Amount of Substance | Multiple Choice Question Walkthrough 1 | A level Chemistry
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- čas přidán 11. 09. 2024
- Amount of Substance.
Multiple Choice Question Walkthrough.
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Amount of Substance Topic Playlist:
• Amount of Substance | ...
00:14 Empirical Formula - using % by Mass
01:38 Concentration & unit Conversions
02:37 % Atom Economy
03:37 Concentration Calculation & Electrophilic Addition
05:13 Ideal Gas Equation
07:06 Concentration Calculation
08:05 Titration Method
09:35 Gas Volumes
11:12 Gas Ratios and Moles
13:10 Percentage Yield
Watching this right before exams 😭This is so helpful! Thanks!!
That's great to know thank you 😊
And the best of luck to you!
life saver
Thanks! Happy to save you!
Please could you tell me how is one supposed to know that buta-1,3-diene reacts with an alkene to make an addition reaction? As I haven’t come across it in the specification or lesson
I'm not totally clear what you're asking due to an autocorrect issue (I think).
When you study the Alkenes topic, you will learn that one of the main reactions alkenes undergo is addition reactions (specifically electrophilic addition). In general, this is where one (usually) small molecule, e.g. a halogen, adds onto the alkene in the position where the double bond was. The double bond becomes a single bond. If there are 2 double bonds, this addition is likely to happen twice
@@chemistrytutor ohh I haven't even studied that yet😅😅I might have to pre-read it thankyou
@excellenceeminue1835 good news! I'm sure it'll make sense when you do!
Why don't A and B dilute the base? Technically it sounds like they do
They would dilute it, but they won't change the moles present.
Bigger volume but less concentrated = same moles
Is this AS
Yes, AS 👍I've got lots of other AS videos if needed
In question 9, how do you know that there are 200cm3 of oxygen gas at the start?
The question tells us that the butane is reacting with 0.2dm3 of oxygen, which is 200cm3
@@chemistrytutor I'm sorry I mean for question 6 not 9
do u do specific tutoring?
I do sometimes, yes. If you're interested you can email me on thechemistrytutor123@gmail.com
for question 5 how did u get the 2 to 3 ratio
It's taken straight from the equation. The numbers in front of the formula for each chemical. They're called the coefficients or multipliers
oh ok thanks. will they give equations like this but we must constuct and balance them?@@chemistrytutor
@karthithiru sometimes, but more often you're given the full equation. If you're not given it, the ratio is likely to be 1:1. You maybe wouldn't be expected to write the fill equation but work out the ratio they react in
I'm sorry but I think question 2 is wrong because you only worked out the moles and didn't work out the concentration, yet that is wat the question was asking for. I love your videos tho
Dont worry, it is correct 🙂 I never worked out conc = mol/volume, but in my third step I worked out the concentration in g/dm3 and then I divided it by Mr to get mol/dm3
But you're right. An alternative method could have been to work out moles and then divide by 0.1dm3
Oh yeah, my bad
Thank you, I was a bit confused but I get it now 😊