is excellent sir!! Much love from Sri Lanka. The best explanation I've seen so far...

  • @floatingmoose
    @floatingmoose Před rokem +2

    Thank you for making this video. It made the arguments clear and easy to understand!

  • @generalhcross
    @generalhcross Před 8 měsíci +1

    This is the first explanation that I was able to understand. Thank you!!

  • @jadekan72
    @jadekan72 Před 2 lety +1

    Great! I didn't understand the way my teacher in the school doing this proof. But here I got hjelp! Thanks so much!

  • @gavinhyde2849
    @gavinhyde2849 Před 2 lety +2

    Great video. Straight to the point and easy to understand.

  • @aniketpal9629
    @aniketpal9629 Před 3 lety +2

    Darunnnn sirrr. Khub sundarrrr bojhalen sir .

  • @devadathan6620
    @devadathan6620 Před 3 lety +2

    easy to understand. Very useful .❤️👍

  • @mathematicsmind8648
    @mathematicsmind8648 Před 4 lety +2

    It's simply awesome.. 🙏

  • @reactionboy4437
    @reactionboy4437 Před 4 lety +2

    Sir,I learned many things from this lecture

  • @benedictkongyir1899
    @benedictkongyir1899 Před 2 lety +1

    May God bless you for your work

  • @michaelbachmann457
    @michaelbachmann457 Před 3 lety +1

    very lovely explained thank you :)

  • @prof.lalitkumarpachori8508

    The Cantor set is an example of an uncountable set of Lebesgue measure 0 which is not of strong measure zero. Borel's conjecture states that every strong measure zero set is countable. ... A set A ⊆ R has strong measure zero if and only if A + M ≠ R for every meagre set M ⊆ R.

  • @D_i_n_e_s_562
    @D_i_n_e_s_562 Před 4 lety +2

    Thanq sir...

  • @Kalpanadubey11
    @Kalpanadubey11 Před 3 lety +1

    Sir apke pdane ka trika bhut accha hai please keep it

  • @saskiarymkiewicz260
    @saskiarymkiewicz260 Před 3 lety +1

    thank you, this really helped me

  • @diejodomison4249
    @diejodomison4249 Před 8 měsíci

    Amazing video sir

  • @priyanqajha4838
    @priyanqajha4838 Před 2 lety +1

    Finally crystal clear

  • @pradhumansinghchouhan9237

    great video

  • @sahayam80
    @sahayam80 Před 4 lety +1

    good explanation. thank you

  • @ethangrubelich1305
    @ethangrubelich1305 Před 2 lety +1

    KING. THANK YOU.

  • @dollykashyap4665
    @dollykashyap4665 Před rokem +1

    thnks sir u re the best 🥰

  • @aakritibhuriya1484
    @aakritibhuriya1484 Před 10 měsíci +1

    thank you sir !

  • @poojaingole416
    @poojaingole416 Před 4 lety +2

    Thank you sir...

  • @indugupta6081
    @indugupta6081 Před 3 lety +1

    Thanks Sir

  • @sridharreddy4162
    @sridharreddy4162 Před 2 lety

    Well explanation sir

  • @monoramamandal4941
    @monoramamandal4941 Před 3 lety +1

    Thank you so much ..

  • @Chysrh
    @Chysrh Před 2 lety

    Nyc expl.

  • @danielzhu4487
    @danielzhu4487 Před 2 lety

    Preciate it

  • @exol4229
    @exol4229 Před 2 lety

    Thankyou!

  • @sushmithabts229
    @sushmithabts229 Před 2 lety

    Thank you so much sir

  • @radhikasavalam6696
    @radhikasavalam6696 Před 4 lety +1

    Thank you Sir

  • @kousei8411
    @kousei8411 Před rokem

    Simple and easy explanatiion

  • @mansafabrar6872
    @mansafabrar6872 Před 3 lety +2

    Best proof for R to be uncountable. 👍

  • @gandhamprasanthi7035
    @gandhamprasanthi7035 Před 4 lety +1

    Thank u sir

  • @ananddanodiya2324
    @ananddanodiya2324 Před 4 lety +1

    Thank sir

  • @ABKARIMSIR
    @ABKARIMSIR Před 4 lety +1

    Thanks you sir 😇

  • @subhopal1760
    @subhopal1760 Před 4 lety +2

    Thnk sir....plzz sir upload vedios for csir net...

  • @akhileshkumarojha9301
    @akhileshkumarojha9301 Před 2 lety

    Thank you so much sir 🙏🙏

  • @devanshpandya3818
    @devanshpandya3818 Před rokem +1

    Natural lite is good concept
    Yaa Ur explanation is also

  • @ranjithkumar-vl8mq
    @ranjithkumar-vl8mq Před 4 lety +1

    Thank u sir..to teaching in english...

  • @osmaniavenky4874
    @osmaniavenky4874 Před 4 lety

    Super sir

  • @vlog_vihar
    @vlog_vihar Před 2 lety

    Sir good explanation but Hindi me bolte to or achha samajh ata.
    Thankyou sir

  • @saisameer5842
    @saisameer5842 Před 3 lety +1

    👌👌👌❤

  • @cut143
    @cut143 Před 4 lety +2

    Sir Topology questions and answers video daliye please

  • @Dream16780
    @Dream16780 Před 3 lety +1

    Bahut hard

    • @Dream16780
      @Dream16780 Před 3 lety +1

      And sir..you are really a good teacher..thanks for your lecture.

  • @s.p6482
    @s.p6482 Před 4 lety

    💖 from West Bengal

  • @baisarinku2340
    @baisarinku2340 Před 4 lety +1

    Sir aap unacadamy app pr class kyu nhi le rhe.....??

  • @lakshakumarlariya6821
    @lakshakumarlariya6821 Před 27 dny

    ❤❤❤❤❤❤

  • @bilalmusharraf9321
    @bilalmusharraf9321 Před 3 lety

    Sir plz make a complete series of important topics for IIT jam

  • @AjaySingh-bk6lk
    @AjaySingh-bk6lk Před 4 lety

    Sir isko cator set ki help se prove kr saktay h kiya

  • @lucienchu9649
    @lucienchu9649 Před 8 měsíci

    Sorry sir, I am pretty confused, say a11 = 7, then b1 = 8. Isn't that we can always find a number in the list such that it starts with 0.8 then bla bla bla which will ultimately match the number B?

  • @boxman_ninja0819
    @boxman_ninja0819 Před 2 lety

    Why can we not apply this proof to the set of rational numbers?

  • @mathsclub1903
    @mathsclub1903 Před 4 lety

    what is the condition of b1 not equal to a11

  • @soniyasharma3406
    @soniyasharma3406 Před 3 lety

    I'm so happy that i got it. I'm so bad with proofs. Any suggestions to improve it???

  • @MathematicalMinds
    @MathematicalMinds Před rokem

    Sir
    Please define uncountable union & countable union of sets

  • @zahidrasoolkhan2277
    @zahidrasoolkhan2277 Před 4 lety +1

    Love from kashmir

  • @kaushalkumar-oz3eh
    @kaushalkumar-oz3eh Před 4 lety +3

    Sir please upload some lecture Riemann integral 🙏🙏🙏

  • @soniyasharma3406
    @soniyasharma3406 Před 3 lety +1

    Very beautifully explained, sir.
    I got it but
    I've a question, we have let that B, what if this assumption is wrong?????
    What if there doesn't exist such B.
    Maths is mysterious!!

    • @greatisnothing
      @greatisnothing Před 3 lety +4

      There exist such B, just as we define it. It's Because we can proof that there is one element such as B exist that is not listed, it proves that its uncountable.

    • @soniyasharma3406
      @soniyasharma3406 Před 3 lety +1

      @@greatisnothing , yes. Got your point.

  • @ganeshmapari1576
    @ganeshmapari1576 Před 4 lety +2

    Like Classic girukul,like that, thanks

  • @sarojghosh7916
    @sarojghosh7916 Před 4 lety +2

    Any connected metric space with atleast two elements must be uncountable .

  • @alizach.3708
    @alizach.3708 Před rokem +1

    Sir agr ic ki jaga (0,5) is uncountable prove karna hoto same aise hi hoga??

  • @ieltscuecard467
    @ieltscuecard467 Před 2 lety

    Why nonmeasurable set is uncountable????

  • @nileshgangurde4893
    @nileshgangurde4893 Před 2 lety

    aii not equal to bi
    Aise assumption krna hi q he
    Agar aise assumption nhi krenge to countable ho jayega na

  • @aniketpal9629
    @aniketpal9629 Před 3 lety

    I am now reading in 6th sem b.sc . And i was unable to understand the proof of this thm. untill watching the proof u provided it sir

  • @user-im9hk7qv7n
    @user-im9hk7qv7n Před 2 lety

    Please help me in the theorem
    (0,1) is countable

  • @amandeep9930
    @amandeep9930 Před 4 lety +1

    A countable set has measure zero. Since measure of (0,1) is 1,it must be uncountable.

    • @RahulMapariBasicMaths
      @RahulMapariBasicMaths  Před 4 lety +1

      Very good. But we have some examples that a set is Uncountable but measure is zero.

    • @amandeep9930
      @amandeep9930 Před 4 lety +1

      @@RahulMapariBasicMaths Yes Sir, the most well known example is Cantor Set.
      Sir, I watch your videos regularly. Thank You for helping us.

    • @mansafabrar6872
      @mansafabrar6872 Před 3 lety

      Could u please explain measure zero concept?

  • @jeffjo8732
    @jeffjo8732 Před 10 měsíci +1

    1) The interval [0,1] is indeed uncountable. (Note that you did not exclude 0.0000... or 0.11111... from the set you used, so the set is [0,1], not (0,1).)
    2) Cantor's Diagonal Argument proves it.
    3) This video is not a correct demonstration of CDA, and does not prove it. It is close, but incomplete. In fact, most expositions of CDA fail this way.
    It fails because you can't just say "we assume this list is complete" and then, when you show it is missing a number, claim a proof by contradiction. You have to actually use the assumed fact in the proof that leads to the missing number. All you really assumed is a list of some real numbers in that interval.
    What is shown in the video, is that if you have a list of any subset of [0,1], then that subset does not include the number B. This is the first part of CDA (actually, it is about strings, not numbers, but it does work with numbers). Only once this *_lemma_* is proven, directly and not by contradiction, does Cantor assume that the full set can be listed. Then we get the contradiction that B is in the listed set (since it includes all) but also not in the set (by the lemma). In other words, the contradiction is about B, not the interval.

  • @barasharanidas7265
    @barasharanidas7265 Před 4 lety +1

    Thank you sir....