Transformations of Graphs (stretches) : ExamSolutions
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- čas přidán 9. 09. 2010
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Despite being here 10 years late, this video helped me so much! Great explanation! Thank you so much for taking the time to create this video :)
You're welcome, Ryan.
*Edit 11 years :)
Saved my life a decade later. Thank you!! 👏👏
Still going.
This is in the 2020 updated syllabus, right?
@@aryanb737 Yep - I was using this to revise before an assessment. 👌
@@fh17522 so, how was the exam? Were you able to solve the transformation problem?
@@aryanb737 I'd done loads of revision for paper 1 but the teacher then decided we should do paper 2. :))) it was all good though. This video is definitely good to have in your corner. 👌
The minus would cause a reflection after the stretch. So -af(x) is a stretch of scale factor a parallel to the y-axis followed by a reflection in the x-axis. Also f(-ax) is a stretch scale factor 1/a parallel to the x-axis followed by a reflection in the y-axis.
i am an international student and i always get confused in math class because of the language problems. but i can catch up now after watched some of your videos! thank you so much!!!!
still over 10 years u are still helping people (including me now)! thank u for the help !!
13 years now bruh........ he uploaded video just 10 days ago... what a consistency
THANK YOU SO MUCH, I WAS SO PUZZLED BEFORE BUT THIS VIDEO TAUGHT ME SO MUCH!
Your welcome
+ExamSolutions You're*
Hello people
Thanks alot we need more people like you
I'd never properly grasped this topic, but this video was just what I needed. Thanks!
Even after doing extra coaching, I had difficulties understanding this and this video literally cleared all my doubts. Thx a lot.
thank you so much. Most videos explain 6 rules but they dont explain the enlargement rules, this video did exactly that.
Thanks! I was really struggling with stretches specifically and you seemed to save me!
Thanks mate appreciate it , really clear tutorial
EPIC LIFE SAVER!!!!! THANK YOU!! THIS IS LIKE A LAMP OF GUIDANCE TO ME!!! You gained another subscriber!
Amazing! I've been struggling for ages with this. Thank you so much!
You're my savior! I don't understand a thing in class and now I'm understand it crystal clear that I can even teach my friends!
Thank you!
You teach them. Good luck.
You explained it in a simple and clear manner. Helped me understand it, thank you!
Thank you so much I was so confused before I saw this. Thanks for the help!
I am so old after 12year I am watching this video And still its helpful
Thank you for the explanation, this was very clear and concise. It helped me understand something my book skipped over.
oh my god thank you so much you've literally saved my life i know i'm 12 years late but i love you so much man
great! first time someone explained it well!
Thanks very much! Cleared all my confusions about stretching graphs :)
Good to hear that is is sorted for you. Best wishes
i did not know it was this easy thank u so much!!!!!
Awesome bro, perfectionist!
@ExamSolutions once again, thanks a lot. stretching parallel to the x-axis is so confusing!
Nice explanation. I really didn't understand this in my maths class, but this has made me understand it much better.
Thank u bro. I have a test tomorrow. That really helped me.
Very helpful- Thank you.
Thankyou so much, this is very helpful
@twelveheroes y=x/2 for the oblique asymptote and x=0 stays the same if I am reading your question correctly.
This video is also very helpful. Thank you.
These videos are great thank you so much!! I was wondering what would happen is the value of a was negative?
Thank you so much helped a lot!
thank you sooooo much
Thank you so much sir.
It's really helpful for me ☺️☺️☺️☺️.
@twelveheroes This will get twisted. so y=2x say streched parallel to the y-axis by a stretch of 4 units becomes y=8x
@ExamSolutions thanks so much! :)
you sir are a wonderful teacher!!
Thank you, you are too kind.
I have my gcse today, thank u so much
thank you!
Thanks
@TooPizza1994 No probs - thanks for your support.
Thankyou, a really clear and detailed explanation. 👍
Thank you.
Cheers mate.
Really really helpful. This is recommended it really helps
Ty soooo muchhhhh
Glad to help.
I watch your videos all the time, your just so helpful and I really appreciate your work.. Your helping my revision - 2 months to revise for ALL of A-Level maths, gotta work hard for our dreams eh! On a side note tho, is there any shortcut to answering the REALLY hard questions? In maths generally? I guess its understanding whats going on..
Hi, I am pleased to hear that the videos are proving useful to you. Is there any short cuts. Not really, it is just hard work on your part. Do tons of questions from past papers and try other boards if you exhaust your board. You will then learn to apply methods as you have rehearsed them so many times. Good luck.
ExamSolutions Wow, It's an honour for you to reply to me, honestly I've been going all night finishing of C1, and I wouldn't understand alot of these concepts if it hadn't been for your wonderful videos, respect
Thankyouu!
When y=af(x), shouldn't the stretch be along the x-axis instead of being parallel to the y-axis and vice-versa with y=f(ax)?
what if I want to strech x axis variably.....as a function of x??
U use the same term stretch for both the cases when there is a compression i.e in case y= f(2x) its not a stretch its compression.
amazing! thank you
I'm pleased to hear it helped.
Could you be asked to prove why it translates/reflects/stretches in the exam?
THANK YOUUUUUUUU
Thank you for watching.
This was the only part in the book I was stuck in and you explained it very well and have made me understand it a lot more! Thanks ever so much! (Got my GCSE in a couple of weeks so thanks for your help)!
what would happen to the asymptotes of a graph if it's stretched?
Good luck
@ExamSolutions even for the oblique asymptote?
Cool
sorry for bothering, but if i have a graph of f(1/2x), what would my oblique asymptote x=y and vertical asymptote x=0 become?
Thankk uu sooo much
No problem. You are welcome.
I really didn’t get it, and this was literally the ONLY video which I actually understood.
@ExamSolutions Sorry not strictly correct. Nothing if you have a vertical asymptote and you strech parallel to the y-axis and nothing if you have a horizontal asymptote and stretch parallel to the x-axis. However, if you have a vertical asymptote say at x=3 and you stretch by a scale factor of 2 parallel to the x-axis then this will now be at x=6. Similarly if you have a horizontal asymptote say y=2 and stretch by a scale factor of 2 parallel to the y- axis then it will now be at y=4
Can we say y=af(x) as is like pulling the graph from above and y=f(x/a) pulling graph from the right.
I suppose in a kind of way but in an exam you should be encouraged to use the words stretch, scale factor and invariant line.
Thankyouu ❤❤ love from Pakistan 🇵🇰
I think you just solved a big math issue of mine
That's good. Thanks for watching.
if the graph is let say y=(3x+4)^2 , what would happen to the translation?
Thanks
Its a translation of x^2 by 4/3 to the left
I dont get how the first graph is parallel to the y axis and vice versa
@twelveheroes nothing
1:30
Watching today one day before paper😂
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WP WAGNER ANYONE??
watch speed =1.5. You are welcome
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