Avogadro's Number, The Mole, Grams, Atoms, Molar Mass Calculations - Introduction
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- čas přidán 21. 08. 2016
- This general chemistry video tutorial focuses on avogadro's number and how it's used to convert moles to atoms. This video also shows you how to calculate the molar mass of a compound and how to convert from grams to moles. This video contains plenty of examples, notes, and practice problems that you help you complete your next worksheet assignment.
Full-Length Math & Science Videos:
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Introduction to Moles:
• Introduction to Moles
How To Calculate The Molar Mass:
• How To Calculate The M...
How To Convert Grams to Moles:
• How To Convert Grams T...
How To Convert Moles to Grams:
• How To Convert Moles t...
Moles to Atoms Conversion:
• Moles To Atoms Convers...
Grams to Molecules Conversion:
• Grams to Molecules and...
_________________________________
Grams to Atoms:
• How To Convert Grams t...
Moles, Atoms, & Grams Conversions:
• How To Convert Between...
How To Balance Chemical Equations:
• How To Balance Chemica...
Stoichiometry - Basic Introduction:
• Stoichiometry Basic In...
Avogadro's Number:
• Avogadro's Number, The...
_________________________________
Limiting Reactant Problems:
• Limiting Reactant Prac...
Excess Reactant Problems:
• How To Find The Amount...
Theoretical & Percent Yield:
• How To Calculate Theor...
Percent Yield - More Examples:
• How To Calculate The P...
Percent Error:
• Percent Error Made Easy!
_________________________________
Percent Composition By Mass:
• Percent Composition By...
Empirical Formula Problems:
• Empirical Formula & Mo...
Empirical Formula - Hydrated Compounds:
• How To Find The Empiri...
Combustion Analysis:
• Introduction to Combus...
Stoichiometry Practice Test:
• How To Solve Stoichiom...
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At about minute 8:00 it has to be 2.4x10^24, not 2.4x10^23.Nevertheless, keep on the good work. :)
Thanks for letting me know.
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@@yume6742 heyy can you help? in the 1st conversion he's saying to convert moles to atoms...so atomic no. or atomic mass? idgi T.T
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In around the 8th minute, the formula unit should be 2.4x10^24 and the no. of Cl ions should be 7.2 x 10^24 as you add one unit of exponent when you move a decimal point to the left
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no it's 7.2 x 10^25
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Wow, that exponent switch from 23 to 24 was a really good point. Thank you.
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9:57
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8:00 why ? It should be equal 2.4 ×10^24 cause we added a 10 to 24 × 10^23
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i got a question. at around 14:55, he didnt finish calculating, why did he skip the actual calculation, and went straight to converting moles to atoms?
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In the beginning of the video you said that the value of the mole is *6.02x 10^23 but it should be 6.022x 10^23!!. as mentioned in our book .
Even I searched in the web and got the answer as 6.022x10^23*.
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This really helped! I could not get it in class the reason why the 10^# was changing from 23 to 24. Now i get it! test tomorrow!
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For those who are confused
6.02x10²³ = 602hexillion
So it's a unit of measure.
Half a dozen apple = 6 apples
A dozen apples = 12 apples
A mole of apples = 602hexillion apples or 602,000,000,000,000,000,000,000 apples.
My brain is hurting even more
@@liutjinsiu9689 same
That didnt help a bit lol🤣.
We are confused still 😕
@@asadasadasadsalem7690 it’s basically just a unit of measurement! It’s confusing because it’s such a massive unit of measurement, but if you just think of it as 6.02E23 it becomes a lot easier! If you try and just see it as a simple unit of measurement that has a large sum it will probably become a lot easier to understand :) hope this helps anyone in the future in the comment stream, let me know if you want me to explain more!
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im so glad I found your video for the life of me I couldn't find out why 10^23 changed to 10^24.thanks alot
The explanation of Avogadro's number and molar mass is the best that I have seen. Great job. There is an error at about 8 minutes. Should be 10^24 not 10^23. This is minor issue - just pointing it out for others in case they notice it.
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I've learnt that m = n x M and n = m/M are formels that you can use when you want the mole mass, mass or the amount of substance.
For example: Calculate the amount of substance for 750g propan.
Propan= C3 H8
12x3 + 1,01x8 = 44,08
750/44,08 = 17,01 g/mol
Also I understood the video very well!
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I still to this day imagine the mole as a little furry burrowing mammal...
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